I believe your 2nd circuit equation is incorrect per Kirchhoffs current law, the current source is flowing into the node so it should be positive and current thru R2 (Vx/20) is flowing out so it should be negative.
Thankyou very much! I am confused about what the "current source" is in the 2nd example. Could you please give an example of what the current source might be? Thanks.
@@eeapplications Yes I see that, but why is the current source different from the voltage source? Isn't the current coming from the voltage source? If not, what is producing the 2A current? Sorry for my lack of understanding.
In a current source, the current is constant and the voltage is variable. For example, when we set the current source to 1A, no matter which Resistor or load we connect, they will all draw 1A current. It does this by changing the output voltage. It ensures that the current remains constant. What is important here is my mind. If the voltage source is constant, it will draw different current when we connect different resistors.
@@bobs_ya_runkle basically it's just a challenge, hypothetical, the current is powered by itself not relying on the voltage source, think of it as a current-producing battery
You have to short circuit the voltage source so R1 and R3 will have the same potential difference with respect to their terminals. Here short circuit means you basically remove the batteries
I believe your 2nd circuit equation is incorrect per Kirchhoffs current law, the current source is flowing into the node so it should be positive and current thru R2 (Vx/20) is flowing out so it should be negative.
Incoming current is equal to outgoing current,
Inorder to write it in the rhs he wrote it in LHS
Bro this is so much easier than what I learned at university 🤣
Same
wow you explained it so easily
Such good presentation and explanation, thanks!
Thankyou very much! I am confused about what the "current source" is in the 2nd example. Could you please give an example of what the current source might be? Thanks.
In the 2nd example, the current source is the 2A source.
@@eeapplications Yes I see that, but why is the current source different from the voltage source? Isn't the current coming from the voltage source? If not, what is producing the 2A current? Sorry for my lack of understanding.
In a current source, the current is constant and the voltage is variable. For example, when we set the current source to 1A, no matter which Resistor or load we connect, they will all draw 1A current. It does this by changing the output voltage. It ensures that the current remains constant. What is important here is my mind. If the voltage source is constant, it will draw different current when we connect different resistors.
@@bobs_ya_runkle basically it's just a challenge, hypothetical, the current is powered by itself not relying on the voltage source, think of it as a current-producing battery
Quick question regarding the first example, why do we consider R1 and R3 to be in parallel rather than in series?
You have to short circuit the voltage source so R1 and R3 will have the same potential difference with respect to their terminals. Here short circuit means you basically remove the batteries
when you short circuit the voltage source these resistors are connected to the same nodes.
@@Tyler-km8uu You remove batteries but you also put wire there
2:35 why you have not use R2 9 k ohm resister when finding Vth?
Because no current flows through that resistor.
Why the current is -2 in 5:02
Excellent 👌
Thank you very much for your interest 😊
@@eeapplications You welcome
2:33 how Vth is calculated , can any one simplified that step please ?
Thank you very much for this amazing video! I have a question, can the load-RL be a capacitor or an inductor (in a DC circuit)?
Thanks ❤
I dont quite understand example 2, Vth, why not (10-Vx)/5?
can you do it with a resistent that is in paralel with V1?:(
Thank you, very interesting! could you explain the formula at 5 minutes of the video? THANKS
Thank you. I'm glad you liked the video. In that formula, we did nodal analysis to find the voltage at point Vx.
Why is it the voltage across the 20 Ohm resistor R2 4:40
thanks
Thanks a bunch
Interesting 😅
Makes sense