Equivalent Resistance of Complex Circuits - Resistors In Series and Parallel Combinations
ฝัง
- เผยแพร่เมื่อ 10 ธ.ค. 2017
- This physics video provides a basic introduction into equivalent resistance. It explains how to calculate the equivalent resistance of circuits with resistors in series and parallel combinations.
Schematic Diagrams & Symbols: • Schematic Diagrams & S...
Resistors In Series:
• Resistors In Series - ...
Resistors In Parallel:
• Resistors In Parallel ...
Series and Parallel Circuits - Light Bulb Brightness:
• Series and Parallel Ci...
How To Solve DC Circuits:
• How To Solve Any Resis...
_________________________
Voltage Divider Circuit:
• Voltage Divider Circui...
Current Dividers:
• Current Dividers Expla...
Parallel Circuit Challenge Problem:
• Finding The Current In...
Kirchhoff's Current Law:
• Kirchhoff's Current La...
Kirchhoff's Voltage Law:
• Kirchhoff's Voltage La...
DC Circuits Review:
• Series and Parallel Ci...
____________________________
KCL and KVL Circuit Analysis:
• Kirchhoff's Law, Junct...
Thevenin's Theorem - Circuit Analysis:
• Thevenin's Theorem - C...
Norton's Theorem - Circuit Analysis:
• Norton's Theorem and T...
Superposition Theorem:
• Superposition Theorem
Maximum Power Transfer:
• Maximum Power Transfer...
Physics PDF Worksheets:
www.video-tutor.net/physics-b...
Final Exams and Video Playlists: www.video-tutor.net/
Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections
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Greetings! I found that you made a little mistake between 8:46-8:50. These three resistors are in series not parrallel but the good thing is that you got the right answer it might be a pronunciation mistake. 😇
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Top quality tutorial. In my experience the place where most errors occur is the calculation of the parallel resistances. Students make errors on the calculator entering all the numbers. I now teach product over sum which has a far greater success rate. For anyone who does not know two resistors in parallel can be calculated by multiplying the two values together and then dividing by the sum of their values. So lets say 2 resistors 4 ohms & 6 ohms. (4 x 6) divided by (4 +6) = 24 divided by 10 =2.4 ohms. For 3 resistor just calculate an equivalent value for the first 2 and do the calculation again with the first answer and the third resistor. There seem to be far less calculator input errors using this method.
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