Norton's Theorem and Thevenin's Theorem - Electrical Circuit Analysis
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- เผยแพร่เมื่อ 20 พ.ย. 2019
- This electronics video tutorial on electrical circuit analysis provides a basic introduction into Norton's theorem and touches on Thevenin's theorem. It explains how to use Norton's theorem to calculate the current flowing through the load resistor in addition to using KVL nodal circuit analysis.
Schematic Diagrams & Symbols:
• Schematic Diagrams & S...
Resistors In Series:
• Resistors In Series - ...
Resistors In Parallel:
• Resistors In Parallel ...
Series and Parallel Circuits - Light Bulb Brightness:
• Series and Parallel Ci...
Equivalent Resistance of Complex Circuits:
• Equivalent Resistance ...
How To Solve DC Circuits:
• How To Solve Any Resis...
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Voltage Divider Circuit:
• Voltage Divider Circui...
Current Dividers:
• Current Dividers Expla...
Parallel Circuit Challenge Problem:
• Finding The Current In...
Kirchhoff's Current Law:
• Kirchhoff's Current La...
Kirchhoff's Voltage Law:
• Kirchhoff's Voltage La...
DC Circuits Review:
• Series and Parallel Ci...
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KCL and KVL Circuit Analysis:
• Kirchhoff's Law, Junct...
Thevenin's Theorem - Circuit Analysis:
• Thevenin's Theorem - C...
Superposition Theorem:
• Superposition Theorem
Maximum Power Transfer:
• Maximum Power Transfer...
Physics PDF Worksheets:
www.video-tutor.net/physics-b...
Final Exams and Video Playlists: www.video-tutor.net/
Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections
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4:10 why did we substitute Vc from 100? Help pls and why voltage at point B is 0?
As they say "A good YT video is worth a thousand lectures". Thanks man!!!
The last part where you went backwards, I was mind blown. You know your ohms law very well.
I cant believe ive been watching this guy for 5 years now already, all the way from school to engineering at uni now.
Well done sir! That is one of the best demonstration I have seen for a long time. Good use of visual and audible techniques. As a kinaesthetic learner I was able to combine what you drew on the board with your voice description. As an old engineer of 56 this took me way back to a 16 year old who was t that interested in T+N and just wanted to build exciting projects instead…. Anyway you explained it so well I actually remembered the theory and I think I would say I learnt some very useful theory. Thanks again
that reverse proving made me understand better, teaching is a GOD given talent. Thanks!
I appreciate your work! It's very intuitive-- the way you often use voltage. It may be good for folks to know how to find "I Norton" without the use of Thevenin. This circuit is actually much easier if you go about shorting points A and B (since it removes a 3 ohm resistor), doing Source Transformation on the voltage source, and adding the current sources via the Superposition Principle. I ended up with a current source of 19.5 A running through two resistors in parallel. Current division yielded "I Norton."
Anyway, thanks for your work!
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Correct me?:
You do not need (Vc-0)/6. It's just the total voltage Vc across both resistors to B, Vc/6.
How you said it confused me.
It's been years.
For me, what would have helped me
understand quicker, if you'd said, "Total" current of I1, plus "total" current of I2...I lost that back in time somewhere.
We all learn and obsess (lol) differently !
Thanks again! Made the gray cells exercise again !! Broke out my pencil and paper and eraser !
Good format. Liked how your computer graphics worked. Good calm voice. And your math gymnastics. I love to see how other people learned. You taught me to see several of the formulas differently than I was taught.
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4:10 why did we substitute Vc from 100? Help pls
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Beautifully explained. Thanks
Thevenin? More like “Thanks for filling us in!” Your videos are just the best; keep up the great work.
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Very clear and useful.Thank you!
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Good stuff man, quite literally 10 times as fast, and much more concise than my prof
We’re did he get RL
@@michaelloguemichael85 load resistor was given
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Thanks for the video, man!! Helped a lot
How come at 2:00 the resistors are in parallel, but in 4:20 they are in series? I am just a little confused since they seem to be exactly the same.
I have the same doubt. 😇
Same here!
same here
The resistances are in parallel at 2:00 because he was calculating the resistance, but when he started to calculate the current at 4:20 the current would be the same at both positions because at A there is no current going through so the current would just continue down to B. I3 is the same at both resistances. Another way to think about it is through KCL which states that the current that goes into a node is the same amount of current going out of a node. in this case I3= 0+I4, meaning that I3=I4 so they are both basically I3.
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in 1:53, how is the 11 ohms resistor in parrallel with the 3 ohms resistor and its an open circuit??
not that, the end of the 3ohm is touching with the start of the other 3ohm so they are in series not parallel! Unless i am wrong
Thank you so much
Thank you so much man.
Did you understand the whole process???
Great methods
Good explanation tqvm
Thank you sir 🙏
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Try Microsoft Whiteboard
Very consice video. Thanks a lot- The Organic Chemistry Tutor
at 6:58 Va should be Vc*R2/(R2+R3) not Vc*R3/(R2+R3). Here R2 and R3 are same so we would get the same answer. Thanks for your video
Actually the video is right by using R3 instead of R2.
To put it into a perspective, the amount of voltage entering R3 would be the same voltage entering the Load (RL in this case) since R3 and RL are parallel.
@@shichiya5743 nope you should watch circuit carefully. Here we are talking about R2 and R3 which are in series not in parallel, you should know the formula for the drop of voltage in series. And Rl which is load is parallel with the resultant of R2 and R3
@@deveshmeena5798I noticed the same thing and was wondering if it was a mistake from TOCT, or if I had a poor understanding, but thank you :D!
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when you are doing node analysis about node C why is it not (Vc-Va)/3. why did you do Vb instead of Va?
Might be a bit late, but since I had the same question and figured it out, I thought I would share:
He took the two 3ohm resistors in series and added them together, causing node A and node C to be identical. Then, since node B is the designated ground (therefore 0V), Vc/6k is the simplified result.
@@PigeonPulverizer Hi! when you do the calculation it yields two different solutions. (Vb-va)/3 + Va/3 = Vb/3. Not Vb/6
@@PigeonPulverizer, right! This is possible because while finding V Thevinin, he creates an open circuit between points A and B which results in the two 3 ohm resistors being in series. Happy studying!
@@keremhassoy9556,
I am not sure what you mean by this. Doing (Vb-Va)/3 would be in the incorrect current direction for this solution. Also, the calculation of (Vb-Va)/3 +Va/3 is TECHNICALLY (Vb-Va)/3 +(Va-Vb)/3; which sums to 0 since you are adding the current value across the same resistor from from both directions. Good luck!
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Why minus the potential at B at 4:15? Why not Vc-Va?
تملك صوتًا مميزًا، يبعث على الارتياح، فأنا لا أدرس بواسطة مقاطعك فقط، إنما أشحن طاقتي كذلك، شكرًا لك
Thank you
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Oh yeah, and checking the answer too ! Super! Always did that ! Great !
Thanks. What software are you using?
It's honestly probably Paint or Photoshop with a drawing tablet connected
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Question; at one point Vc was 66.8V, then at the end it was 60V. Is this because the load resistors was connected?
حسبنا الله في هندسة شبرا و في قسم اتصالات وفيا و شكرا جزيلا لصاحب الفديو
great💛
watching this the night before my test help
Why is the circuit at 1:45 in parallel but the circuit at 3:19 the 3 ohm and 3 ohm resistor are in series. Please explain!
thanks
Nice video!! Which software is used for the drawing part?
Annotations
Why on 2:00 you calculated as a parallel and on 4:24 as in series? Sorry I dont understand,to me looks the same ,beacuse you removed "Rl" ; I see only one way for current to flow.
Your videos is one of the most helpfull!You use better concept than school`s.
2 years and still no reply:( do you have the answer already by any chance? I want to know
Can someone explain how in 2:05 they are parallel they seem to be in series?
there's a node in between, they aren't directly connected
@@Hans-pt7qf but he says in 4:19 that they are in series?
how do you know which resistor is the RL? is it stated in the question already? genuinely asking :) great video btw
Just an advice for your tutoring from what i personally find confusing. Can you explain where you get point C in your nodal analysis? I understand A and B but does C come from? lets say you have different circuit with things all over the place. How you determine where are you going to put that point C ? Like whats the logical reasoning for it...
Nodal analysis deals with node voltages. So place your point C,D,E… on the essential nodes. Search essential nodes if you don’t know what they are. It’s where 3 or more branches meet.
How did you get the 24 that you used to solve the Norton's resistance ?
24 is used to get rid of the fractions, 24 is in the table of 6 and 8.
İ cant speak English but i am this is understant , teşekkürler
is it compulsory to calculate with KCL ??? can we calculate this sum in norton thm using KVL??? Plz reply....
I've got a question.... At 2:40, we're supposed to add a short circuit to 6 ohms load, right? As far as I know, we need to add a short circuit on the load, when we use Norton's theorm, and open circuit when we use Thevinin's theorm. Correct me, if I am wrong, please.
yes
@@pawanbhatt1767 so we shouldn't calculate r3 i think
Why is R3 added parallel and not serially to Rn?
How to identify the Load Resistor? Is it always the one on the far right side of the circuit or is there any other specific method to identify it? Btw, superb explanation, you are really helping me for my exam!
Load Resistor is always the resistor that you define as the output of the circuit. Usually, it is on the far right of a circuit schematic.
Usually denoted by RL
Usually its on the far right, but if the circuit is decently complex your professor should be telling you what the load resistor is anyways.
Hello, thanks for the explanation,
Please I wish to know how we came about 24 while looking for the voltage vc
bsc 24 comes in both the tables of 6and 8 so its used to make the calculation easy thats all
Why did we calculate vc?
when we calculate the value of R Norton can it be ( 3 ohm in series 3 ohm) and parallel with 8 ohm it'll lead to different answer. So is it wrong ?
excuse me sir sometime i really confuse why dont we apply KCL at the loop so we can get I1 = (100+7)/8 = 13.375 that why some time we use KCL,KVL law ?