This is the best Thevenin's theorem + example video I've seen so far (I've watched half a dozen by now). Thank you for the clear and concise video! Bless you
I’ve been studying all day and this is by far the most helpful video I’ve come across thank you so much!!! For anyone who needs a step by step explanation this is for you
Thanks for this. The book I’ve been using to teach myself wasn’t very good at explaining things and I needed the guidance. Now I understand why this theorem is so important.
Best explain,I will give out of out 100, Becouse next Tommrow of my exam in college in BTech in electrical engineering in 3rd sem. But I understand concept only in one time' but my professor was explained all time😅😅😅
🎯 Key Takeaways for quick navigation: 00:00 📜 *Introduction to Thevenin's Theorem* - Thevenin's Theorem, developed by French engineer Lyon Thevenin in 1883. - Explains the need for Thevenin's Theorem when dealing with variable elements in a circuit and the advantages it offers in simplifying complex networks. 01:34 🔍 *Thevenin's Theorem Statement* - Thevenin's Theorem states that a linear bi-directional two-terminal network can be replaced by an equivalent network with a voltage source (Vth) in series with a resistor (Rth). - Describes the significance of Vth (open-circuit voltage at the terminals) and Rth (input resistance when independent sources are turned off) in the equivalent circuit. 03:19 🔄 *Example of Applying Thevenin's Theorem* - Illustrates the application of Thevenin's Theorem using a practical circuit. - Emphasizes the replacement of a complex network with Thevenin's equivalent circuit (Vth in series with Rth) for simplifying analysis. 08:31 📐 *Calculating Thevenin Voltage (Vth)* - Demonstrates the steps to calculate Vth by modifying the circuit, applying nodal analysis, and determining the open-circuit voltage between terminals. - Shows the importance of maintaining consistent polarity throughout the analysis. 10:30 🧮 *Calculating Thevenin Resistance (Rth)* - Outlines the process of calculating Rth by turning off independent sources, modifying the network, and finding the equivalent resistance. - Highlights the parallel and series combination of resistors in the modified network. 11:25 ⚡ *Solving Circuit with Thevenin Equivalent* - Applies Thevenin's equivalent circuit to solve for the current flowing through a load resistor (RL) in two different scenarios. - Shows how the simplicity of Thevenin's equivalent circuit facilitates easy calculations for varying load resistances.
Thank you for short and understandable lesson videos . Can you make videos about Biomedical İnstrumentation , bioMems , signal processing and biomedical devices , like other videos ?
I did'nt understand the voltage source removing to find the equivalent resistance . One is short circuited and otherone is disconnected . Please if u can recommend me a lecture to understand it. Thankyou for the lecture.
As explained in the lecture, we replace the independent source by its "internal resistance". An ideal voltage source has zero internal resistance and hence we replace it by a short circuit, and an ideal current source has infinite internal resistance and therefore we replace it by an open circuit.
Do u think potential difference is the only reason why current flows ? V=IR( ohms law ) Here resistance is zero that's why no potential difference or no potential drop but current ain't zero right ? It's the resistance which is zero
Thank you soo much sir for explaining these concepts in easiest form . I'm very helpful from your videos . Plz provide PDF 9f these lectures will helps me alot for digital learning although I already made notes but also want pdf plz sir 😀🙏❤️
For voltage sources, we set their voltage to zero, effectively replacing them with a short circuit. For current sources, we set their voltages to zero, effectively replacing them with an open circuit.
The answer should have been 24 V had the two resistors been in series. They are in not in series or parallel so the voltage Or current division rule cannot applied. Note that there is a current source of 2A connected between them making the point a principal node.
@@hemantbhatt3553 can’t we use a simple mesh analysis equation -32 + 4i +12i =0 I=2A and the same current flows through entire circuit. As the 1ohm resistor is open and voltage can’t flow. The resistance at 12ohm is v=ir 12x2=24volts and since 4&12 ohms are series same voltage flows and Vth is 24volts
Yes it is , in the starting you can see that it's already mentioned that Rth is input/equivalent resistance at the terminal... So I think that we calculate it like that only
you just summarized 8 days worth of lessons in just 13 minutes. absolute legend
goat
Who r watching just 1 night b4 exam 😂
Chup ho ja randike
3:30 hrs before🎉
Me
I'm watching after exam😊
30 minutes b4 xdxd
This is the best Thevenin's theorem + example video I've seen so far (I've watched half a dozen by now). Thank you for the clear and concise video! Bless you
I have cleared my all confusions about thevenin's theorem after taking this lecture....
Sir u'r helping me a lot
IT'S ok Ra nanna
@@detainedboi5335 telugu aa
thanks teacher.... I have been trying to understand this topic for 3 hours and it lasted 13 mins thanks for your video
I’ve been studying all day and this is by far the most helpful video I’ve come across thank you so much!!!
For anyone who needs a step by step explanation this is for you
Thanks for this. The book I’ve been using to teach myself wasn’t very good at explaining things and I needed the guidance. Now I understand why this theorem is so important.
Really helps alot..searching on TH-cam and found a perfect destination..clear voice and clear conceptual clarity...🙏🏻🙏🏻🙏🏻🙏🏻..
Chala exciting ga feel avthunnad
@@detainedboi5335 adhey magicuu
A doubt; How the $ ohm resistor and 12 ohm resistor are parallel and those are in series with 1 ohm resistor?
@@gamerclash7092 because same current will not flow accross 4 and 12 ohm resistor so it will be parallel.
1 night before exam 🗿
Am waiting for it last 2 months
Thanks
Ur teaching was perfect sir.. 👌👏Tnx foh helping us to understanding..🤝
No change....again excellent teaching....love towards NESO 😊😊
Didi Can you please help me in understanding that why did he short circuited the voltage source but open circuit the current source ?????
Plzzz
@@Ppadira voltage source have internal resistance less
Current source have internal resistance near to infinity
Thank you sir , this 12 minutes is very very efficacious for me, love from Kerala 🙏
Best explain,I will give out of out 100,
Becouse next Tommrow of my exam in college in BTech in electrical engineering in 3rd sem.
But I understand concept only in one time' but my professor was explained all time😅😅😅
3 hrs before exam 😂😢
😂
😂😂😂😂😂yup
You are an angel saving me in my EEE exams. Thanks a lot
Saved the day😭🙏🙏🙏🙏
I really want to appreciate the brain behind this explaination and TH-cam channel. Please how can i get the textbook that contains all questions?
thank you sir for explaining this very hard topic very easly thank you very much
Watching 1/2 hr before exam
know i realized that i simply wasted my time by sitting in the class .i understood in one vedio thank you so much
I understand your videos very well sir. If you search for any topic TH-cam, your videos will be there first👈 sir... good explanation sir 🙏🙏
bro luv you ho gya we started studying the night of exam and it worked out well..
Half n hour before exam >>>>>>
Thanks Sir, Please make more videos on Electrical engineering topics.
Deserves more likes & views
nice video, just a question, why Rth is not 4?
Thank you for creating such valuable resources 🙏
tbh i tried understanding Thevenin's Theorem in book it is very complicated and messy
you explained it very well
never knew it was that easy
Your lectures are really awesome Sir!!!💯💯💯💯
I'm watching just 15 minutes before exam😉
I am definitely following and subscribing ❤❤
Thank you very much sir you're videos are very helpful sir😇😇😇
Thank you sir but having one doubt from where you get 4ohms??
Omg...thank you sooo muchh sirrrr
Thank you sm, I understand clearly now.
Do we only apply the vx where there is a voltage drop?
🎯 Key Takeaways for quick navigation:
00:00 📜 *Introduction to Thevenin's Theorem*
- Thevenin's Theorem, developed by French engineer Lyon Thevenin in 1883.
- Explains the need for Thevenin's Theorem when dealing with variable elements in a circuit and the advantages it offers in simplifying complex networks.
01:34 🔍 *Thevenin's Theorem Statement*
- Thevenin's Theorem states that a linear bi-directional two-terminal network can be replaced by an equivalent network with a voltage source (Vth) in series with a resistor (Rth).
- Describes the significance of Vth (open-circuit voltage at the terminals) and Rth (input resistance when independent sources are turned off) in the equivalent circuit.
03:19 🔄 *Example of Applying Thevenin's Theorem*
- Illustrates the application of Thevenin's Theorem using a practical circuit.
- Emphasizes the replacement of a complex network with Thevenin's equivalent circuit (Vth in series with Rth) for simplifying analysis.
08:31 📐 *Calculating Thevenin Voltage (Vth)*
- Demonstrates the steps to calculate Vth by modifying the circuit, applying nodal analysis, and determining the open-circuit voltage between terminals.
- Shows the importance of maintaining consistent polarity throughout the analysis.
10:30 🧮 *Calculating Thevenin Resistance (Rth)*
- Outlines the process of calculating Rth by turning off independent sources, modifying the network, and finding the equivalent resistance.
- Highlights the parallel and series combination of resistors in the modified network.
11:25 ⚡ *Solving Circuit with Thevenin Equivalent*
- Applies Thevenin's equivalent circuit to solve for the current flowing through a load resistor (RL) in two different scenarios.
- Shows how the simplicity of Thevenin's equivalent circuit facilitates easy calculations for varying load resistances.
Good evening Sir
What if there was a dependent source in between then we have to do nothing with it na sir?
Please suggest 🙏
College exam?
@@adityasarvade7817vit?
Ur help is unforgettable for me sir
thank you, simple and clearly explained
Thanks for all
You are best
Thank You soo much Sir ...
Watching this 15 minutes before exam
Nice explanation
How I can thank you sir....your explanation is very clear and easy to understand and that example problem also able to understand.. thank you alot sir
Thanku sir
Simplicity exist here.
Thank you for short and understandable lesson videos . Can you make videos about Biomedical İnstrumentation , bioMems , signal processing and biomedical devices , like other videos ?
Thank you..... I understand perfectly.....☺☺☺
Sir please try to upload resonance videos.we are feeling much difficulty in understanding resonant circuits
thanks for explaning it , it really helps .
Thank you very much for this.
I'm watching 2 hours before exam😂
very helpful. Thank you!!
Awesome video about Thevenin's theorem! I needed this and this is perfect for me
please also make a video of Norton's theorem
Your videos are really ...really helpful sir.......thanks a lot
Me watching this 3hr before exam
Sir you are the bast teacher
Thank you Sir!
Your voice, unlike many an Indian gurus, is pleasant. But you could've drawn it right from the beginning like Khan Academy does.
I have exam with in 1hour
I am watching now
Wonderful explanation.
watching this on exam day :)
I did'nt understand the voltage source removing to find the equivalent resistance . One is short circuited and otherone is disconnected . Please if u can recommend me a lecture to understand it. Thankyou for the lecture.
As explained in the lecture, we replace the independent source by its "internal resistance". An ideal voltage source has zero internal resistance and hence we replace it by a short circuit, and an ideal current source has infinite internal resistance and therefore we replace it by an open circuit.
@@pawankumarmishra6699 thank you mishra ji
@@pawankumarmishra6699 hey hi, do u know why he grounded the 12ohm branch while calculating Vth?
You guys are doing a good job keep it up well done
Sir Vx=Vth, why i3 current between Vx and Vth , there is no potential difference......?
i know right
Do u think potential difference is the only reason why current flows ?
V=IR( ohms law )
Here resistance is zero that's why no potential difference or no potential drop but current ain't zero right ? It's the resistance which is zero
🆕 @Nini 🆕 Sanjay 🆕 New 🆕🆕
Since VX=vth, so potential difference is 0 here.
Very helpful
Thank you soo much sir for explaining these concepts in easiest form . I'm very helpful from your videos . Plz provide PDF 9f these lectures will helps me alot for digital learning although I already made notes but also want pdf plz sir 😀🙏❤️
While calculating Rth why voltage source considered as short circuit and current source as open circuit??
For voltage sources, we set their voltage to zero, effectively replacing them with a short circuit.
For current sources, we set their voltages to zero, effectively replacing them with an open circuit.
sir why have we considered 1 ohm for calculating equivalent resistance but not for calculating voltage
Thank you so much sir
great writing mate
Why we can't apply voltage divider for Vth
Vth=32*12/(4+12)= 24 Volt
While in soln Vth= 30 Volt
I have same doubt
The answer should have been 24 V had the two resistors been in series. They are in not in series or parallel so the voltage Or current division rule cannot applied. Note that there is a current source of 2A connected between them making the point a principal node.
@@hemantbhatt3553 can’t we use a simple mesh analysis equation
-32 + 4i +12i =0 I=2A and the same current flows through entire circuit. As the 1ohm resistor is open and voltage can’t flow. The resistance at 12ohm is v=ir
12x2=24volts and since 4&12 ohms are series same voltage flows and Vth is 24volts
@@hemantbhatt3553 if possible can you please answer soon I have an exam in 2 days
Thanks for this ice informative lecture.
thank you sir
It's 3 am and I have exam tomorrow 😂😂
thank you so much
Thank you sir 🙌
amazing!!!
Yes I'm watching on the exam day 😢
Im watching 20 min before exm😂
9:42 I don't understand the looked from part , how we looked from there ? Isn't that general Req ?
Yes it is , in the starting you can see that it's already mentioned that Rth is input/equivalent resistance at the terminal...
So I think that we calculate it like that only
Thank u so much bhaiya
Sir plz upload more about network theory plz
Thanks sir
Thanks sir,u help a lot
Thanks for your lecturer vedio
🥺🥺🥺 thankyou so much sir
Kon kon bsc 2 nd year se h 😅
Thnks for this thing
Very helpful sir... Please upload ..
Watching while writing the exam 🌚
How to assume current directions 6:45
8:03 3vx-96+vx=12 right? Not 24
Am I right.
No. You are doing some calculation error. When taking the LCM, which is 12, the -2 will be multiplied by 12 to give -24.
Why 12 and 1 ohm resistor are not parallel with series on 4
i.e (12||1)+4 ...why ,please help......
Sir rth lo 4ohms 12ohms series lo unnai kada sir
Parallel gaa unnay bro
In the last step, will we not apply Voltage divider rule?
Cause the voltage changes in series
Just awesome 👍
how at 11:35 RL= 6 ohm??
and how is RL= 16 ohm at 11:57
please explain.
Given in question