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he knows a thing about everything and not everything about a thing, he uploads good videos generally but he doesn't go into the deep details and that's completely normal
@Al_hamdoulilah_0 it is helpfull but not enough if you are an electrical engineering major that is You still need to learn how to find Rth when there are dependent sources.
I bombed my first electrical exam. The next two I watched all your videos and did the practice problems, came out with an 84 and then a 93 on the final exam. I'm in your debt again, thank you!
It was from when he did Nortons theorem he use the same problem so that’s where he got the six from He must’ve me the videos back to back I forgot to add the six this time
hey keep it up, I don't know if you have a stable job or not but please don't stop making these videos. You're helping people especially those in the third world country. Thank you so much keep it up. Hope you get more subscribers. God bless! Thank you so much I'm very grateful. - ECE student 2nd year school year 2019-2020, I'm from a third world country
Professor Organic Chemistry Tutor, thank you for explaining Thevenin's Theorem by solving a classical Circuit Analysis problem from start to finish. When I took Circuit Analysis many years ago, I did not fully understand this material, however my knowledge of the material has improved over time. This is an error free video/lecture on TH-cam TV with the Organic Chemistry Tutor.
FOR ANYONE CONFUSED , he randomly included Rload = 6 ohms in the middle of the video , it wasnt given at the start . Its abit confusing unfortunately :(
This is super. I have watched so many vids and read this in books and could not get my head around it. This makes it so simple. You DON'T skip steps like the others. I couldn't grasp why R1 was in parallel with R2. Now I follow. Your vid on series/parallel was a great help leading up to this. Thanks
@@carltonyuan2442 Hi Carlton. It took me a few vids to get my head around this. Remove the voltage source providing a short circuit as instructed. That brings the left hand end of the 4 ohm resistor to earth - in parallel to the 5 ohm. It helps to redraw the 4 ohm resistor vertically where the voltage source used to be. Hope this helps.
@@carltonyuan2442simply because they are not there in the same line. Same line is series and opposite is parallel. From the diagram you can see that 4 and 5 are not on same line so parallel and when these two combined we can draw that upper side 4 ohm or 5 ohm it can be series with 9 ohm. Hope this helps you .
Hey, i've just watched a bunch of videos to the thevenins theorem a cause to my assesment next tuesday. I wanted to thank you a lot because your video helped me a lot .!
You explained the theorem so well...I was afraid to try to learn this but now I'm able to solve most problems with ease!!!!! Thanks man! It means a lot! 😀😀😀
I just wanna say big thanks to you man for publishing all these videos you're great person ❤❤ I was randomly scrolling through youtube where i saw one of your videos and remembered how much they helped me back in the days when i was studying computer engineering.
Great video! I was wondering where the RL resistance = 6 came from. At 6:48 he says he'd written it down before, but all I saw was just plain "RL" without it = 6. Am I missing something?
The only way I could think of to get 6 is to just straight up add the 3 resistances and divide by 3, but for some reason I highly doubt that's correct.
"Bro, that was incredible! You just cleared all my doubts with such an amazing lecture! ❤️ For those who might be confused about how Sir is calculating the potential at each point (like the 12V at the beginning), here's a breakdown: In a circuit, there's a potential drop when current flows through a resistor, which is calculated using the formula V=IR. If there's no resistance (i.e.,R=0), there won't be any potential drop. Hope this clears things up! ❤️"
How are you so good at teaching. Most people ask how are you so smart, but many people can learn the stuff you know, while very few (if any) can then teach it as well, and not just one subject, all of them.
Exactly!! I mean If you're an engineer and you're working hard to get your degree, so you study all of these subjects like chemistry,math, physics and etc. So basically you know all of that at some point. I mean, it's still impressive but what fascinates me more is his teaching skills.
@@danielmoreno9935 first equivalent resistance making the short circuits and open circuits then apply KCL or KVL to find the voltage or current (in case it's Norton's) with the sources on and create the circuit in serie (thevenin) with the two given information
He should be given a Nobel prize or something. If not for all the engineers he got through university and others he helped then for the shear amount of positive comments he gets.
Hello sir, you've totally forgot to calculation the value of the load resistor. But I do continue to thank you for your lessons that had helped me immensely.
Let's take Load resistor as 6 ohm...take different value, will be given in the question, don't consider it in Thevenin's resistance, it is the step of solving Thevenin's theorem...
Nice demonstration. At 4.30 you said the sum of currents is equal to 1, but should said zero, however you did write down the correct value. At 6.24 you wrote 34.4 Ω instead of 34.4 V.
@@wankhairolyusri9449 its just that he simplified the numbers. Added up the vc to -9 and moved it to the other side, so it becomes positive. And added up 250 to 60, thus giving you 310
why the hell my professor teach this for 2 hours and I didn't understanding a thing and this video is almost just 10 mins. and now I understand this theorem.
for everyone who is confused abt the 6ohm resistance it is the load resistance which was given in the question as RL = 6 ohm.. he just forgot to write it in the problem in the start... so yeah we didn't calculate it.. it was given
You don’t have to do nodal analysis at all at that 4:06 , just do a quick source transformation for the Voltage source putting an upward facing current source of 50/4 Amps parallel to a 4Ohm resistor. After that Add the 50/4 and the 3Amp current source as they’re both in parallel whilst also adding the parallel 5 ohm , 4 ohm resistors. Then just do V=IR which results in 31/2 times 20/9 = 34.4V .
3:28 I'll take note of this, if there is open circuit then there is no voltage drop to VA. That means Vc = Va or the voltage on one end of the resistor is = to other end of resistor and not 0V I finally got it lol
Final Exams and Video Playlists: www.video-tutor.net/
Final Exams and Video Playlists: www.video-tutor.net/
Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections
Hey! wher did the six come from after calculating thevenin's voltage
@@vincenciaondigo3584that could be any value according to the question given.... It's not something that was calculated
how, and why, does this guy know so much stuff?? Like... chemistry? calculus? circuits? Is there anything he doesn't have a video on? Bravo, sir.
I always wonder what his undergraduate major was to get this background. Chemical engineering maybe?
he knows a thing about everything and not everything about a thing, he uploads good videos generally but he doesn't go into the deep details and that's completely normal
i heard his major was electrical engineering depends on the uni but some of us also take chemistry classes @@graemep7729
Can I ask you a question ?
Do you find this video helpful ?
I mean Can I rely on this video for understanding and reviewing?
@Al_hamdoulilah_0 it is helpfull but not enough if you are an electrical engineering major that is
You still need to learn how to find Rth when there are dependent sources.
once I see this channel's name in search results, I know I'm safe.
I can so relate 😌
same over here huhuhuhu
Same here
Yes😄😄
Amen to that
I've tried to understand this concept for a few weeks but after watching this video I really feel like I understand it properly. Thank you so much:)
Nice, now its my turn haha
Interestingly, all the videos you have been posting lately are exactly what I need as I've been learning it
Correct
Same, saving my Circuits grade!
Me too!
.sjbr
th-cam.com/video/p2GNgMG15mE/w-d-xo.html
I bombed my first electrical exam. The next two I watched all your videos and did the practice problems, came out with an 84 and then a 93 on the final exam. I'm in your debt again, thank you!
ur welcome
@@anasm6751 brother you didn't do shit
What kind of man had so much knowledge
😂 A man with female problems i guess
A nerd
Engineers!
Was on the verge of dropping out of engineering
@Afrah@2 EE tomorrow 😭🤣
@@263boi Me too bro hang in there we got this
same bro, same. but we're still trying
lol so truue but I still struggling😭
you from zimbabwe?
6:53 - 6 ohm load resistance Rl, you didnt write this down before anywhere, just thought I would point out for continuity. Thanks.
yeah i reversed it couple of times to know where it comes from
It was from when he did Nortons theorem he use the same problem so that’s where he got the six from He must’ve me the videos back to back I forgot to add the six this time
Me too
We need more people like u
Thank you, now I could know that maybe he just forgot to wrote it, because I was curious where he got that 6ohms
hey keep it up, I don't know if you have a stable job or not but please don't stop making these videos. You're helping people especially those in the third world country. Thank you so much keep it up. Hope you get more subscribers. God bless! Thank you so much I'm very grateful.
- ECE student 2nd year school year 2019-2020, I'm from a third world country
Same
Nigerian?
Am from Viet Nam, yes indeed those video is helping me a lots through college.
My greatest thank to you sir private tutor if you read this !
@@arnordtetris7496 sup, I graduated recently from my ECE currently preparing for board exam boy how time flies hehe
@@adamsonkhalid4905 asian from philippines
I think this guy always has the perfect videos for studying. Been a avid watching for years. Cheers boss.
Professor Organic Chemistry Tutor, thank you for explaining Thevenin's Theorem by solving a classical Circuit Analysis problem from start to finish. When I took Circuit Analysis many years ago, I did not fully understand this material, however my knowledge of the material has improved over time. This is an error free video/lecture on TH-cam TV with the Organic Chemistry Tutor.
FOR ANYONE CONFUSED , he randomly included Rload = 6 ohms in the middle of the video , it wasnt given at the start . Its abit confusing unfortunately :(
This is super. I have watched so many vids and read this in books and could not get my head around it. This makes it so simple. You DON'T skip steps like the others. I couldn't grasp why R1 was in parallel with R2. Now I follow. Your vid on series/parallel was a great help leading up to this. Thanks
why is it parallel help me please
@@carltonyuan2442 Hi Carlton. It took me a few vids to get my head around this. Remove the voltage source providing a short circuit as instructed. That brings the left hand end of the 4 ohm resistor to earth - in parallel to the 5 ohm. It helps to redraw the 4 ohm resistor vertically where the voltage source used to be. Hope this helps.
Yeah these professors be skipping 50 steps while explaining
@@carltonyuan2442simply because they are not there in the same line. Same line is series and opposite is parallel. From the diagram you can see that 4 and 5 are not on same line so parallel and when these two combined we can draw that upper side 4 ohm or 5 ohm it can be series with 9 ohm. Hope this helps you .
@@karthikgaming2690Well if i consider the following loop : source (50v) then r1 and then r2 theb they are clearly in series.
Hey, i've just watched a bunch of videos to the thevenins theorem a cause to my assesment next tuesday. I wanted to thank you a lot because your video helped me a lot .!
You explained the theorem so well...I was afraid to try to learn this but now I'm able to solve most problems with ease!!!!! Thanks man! It means a lot! 😀😀😀
I just wanna say big thanks to you man for publishing all these videos you're great person ❤❤
I was randomly scrolling through youtube where i saw one of your videos and remembered how much they helped me back in the days when i was studying computer engineering.
Great video! I was wondering where the RL resistance = 6 came from. At 6:48 he says he'd written it down before, but all I saw was just plain "RL" without it = 6. Am I missing something?
Even I am thinking the same, please tell me, if you get to know the reason.
He say's because he wrote it before, and I also did not see it written or derived anywhere so I'm a bit confused
The only way I could think of to get 6 is to just straight up add the 3 resistances and divide by 3, but for some reason I highly doubt that's correct.
I scrolled back through several-year-old comments, and they said he forgot to include R = 6, which was a given for the problem.
god bless you@@laurabravo2073
I can't believe this man literally exists,like I mean ,mann he's so packed with information. Thumbs up Mr Tutor 💯!!
What is better than a coherent and comprehensible educational video for a student? Thank you so much ;)
If only we had coherent and comprehensible teachers
"Bro, that was incredible! You just cleared all my doubts with such an amazing lecture! ❤️
For those who might be confused about how Sir is calculating the potential at each point (like the 12V at the beginning), here's a breakdown:
In a circuit, there's a potential drop when current flows through a resistor, which is calculated using the formula
V=IR. If there's no resistance (i.e.,R=0), there won't be any potential drop.
Hope this clears things up! ❤️"
thanks so much man, you're a last minute savior!
You're an amazing resource for all of my classes this semester. Thank you so much for all the help!
if you dond mind can you explain how he got the load resistor 6?
@@usuis8541 load resistor 6 is already given
A months worth of lectures to study for the morning. Here we go
This channel is actually helping me in school. THANK YOU
Wtfff who the fuck teaches this at school?? This shit is at college's level
@@mr.blueitachi5258 don't u know I m in 12th standard and this is in My Syllablus
@@mr.blueitachi5258 hahahah yeahh me too, but he literally mentioned this channel not this video. so he was literally correct lmao
im 10 and im studying this lol
@@orlanyllanoautohubone9459 same here came here after going on physics galaxy channel where i had some confusions which this channel resolved
I've been journeying with you right from Junior High school. "Thank you" isn't enough
WOHOOOOOOO LET'S F... GOOOOO. THIS IS THE FIRST CIRCUIT I SUCCESSFULLY CALCULATED THEVENIN. LET'S GO BROOOOO.
This Guy made me Pass with flying colors my High school Studies Much Respect I am happy to see he has got 4.77Million Subs
How are you so good at teaching. Most people ask how are you so smart, but many people can learn the stuff you know, while very few (if any) can then teach it as well, and not just one subject, all of them.
Exactly!! I mean If you're an engineer and you're working hard to get your degree, so you study all of these subjects like chemistry,math, physics and etc. So basically you know all of that at some point. I mean, it's still impressive but what fascinates me more is his teaching skills.
0:40 thevenin-resistance
2:30 thevenin-voltage
Thank you!
Finished my degree in record Time Degree in Applied Chemiatry. Because of this guy❤❤.. 2018 to 2020 been fun with this guy😢😢❤❤❤the best Tutor ever
i learned more watching this 9 minute video than i did on my 1 hour 30 min lecture class
The man, the myth, The Organic Chemistry Tutor. God bless your soul for dumbing stuff down for us panicking students!
Probably one of the best videos on thevenin
Great. I'm starting to see a pattern in solving for Thevenin circuit. Thank you!!!
What’s the pattern???
@@danielmoreno9935 first equivalent resistance making the short circuits and open circuits then apply KCL or KVL to find the voltage or current (in case it's Norton's) with the sources on and create the circuit in serie (thevenin) with the two given information
I understand you better than my lecturers, thanks for the effort.
He should be given a Nobel prize or something. If not for all the engineers he got through university and others he helped then for the shear amount of positive comments he gets.
This was a good video, but you never mentioned the 6 ohms until we went to solve for I(L).
I went looking for a comment about this because I was confused about that too lol! Glad you noticed it too
thats all im looking for
I was pretty lost too, nearly rewatched to see if he had mentioned it before
So where 6 ohm come from ?
@@ScorBiduBiduXI it was just in the initial problem and he forgot to add it.
I actually learned a lot from this guy. Thank you keep the good work you are doing!!
u are better then my chem teacher
i listen to u from now on
The Organic Chemistry tutor is the universal daddy.....
Very helpful as always! I like that you verify the results at the end by solving for the different values!
crazy things about this guy he know almost every math and electrical problems
You saved my life bro thank you so much.😅
4:29 he said that Kirchoff's law means that the current in and out must sum to 1, but its actually 0
No as per kir Kirchhoff's law integral(E.dl)=0.. which means current sums to zero along any line or junction
@@Abhisheism Thats what he is saying. 0 not 1.
yes hw said 1 but wrote 0(he must have said 1 by mistake)
it was a mistake...
We can simply say that he is still a human who commit mistakes.
Ahh i got this!!! Thank you so much sir 😁🎉
Helpful! But why the load resistor is 6 ohm ?
I also didn't see his 6 ohm calculations
@@Teezy777 the question will tell h what the load resistor is
Literally, thanks. I was trying to understand this method for month now thanks (:
You are the best totur on You tube
Thank you a lot
This channel still alive wow im impressed
Can you explain where certain numbers you came up came from. Like dude tell me how you got zero and then rest. You made me switch videos. Thanks guy.
Hello sir, you've totally forgot to calculation the value of the load resistor. But I do continue to thank you for your lessons that had helped me immensely.
Thank you. I am passing my college semester exam because of you.
@ 7:15, where did the 6 ohm resistor come from?
That was just the value that he chose for RL. It would most likely be given on a test or something
@@mklinger23 What if it's not given?
@@ShadowBeast then you solve Req normally without adding the RL to it
@@bsh8566 Thank youu!
Thank you sir..I learned lot of lessons from you♥️🙏
where did you get the load resistance of 6 ohms from i rewinded from start you never assigned a resistance for the RL
I agree. He never said said where the 6 ohm resistor came from. I think he just picked as an "example load".
@@Festus2022 ive been watching his other videos i think this might be a 2 parter or something and he reused the 6 ohm from that circuit
Let's take Load resistor as 6 ohm...take different value, will be given in the question, don't consider it in Thevenin's resistance, it is the step of solving Thevenin's theorem...
Where did the 6 ohm load resistance come from? I'm using this as a part of a study guide for my Circuits exam.
Same hahahah im confused where the hell is that 6 ohms load comes from😂
@@anthonysta.iglesia7607 I think it must've come from the example problem he got it from. I'm just assuming lol.
I was gonna ask the exact same thing. He said "which is what i wrote down before" but i dont recall him writing anything like that lol
thanks for that I was so confused too
6:00 he also didn't multiply both sides by 20!
Where did you get 6 for load resistance from??
It wasn't in the initial circuit diagram.
Tmo is my exam but I pretty sure I'll pass because of this legend
For the case of the thevenin voltage, why cant you use the potential divider formula?
you are a legend
living legend
Thank you for this............................................
☺☺☺☺
God bless you for making studying so much easier
Have a midterm tomorrow and you just saved my ass, thank you.
Thanks man you saved my life
Nice demonstration. At 4.30 you said the sum of currents is equal to 1, but should said zero, however you did write down the correct value.
At 6.24 you wrote 34.4 Ω instead of 34.4 V.
I was looking for this because this confused me as well. Glad to see this comment that helped fix the confusion!
im confused where the six ohm come from 6:48. did he just chose one? im not good at english sorry.
It's the load resistance which was removed previously
wow, this guy is teaching more than my uni prof
this guy is a SAINT
these videos boosts my 32.33 repeating of course percentage of survival.
Very well done! Thank you for this lesson! Greetings from Brasil
You should make a video about why you know so many subjects well, it is quite impressive
Who's watching this while online learning and dont understand the lecturer talking too fast?🙋that moment i quickly move to yt😌thank you so much
Source transformation makes this problem even easier in the beginning! I got the same answers as well using that method. Try it out!
hey,do u know why should the 310=9Vc should be over 9 for both sides?i am new in this
@@wankhairolyusri9449 its just that he simplified the numbers. Added up the vc to -9 and moved it to the other side, so it becomes positive. And added up 250 to 60, thus giving you 310
why the hell my professor teach this for 2 hours and I didn't understanding a thing and this video is almost just 10 mins. and now I understand this theorem.
Maybe your professor teaches in a way that was unclear and confusing manner
This guy is the best ❤
wowww......Great Brother very helpful , i solve this math.....
Parallels can also be calculated as the product over the sum of the resistors. Never has it not worked. That's what the equation simplifies to.
It helped me a lot for my school
1000X better than my prof explained it
VERY HELPFUL! Thank You!!
Where did you get the 6 ohms load resistance?
yes please i have the same question where did the six come from in the 6:57mins
A and B poin resistance 6 ohms which we thought load resistance
this is free and is better than my university lecture. Why the hell do we pay 9 grand for that when this is astronomically better
I very much needed this. Thank you so much
Ye?
wow can this guy be my new professor
Thank you so much sir 😭
for everyone who is confused abt the 6ohm resistance it is the load resistance which was given in the question as RL = 6 ohm.. he just forgot to write it in the problem in the start... so yeah we didn't calculate it.. it was given
You don’t have to do nodal analysis at all at that 4:06 , just do a quick source transformation for the Voltage source putting an upward facing current source of 50/4 Amps parallel to a 4Ohm resistor. After that Add the 50/4 and the 3Amp current source as they’re both in parallel whilst also adding the parallel 5 ohm , 4 ohm resistors. Then just do V=IR which results in 31/2 times 20/9 = 34.4V .
watching this makes 1'000'000% more sense than my lecturer
Why did he multiply by 20 @5:26 ? Does it have to be 20 or is it just a random number?
hey if u still don't know by now, 20 was multiplied to simplify the equation, also 20 is lcd of 4 and 5.
am impressed incredible tutorial
Doing god's work bro
Where did he get the 6 resistance on the last solution?
pls help
It was given in the question already.
Thanks man! You're the best!
So well explaination, you save my time !
Thank you really much.
I wish I saw this before my exams 😢
How did we solve for RL to equal 6ohms?
at about 1:30 why does it not work to add (1/5 and 1/9) + 4 when the 9 and 5 is in parallel and the 4 ohm is in series with them?
3:28 I'll take note of this, if there is open circuit then there is no voltage drop to VA. That means Vc = Va or the voltage on one end of the resistor is = to other end of resistor and not 0V I finally got it lol
Thankyou you are a saviour!