Final Exams and Video Playlists: www.video-tutor.net/ Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections
he knows a thing about everything and not everything about a thing, he uploads good videos generally but he doesn't go into the deep details and that's completely normal
@Al_hamdoulilah_0 it is helpfull but not enough if you are an electrical engineering major that is You still need to learn how to find Rth when there are dependent sources.
I bombed my first electrical exam. The next two I watched all your videos and did the practice problems, came out with an 84 and then a 93 on the final exam. I'm in your debt again, thank you!
It was from when he did Nortons theorem he use the same problem so that’s where he got the six from He must’ve me the videos back to back I forgot to add the six this time
hey keep it up, I don't know if you have a stable job or not but please don't stop making these videos. You're helping people especially those in the third world country. Thank you so much keep it up. Hope you get more subscribers. God bless! Thank you so much I'm very grateful. - ECE student 2nd year school year 2019-2020, I'm from a third world country
You explained the theorem so well...I was afraid to try to learn this but now I'm able to solve most problems with ease!!!!! Thanks man! It means a lot! 😀😀😀
Great video! I was wondering where the RL resistance = 6 came from. At 6:48 he says he'd written it down before, but all I saw was just plain "RL" without it = 6. Am I missing something?
The only way I could think of to get 6 is to just straight up add the 3 resistances and divide by 3, but for some reason I highly doubt that's correct.
How are you so good at teaching. Most people ask how are you so smart, but many people can learn the stuff you know, while very few (if any) can then teach it as well, and not just one subject, all of them.
@@danielmoreno9935 first equivalent resistance making the short circuits and open circuits then apply KCL or KVL to find the voltage or current (in case it's Norton's) with the sources on and create the circuit in serie (thevenin) with the two given information
Hey, i've just watched a bunch of videos to the thevenins theorem a cause to my assesment next tuesday. I wanted to thank you a lot because your video helped me a lot .!
Nice demonstration. At 4.30 you said the sum of currents is equal to 1, but should said zero, however you did write down the correct value. At 6.24 you wrote 34.4 Ω instead of 34.4 V.
He should be given a Nobel prize or something. If not for all the engineers he got through university and others he helped then for the shear amount of positive comments he gets.
Let's take Load resistor as 6 ohm...take different value, will be given in the question, don't consider it in Thevenin's resistance, it is the step of solving Thevenin's theorem...
sth i never understood in my 1st year of college so well explained in a 10 mins video, not sure if its actually worth all the time and money to go thru college
for everyone who is confused abt the 6ohm resistance it is the load resistance which was given in the question as RL = 6 ohm.. he just forgot to write it in the problem in the start... so yeah we didn't calculate it.. it was given
why the hell my professor teach this for 2 hours and I didn't understanding a thing and this video is almost just 10 mins. and now I understand this theorem.
At 5:49 you multiply 50V by 5 and then you add it to the 60A. Is this actually correct? I ask because You didn't keep the units while performing these calculations.
How can we cosider the load resister as "open circuit" to calcuate Vth(Voltage-thevenin)? For the calculation, you assumed that there is no current flowing over the register (9 Ohm). Does it really make sense? I need your advice on this!
there's no current flowing over the 9 ohm resistor because there's an infinite resistance across point A and B due to the presence of air in between the two points ( since air acts as an insulator) so current is negligible, almost zero.
To find the Thevenin Voltage, we have to assume the load resistor to be an open circuit because that's the variable that we want to measure. i.e. The current across the load. The will be no current flowing through the 9 ohm resistor since there is an open circuit across the path A to B and so all of the current will be flowing through the 5 ohm resistor. There will be no path along an open circuit
I'm still a little confused on why 6ohms for the load resistance? Also when u said the voltage at B was zero why isn't the voltage at A also 0? Because I thought they both were open circuits thus 0V right?
the 6 ohm was actually given but he forgot to mention it. and V at b was 0 because it was being compared to the ground. the potential voltage difference at ground is always 0, therefore Vb is 0 with respect to ground while A is not, because with the given position where A is, there is definitely some potential difference between A and ground. hope this help
Please consider doing a serie about linear programming simplex and lemke method.. I'd be forever grateful. Or direct me towards some videos worth watching if possible thank you
I don't get Thevenin's Theorem. I only understand that you do it to make the circuit simpler. First you get the Total Resistance : Rth, then hook it up onto the Loader Resistor. Why do we have to use the voltage at Vc? Wouldn't that mean the resistor behind it (R1=4ohm) won't be included? You are using Total Resistance but using a voltage that is past that resistance already. Hopefully someone answers please. Thank you
Where did the 6 Ohm Load resistance come from? It came out of nowhere and was not mentioned in the video until the last part. It just came out of nowhere. Was it given in the problem or calculated?
@@bryyd1922 the value of RL can literally be anything. Thevenin Equivalent looks at what voltage that resistor sees in front of it and the current across it. The voltage drop, in this case is 12, will change with any RL values since the VL=RL*iL and we calculated iL using the thevenin equvalent of the circuit. For example, if you plug in 1 ohm as RL, you will get these values: iL = 2.8197 A VA = iL * RL = 2.8197A * 1Ohm = 2.8197 V VC = 2.8197V + 2.8197A * 9Ohm = 28.197 V Current across 5 Ohm = 28.197V / 5ohm = 5.6394 A = i5
Final Exams and Video Playlists: www.video-tutor.net/
Final Exams and Video Playlists: www.video-tutor.net/
Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections
Hey! wher did the six come from after calculating thevenin's voltage
@@vincenciaondigo3584that could be any value according to the question given.... It's not something that was calculated
once I see this channel's name in search results, I know I'm safe.
I can so relate 😌
same over here huhuhuhu
Same here
Yes😄😄
Amen to that
how, and why, does this guy know so much stuff?? Like... chemistry? calculus? circuits? Is there anything he doesn't have a video on? Bravo, sir.
I always wonder what his undergraduate major was to get this background. Chemical engineering maybe?
he knows a thing about everything and not everything about a thing, he uploads good videos generally but he doesn't go into the deep details and that's completely normal
i heard his major was electrical engineering depends on the uni but some of us also take chemistry classes @@graemep7729
Can I ask you a question ?
Do you find this video helpful ?
I mean Can I rely on this video for understanding and reviewing?
@Al_hamdoulilah_0 it is helpfull but not enough if you are an electrical engineering major that is
You still need to learn how to find Rth when there are dependent sources.
I bombed my first electrical exam. The next two I watched all your videos and did the practice problems, came out with an 84 and then a 93 on the final exam. I'm in your debt again, thank you!
ur welcome
Was on the verge of dropping out of engineering
@Afrah@2 EE tomorrow 😭🤣
@@263boi Me too bro hang in there we got this
same bro, same. but we're still trying
lol so truue but I still struggling😭
you from zimbabwe?
6:53 - 6 ohm load resistance Rl, you didnt write this down before anywhere, just thought I would point out for continuity. Thanks.
yeah i reversed it couple of times to know where it comes from
It was from when he did Nortons theorem he use the same problem so that’s where he got the six from He must’ve me the videos back to back I forgot to add the six this time
Me too
We need more people like u
Thank you, now I could know that maybe he just forgot to wrote it, because I was curious where he got that 6ohms
hey keep it up, I don't know if you have a stable job or not but please don't stop making these videos. You're helping people especially those in the third world country. Thank you so much keep it up. Hope you get more subscribers. God bless! Thank you so much I'm very grateful.
- ECE student 2nd year school year 2019-2020, I'm from a third world country
Same
Nigerian?
Am from Viet Nam, yes indeed those video is helping me a lots through college.
My greatest thank to you sir private tutor if you read this !
@@arnordtetris7496 sup, I graduated recently from my ECE currently preparing for board exam boy how time flies hehe
@@adamsonkhalid4905 asian from philippines
I think this guy always has the perfect videos for studying. Been a avid watching for years. Cheers boss.
You explained the theorem so well...I was afraid to try to learn this but now I'm able to solve most problems with ease!!!!! Thanks man! It means a lot! 😀😀😀
This was a good video, but you never mentioned the 6 ohms until we went to solve for I(L).
I went looking for a comment about this because I was confused about that too lol! Glad you noticed it too
thats all im looking for
I was pretty lost too, nearly rewatched to see if he had mentioned it before
So where 6 ohm come from ?
@@ScorBiduBiduXI it was just in the initial problem and he forgot to add it.
For the case of the thevenin voltage, why cant you use the potential divider formula?
Great video! I was wondering where the RL resistance = 6 came from. At 6:48 he says he'd written it down before, but all I saw was just plain "RL" without it = 6. Am I missing something?
Even I am thinking the same, please tell me, if you get to know the reason.
He say's because he wrote it before, and I also did not see it written or derived anywhere so I'm a bit confused
The only way I could think of to get 6 is to just straight up add the 3 resistances and divide by 3, but for some reason I highly doubt that's correct.
I scrolled back through several-year-old comments, and they said he forgot to include R = 6, which was a given for the problem.
god bless you@@laurabravo2073
How are you so good at teaching. Most people ask how are you so smart, but many people can learn the stuff you know, while very few (if any) can then teach it as well, and not just one subject, all of them.
You're an amazing resource for all of my classes this semester. Thank you so much for all the help!
if you dond mind can you explain how he got the load resistor 6?
@@usuis8541 load resistor 6 is already given
Great. I'm starting to see a pattern in solving for Thevenin circuit. Thank you!!!
What’s the pattern???
@@danielmoreno9935 first equivalent resistance making the short circuits and open circuits then apply KCL or KVL to find the voltage or current (in case it's Norton's) with the sources on and create the circuit in serie (thevenin) with the two given information
I've tried to understand this concept for a few weeks but after watching this video I really feel like I understand it properly. Thank you so much:)
Nice, now its my turn haha
What kind of man had so much knowledge
😂 A man with female problems i guess
A nerd
Engineers!
This channel is actually helping me in school. THANK YOU
Wtfff who the fuck teaches this at school?? This shit is at college's level
@@mr.blueitachi5258 don't u know I m in 12th standard and this is in My Syllablus
@@mr.blueitachi5258 hahahah yeahh me too, but he literally mentioned this channel not this video. so he was literally correct lmao
im 10 and im studying this lol
@@orlanyllanoautohubone9459 same here came here after going on physics galaxy channel where i had some confusions which this channel resolved
0:40 thevenin-resistance
2:30 thevenin-voltage
Thank you!
I can't believe this man literally exists,like I mean ,mann he's so packed with information. Thumbs up Mr Tutor 💯!!
Hey, i've just watched a bunch of videos to the thevenins theorem a cause to my assesment next tuesday. I wanted to thank you a lot because your video helped me a lot .!
Nice demonstration. At 4.30 you said the sum of currents is equal to 1, but should said zero, however you did write down the correct value.
At 6.24 you wrote 34.4 Ω instead of 34.4 V.
I was looking for this because this confused me as well. Glad to see this comment that helped fix the confusion!
i learned more watching this 9 minute video than i did on my 1 hour 30 min lecture class
Finished my degree in record Time Degree in Applied Chemiatry. Because of this guy❤❤.. 2018 to 2020 been fun with this guy😢😢❤❤❤the best Tutor ever
I've been journeying with you right from Junior High school. "Thank you" isn't enough
Very helpful as always! I like that you verify the results at the end by solving for the different values!
I actually learned a lot from this guy. Thank you keep the good work you are doing!!
Can you explain where certain numbers you came up came from. Like dude tell me how you got zero and then rest. You made me switch videos. Thanks guy.
He should be given a Nobel prize or something. If not for all the engineers he got through university and others he helped then for the shear amount of positive comments he gets.
Where did the 6 ohm load resistance come from? I'm using this as a part of a study guide for my Circuits exam.
Same hahahah im confused where the hell is that 6 ohms load comes from😂
@@anthonysta.iglesia7607 I think it must've come from the example problem he got it from. I'm just assuming lol.
I was gonna ask the exact same thing. He said "which is what i wrote down before" but i dont recall him writing anything like that lol
thanks for that I was so confused too
6:00 he also didn't multiply both sides by 20!
where did you get the load resistance of 6 ohms from i rewinded from start you never assigned a resistance for the RL
I agree. He never said said where the 6 ohm resistor came from. I think he just picked as an "example load".
@@Festus2022 ive been watching his other videos i think this might be a 2 parter or something and he reused the 6 ohm from that circuit
Let's take Load resistor as 6 ohm...take different value, will be given in the question, don't consider it in Thevenin's resistance, it is the step of solving Thevenin's theorem...
Probably one of the best videos on thevenin
u are better then my chem teacher
i listen to u from now on
How do you know what resistor is the "load resistor" /How do you know which resistor to remove?
I can't tell you how much your explaination helped me.....I don't get anything during the lecture
The Organic Chemistry tutor is the universal daddy.....
You are the best totur on You tube
Thank you a lot
@ 7:15, where did the 6 ohm resistor come from?
That was just the value that he chose for RL. It would most likely be given on a test or something
@@mklinger23 What if it's not given?
@@ShadowBeast then you solve Req normally without adding the RL to it
@@bsh8566 Thank youu!
Okay but how did he know that Rl = 6 ohms in the end?
wondering the same thing
@@stixsenpai5247 I think it's a given
Yh he said thats what he wrote down before but he didn't, just plucked it from thin air. It's stuff like this that triggers my anger issues ;(
Very well done! Thank you for this lesson! Greetings from Brasil
sth i never understood in my 1st year of college so well explained in a 10 mins video, not sure if its actually worth all the time and money to go thru college
wow, this guy is teaching more than my uni prof
Have a midterm tomorrow and you just saved my ass, thank you.
20 Min remaining of CT still watching 😅
Who's watching this while online learning and dont understand the lecturer talking too fast?🙋that moment i quickly move to yt😌thank you so much
This channel still alive wow im impressed
Where 6 ohm came from (RL) 6:51
Bro Aiman
It’s the value of the load resistance.
@@hishamawan16 yes but where did he get it from, how did he calculate it ?
LemonCurd he didn’t calculate it, its just a given value he didn’t write down earlier
I was having same doubt
@@hamstertiff99 You mean that was already given by the question is it ??
I wish you had a website that had notes and practice questions
VERY HELPFUL! Thank You!!
for everyone who is confused abt the 6ohm resistance it is the load resistance which was given in the question as RL = 6 ohm.. he just forgot to write it in the problem in the start... so yeah we didn't calculate it.. it was given
- 6 ohm load resistance Rl, you didnt write this down before anywhere, just thought I would point out for continuity. Thanks.
Thank you sir..I learned lot of lessons from you♥️🙏
why the hell my professor teach this for 2 hours and I didn't understanding a thing and this video is almost just 10 mins. and now I understand this theorem.
Maybe your professor teaches in a way that was unclear and confusing manner
I very much needed this. Thank you so much
Ye?
So well explaination, you save my time !
Thank you really much.
6:23 Volts, not Ohms.
Thanks man you saved my life
I'm sorry but where did you get 6 ohm load resistance from? from, you've said you've written it down before but where ?
I had my LCA mid today. I wish you had uploaded sooner.
At 5:49 you multiply 50V by 5 and then you add it to the 60A. Is this actually correct? I ask because You didn't keep the units while performing these calculations.
Doing god's work bro
Thank you so much sir! I hope you continue to make videos, they are so helpful!
How can we cosider the load resister as "open circuit" to calcuate Vth(Voltage-thevenin)? For the calculation, you assumed that there is no current flowing over the register (9 Ohm). Does it really make sense? I need your advice on this!
there's no current flowing over the 9 ohm resistor because there's an infinite resistance across point A and B due to the presence of air in between the two points ( since air acts as an insulator) so current is negligible, almost zero.
for the Thévenin circuit we remove the load resistor
To find the Thevenin Voltage, we have to assume the load resistor to be an open circuit because that's the variable that we want to measure. i.e. The current across the load. The will be no current flowing through the 9 ohm resistor since there is an open circuit across the path A to B and so all of the current will be flowing through the 5 ohm resistor. There will be no path along an open circuit
wow can this guy be my new professor
my God. you explained it soo clearly. Thank you
I just converted the voltage source to a current source and just added the sources and multiplied the parallel resistors 4 and 5 to find VTH
wowww......Great Brother very helpful , i solve this math.....
how u get RL
Please the value of the Load Resistor , was it given in the question. If not, how did you find it.
Thanks a lot, really helpful. One question tho: what happens if we have a capacitor or a coil in the circuit, besides all the resistors?
Current through that branch will be 0....and potential dif on that branch will we equal to sum of potentials on it
Good video. Correction at 4:13, sum of currents flowing in out of a junction adds up to 0.
Great circuit analysis videos
Why and how did you put ground in the circuit and why you put 0 at the node which is below I2 currect(3A)??
I'm still a little confused on why 6ohms for the load resistance? Also when u said the voltage at B was zero why isn't the voltage at A also 0? Because I thought they both were open circuits thus 0V right?
the 6 ohm was actually given but he forgot to mention it. and V at b was 0 because it was being compared to the ground. the potential voltage difference at ground is always 0, therefore Vb is 0 with respect to ground while A is not, because with the given position where A is, there is definitely some potential difference between A and ground.
hope this help
Thank you for this though why is it when I run a simulation for this the answer for the current is exactly 3.069 A not 2 A. The voltage is right.
I am manifesting people like him into my life
Where did you get 6 for load resistance from??
It wasn't in the initial circuit diagram.
am impressed incredible tutorial
I really like this no bullshit type explainations
I wish I saw this before my exams 😢
I wish I watched this video yesterday.
This helped so much! Thank you!
Understood it clearly
Pls upload more numaricals on this topic
I am in need
Please consider doing a serie about linear programming simplex and lemke method.. I'd be forever grateful. Or direct me towards some videos worth watching if possible thank you
Thankyou you are a saviour!
at about 1:30 why does it not work to add (1/5 and 1/9) + 4 when the 9 and 5 is in parallel and the 4 ohm is in series with them?
how are the 4ohm and 5ohm resistors in parellel????
Any answer ?
At 7:01 where did 6 Ohms come from?
Bro how do u get 6 ohm for load resistance
I don't get Thevenin's Theorem. I only understand that you do it to make the circuit simpler. First you get the Total Resistance : Rth, then hook it up onto the Loader Resistor. Why do we have to use the voltage at Vc? Wouldn't that mean the resistor behind it (R1=4ohm) won't be included? You are using Total Resistance but using a voltage that is past that resistance already. Hopefully someone answers please. Thank you
In the calculation for current through the load resistor, what are the bars above 34.4V and 17.2 ohms for? Great video by the way thank you!
it means that 34.4444...4 and 17.222222....2
may I ask why the 4 ohm is in parallel to the 5ohm resistor, not the 9ohm is in parallel to the 5ohm resistor? 1:27 thank you
Hey did you ever find this answers?
Nice explanation
how did the 6 ohms value come from
When did you specify that the load resistance was 6 ohms?
Where did the 6 Ohm Load resistance come from? It came out of nowhere and was not mentioned in the video until the last part. It just came out of nowhere. Was it given in the problem or calculated?
Where did you get that 6 Ohms?
South CurseOne that’s the value of load resistance
@@amancharlamanas3812 but where did he mention that ?
@@bryyd1922 the value of RL can literally be anything. Thevenin Equivalent looks at what voltage that resistor sees in front of it and the current across it. The voltage drop, in this case is 12, will change with any RL values since the VL=RL*iL and we calculated iL using the thevenin equvalent of the circuit.
For example, if you plug in 1 ohm as RL, you will get these values:
iL = 2.8197 A
VA = iL * RL = 2.8197A * 1Ohm = 2.8197 V
VC = 2.8197V + 2.8197A * 9Ohm = 28.197 V
Current across 5 Ohm = 28.197V / 5ohm = 5.6394 A = i5
@@zodcx ah ok. Makes sense now. Thanks a lot.
@@bryyd1922 you're welcome :D
from where you got the R1 6 Ohm
How is Load Resistance 6 ohm??