You have helped me in literally every module for engineering. Is there no end to your intellect and your ability to carry it over better than many professors. Thank you genius
@@timothyediu1785 these first year engineering students are dumb ass hell. No disrespect to the guy (no extensive respect either) but the guy is just reading off a book (or something of that kind) he's teaching is far from being deep. The videos feel basically like chapters of a disgustingly oversimplified enginnering textbook, which im pretty sure they are. So yeah meat riding is indeed beyond belief
Well done sir! That is one of the best demonstration I have seen for a long time. Good use of visual and audible techniques. As a kinaesthetic learner I was able to combine what you drew on the board with your voice description. As an old engineer of 56 this took me way back to a 16 year old who was t that interested in T+N and just wanted to build exciting projects instead…. Anyway you explained it so well I actually remembered the theory and I think I would say I learnt some very useful theory. Thanks again
You're channel has a lot of subjects about math and science that it is very impresive. You're helping me get through this difficult road which is college and i am very thankful your channel exist you're helping peopple get through tough times and I thank you for that. Hope you're doing well and keep up the good work bro.
I appreciate your work! It's very intuitive-- the way you often use voltage. It may be good for folks to know how to find "I Norton" without the use of Thevenin. This circuit is actually much easier if you go about shorting points A and B (since it removes a 3 ohm resistor), doing Source Transformation on the voltage source, and adding the current sources via the Superposition Principle. I ended up with a current source of 19.5 A running through two resistors in parallel. Current division yielded "I Norton." Anyway, thanks for your work!
Thanks for the refresher ! ENJOYED your videos. Good teacher! Correct me?: You do not need (Vc-0)/6. It's just the total voltage Vc across both resistors to B, Vc/6. How you said it confused me. It's been years. For me, what would have helped me understand quicker, if you'd said, "Total" current of I1, plus "total" current of I2...I lost that back in time somewhere. We all learn and obsess (lol) differently ! Thanks again! Made the gray cells exercise again !! Broke out my pencil and paper and eraser ! Good format. Liked how your computer graphics worked. Good calm voice. And your math gymnastics. I love to see how other people learned. You taught me to see several of the formulas differently than I was taught. Enjoyed it !!
The resistances are in parallel at 2:00 because he was calculating the resistance, but when he started to calculate the current at 4:20 the current would be the same at both positions because at A there is no current going through so the current would just continue down to B. I3 is the same at both resistances. Another way to think about it is through KCL which states that the current that goes into a node is the same amount of current going out of a node. in this case I3= 0+I4, meaning that I3=I4 so they are both basically I3.
Actually the video is right by using R3 instead of R2. To put it into a perspective, the amount of voltage entering R3 would be the same voltage entering the Load (RL in this case) since R3 and RL are parallel.
@@shichiya5743 nope you should watch circuit carefully. Here we are talking about R2 and R3 which are in series not in parallel, you should know the formula for the drop of voltage in series. And Rl which is load is parallel with the resultant of R2 and R3
The voltage we calculated at point C, was 66.857V (5:55) but when we substitute the values and check it again we get 60V (10:51). Why is that? Please answer before OpenAI releases GPT-4 for free. BTW congrats on 6M subs, well deserved🎉🎉
Might be a bit late, but since I had the same question and figured it out, I thought I would share: He took the two 3ohm resistors in series and added them together, causing node A and node C to be identical. Then, since node B is the designated ground (therefore 0V), Vc/6k is the simplified result.
@@PigeonPulverizer, right! This is possible because while finding V Thevinin, he creates an open circuit between points A and B which results in the two 3 ohm resistors being in series. Happy studying!
@@keremhassoy9556, I am not sure what you mean by this. Doing (Vb-Va)/3 would be in the incorrect current direction for this solution. Also, the calculation of (Vb-Va)/3 +Va/3 is TECHNICALLY (Vb-Va)/3 +(Va-Vb)/3; which sums to 0 since you are adding the current value across the same resistor from from both directions. Good luck!
Just an advice for your tutoring from what i personally find confusing. Can you explain where you get point C in your nodal analysis? I understand A and B but does C come from? lets say you have different circuit with things all over the place. How you determine where are you going to put that point C ? Like whats the logical reasoning for it...
Nodal analysis deals with node voltages. So place your point C,D,E… on the essential nodes. Search essential nodes if you don’t know what they are. It’s where 3 or more branches meet.
Why on 2:00 you calculated as a parallel and on 4:24 as in series? Sorry I dont understand,to me looks the same ,beacuse you removed "Rl" ; I see only one way for current to flow. Your videos is one of the most helpfull!You use better concept than school`s.
I've got a question.... At 2:40, we're supposed to add a short circuit to 6 ohms load, right? As far as I know, we need to add a short circuit on the load, when we use Norton's theorm, and open circuit when we use Thevinin's theorm. Correct me, if I am wrong, please.
Hi thanks the beautiful explanation. I remembered my university days... By the way, what app or software do u use to show all the working?? I am a high school maths and physics teacher and this would be handy for preparing videos too. Hope u can help.
nice, or to get straight to norton current, shorten the load and that short loop would turn into In or norton current plus it would also open the parallel resistances. then do a nodal to get the voltage then use ohm's law with In.
You didn't really explain why you put point C where you did at 2:58. I have now no idea how to apply this to a larger or even just different circuit because you just went through without explaining your reasoning.
at 1:56 you say the 3 ohm resistor is in parallel with the resistance to the left. But at 4:20, you say the 3 ohm resistor is in series with the resistors to the left. I am confused. Can you explain this? Perhaps an analogy would help here? Thanks!
i guess the 1:56 one is the ckt which detached the current source and the power source that why the node share is different. you need to look at the node and process of the method. one of the step is detached the current source and power to get he total resistancn.
.One easy way to find if the resistances are in series or in parallel is to see if the current is dividing from a point or not. if the current is dividing the resistances are in parallel. if the same current is flowing through without dividing the the are in parallel. . in the first case when he was calculation R(th) /R(N), the load was detached and the norm is to look at the ckt from the direction of load (where it was before detaching) i.e. from right to left. but in the next the current was from left to right so the equivalent resistance changed. just follow the current division pattern and you will understand. hope it helps
How to identify the Load Resistor? Is it always the one on the far right side of the circuit or is there any other specific method to identify it? Btw, superb explanation, you are really helping me for my exam!
I understood every step of your calculations and circuit simplifications however I am not sure that I understanding the significance of Norton's current or Norton's resistance or Thevenin's current or Thevenin's resistance. Why are these points given special assignations? Also why is Rl the load resistor? What makes it a load resistor?
I didn't understand why the two resistors in calculating RN were considered in parallel, yet, later we considered th 5ohm and 3ohm resistors in series because there was no current flowing from A to B ..i mean isn't ist the same for the calculation of RN?
Final Exams and Video Playlists: www.video-tutor.net/
Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections
You have helped me in literally every module for engineering. Is there no end to your intellect and your ability to carry it over better than many professors. Thank you genius
the meat riding is crazy
@@timothyediu1785 these first year engineering students are dumb ass hell. No disrespect to the guy (no extensive respect either) but the guy is just reading off a book (or something of that kind) he's teaching is far from being deep. The videos feel basically like chapters of a disgustingly oversimplified enginnering textbook, which im pretty sure they are. So yeah meat riding is indeed beyond belief
@@timothyediu1785 meat riding isnt the same as being grateful you'd know it if your parrents educated you better instead of beating you.
@@timothyediu1785please shut up.
@@timothyediu1785 shut up lil bro
Since Calc 1, I've been constantly watching your videos due to the simplicity and clearness. Now circuits? Thank you so much for your help
same
He's a legend. I love that he's covered so many subjects.
@@legoman2m98 poop pjdxaya
th-cam.com/video/ewGoVYboigw/w-d-xo.html
Use this link and for more Electric circuit related numericals.
4:10 why did we substitute Vc from 100? Help pls and why voltage at point B is 0?
I cant believe ive been watching this guy for 5 years now already, all the way from school to engineering at uni now.
we grow up with him
they should put your name on my diploma cause it wouldn't be there without this
Where did you school bruh?
@@luckymuli3653 shitsville where I did and learnt nothing, then I went for my masters and this man helped me speedrun my highschool and BSc 🙏
😂😂
Your Europeans are dumbards
You all learn these in bsc but we study these in high school
Ewww😂😂😂
As they say "A good YT video is worth a thousand lectures". Thanks man!!!
that reverse proving made me understand better, teaching is a GOD given talent. Thanks!
The last part where you went backwards, I was mind blown. You know your ohms law very well.
Well done sir! That is one of the best demonstration I have seen for a long time. Good use of visual and audible techniques. As a kinaesthetic learner I was able to combine what you drew on the board with your voice description. As an old engineer of 56 this took me way back to a 16 year old who was t that interested in T+N and just wanted to build exciting projects instead…. Anyway you explained it so well I actually remembered the theory and I think I would say I learnt some very useful theory. Thanks again
You're channel has a lot of subjects about math and science that it is very impresive. You're helping me get through this difficult road which is college and i am very thankful your channel exist you're helping peopple get through tough times and I thank you for that. Hope you're doing well and keep up the good work bro.
omg u are majical. the way u explain and teach everything make all thigs get easy and simple. thanks for this bro
Thevenin? More like “Thanks for filling us in!” Your videos are just the best; keep up the great work.
You helped me alot through all engineering modules.....thank you sir ...all the way from Zimbabwe 🇿🇼
Bro got me through calc 1, then calc 2, and now helping me with circuits on my way to being a computer engineer.
I appreciate your work! It's very intuitive-- the way you often use voltage. It may be good for folks to know how to find "I Norton" without the use of Thevenin. This circuit is actually much easier if you go about shorting points A and B (since it removes a 3 ohm resistor), doing Source Transformation on the voltage source, and adding the current sources via the Superposition Principle. I ended up with a current source of 19.5 A running through two resistors in parallel. Current division yielded "I Norton."
Anyway, thanks for your work!
I really appreciate this I got an exam tomorrow been putting in a lot of effort but its been really difficult .These videos have really helped me .
You became a wizard in that last minute while doing the check - I've never seen someone check their circuit so clearly!
This man can be a professor for every subject
They say he invented ChapGpt
thank you so much!! the best explanation that i found in english/russian google
now I WILL TEACH MY STUDENTS RIGHT
Thanks for the refresher !
ENJOYED your videos.
Good teacher!
Correct me?:
You do not need (Vc-0)/6. It's just the total voltage Vc across both resistors to B, Vc/6.
How you said it confused me.
It's been years.
For me, what would have helped me
understand quicker, if you'd said, "Total" current of I1, plus "total" current of I2...I lost that back in time somewhere.
We all learn and obsess (lol) differently !
Thanks again! Made the gray cells exercise again !! Broke out my pencil and paper and eraser !
Good format. Liked how your computer graphics worked. Good calm voice. And your math gymnastics. I love to see how other people learned. You taught me to see several of the formulas differently than I was taught.
Enjoyed it !!
This is definitely a topic on my midterm tmr. As always u the goat.
Good stuff man, quite literally 10 times as fast, and much more concise than my prof
We’re did he get RL
@@michaelloguemichael85 load resistor was given
You saved me in entrance prep and you’re still saving me in engineering ✨… my exam’s at 8.30am today cuz it’s 2am rn 💀
How did u do??
Ig it's JEE ,coz I too a JEE aspirant
Thanks man!!! Such a great teacher 💯
Much love from 🇳🇬
Helped me review for an on-site interview. Thanks and cheers!
bro u are a Saviour Thanks a lot for PERFECT LECTURING
How come at 2:00 the resistors are in parallel, but in 4:20 they are in series? I am just a little confused since they seem to be exactly the same.
I have the same doubt. 😇
Same here!
same here
The resistances are in parallel at 2:00 because he was calculating the resistance, but when he started to calculate the current at 4:20 the current would be the same at both positions because at A there is no current going through so the current would just continue down to B. I3 is the same at both resistances. Another way to think about it is through KCL which states that the current that goes into a node is the same amount of current going out of a node. in this case I3= 0+I4, meaning that I3=I4 so they are both basically I3.
Thanks a lot. You are off the charts!
4:10 why did we substitute Vc from 100? Help pls
thank u bruh ,u help me a lot on my final exam,u are absolutely genius🥰
Thanks. You just saved my semester
Amazing explanation hats off to you .
And the last one verification was very satisfying 🫡
Hats off to u sir .
thank you brother a lot. we were looking for such a simple explaination
تملك صوتًا مميزًا، يبعث على الارتياح، فأنا لا أدرس بواسطة مقاطعك فقط، إنما أشحن طاقتي كذلك، شكرًا لك
Excellent tutorial video. Thanks for sharing on TH-cam. Best regards and blessings.
I like your vid and esp ur review at the end to show how everything adds up (no pun intended). It helps!
Nicely and thoroughly explained, much appreciated.
I passed my quiz because of this video thank you for the help
at 6:58 Va should be Vc*R2/(R2+R3) not Vc*R3/(R2+R3). Here R2 and R3 are same so we would get the same answer. Thanks for your video
Actually the video is right by using R3 instead of R2.
To put it into a perspective, the amount of voltage entering R3 would be the same voltage entering the Load (RL in this case) since R3 and RL are parallel.
@@shichiya5743 nope you should watch circuit carefully. Here we are talking about R2 and R3 which are in series not in parallel, you should know the formula for the drop of voltage in series. And Rl which is load is parallel with the resultant of R2 and R3
@@DdraggI noticed the same thing and was wondering if it was a mistake from TOCT, or if I had a poor understanding, but thank you :D!
Very clear and useful.Thank you!
this is a wonderful explanation, saxton hale approves
Thanks for the video, man!! Helped a lot
The voltage we calculated at point C, was 66.857V (5:55) but when we substitute the values and check it again we get 60V (10:51). Why is that? Please answer before OpenAI releases GPT-4 for free. BTW congrats on 6M subs, well deserved🎉🎉
Why minus the potential at B at 4:15? Why not Vc-Va?
Since the load resistance became a short circuit,no voltage drop at a coz there's no current flow
@@xzzy627 this is the time you are answering him. 3 years ago😂
Beautifully explained. Thanks
4:28 you said the resistors are in series but when you found the equivalent resistance you solved them in parallel
Thanks man you're a great teacher! Excellent explanation.
This is so good man.
Thanks for enlightenment
this channel is whole university😊😊😊
Doing A great job Brother. Love from Singapore
Hi... I'm Ur New Subscriber... I love watching Ur Videos.. Keep it Up..😍
How can we decide a circuit needs to be solved using the thevenin or norton theorem? Thankyou as always, for the useful and amazing videos
The organic chemistry tutor🔛🔝
Crystal clear ma man, Crystal clear
Thank you brother for sharing 🙏💞
Splain it's very clear...🤜🤛
Hope that God always bless you 🙏🙏
This bro is holding way to my Engineering degree
when you are doing node analysis about node C why is it not (Vc-Va)/3. why did you do Vb instead of Va?
Might be a bit late, but since I had the same question and figured it out, I thought I would share:
He took the two 3ohm resistors in series and added them together, causing node A and node C to be identical. Then, since node B is the designated ground (therefore 0V), Vc/6k is the simplified result.
@@PigeonPulverizer Hi! when you do the calculation it yields two different solutions. (Vb-va)/3 + Va/3 = Vb/3. Not Vb/6
@@PigeonPulverizer, right! This is possible because while finding V Thevinin, he creates an open circuit between points A and B which results in the two 3 ohm resistors being in series. Happy studying!
@@keremhassoy9556,
I am not sure what you mean by this. Doing (Vb-Va)/3 would be in the incorrect current direction for this solution. Also, the calculation of (Vb-Va)/3 +Va/3 is TECHNICALLY (Vb-Va)/3 +(Va-Vb)/3; which sums to 0 since you are adding the current value across the same resistor from from both directions. Good luck!
@@PigeonPulverizer thank you anime guy!
Very easy to understand with clarity
thanks a lot.. I like the way you were proving final answers. It made me understand well the division of current and voltage in a circuit
Thanks for the great explanation
in 1:53, how is the 11 ohms resistor in parrallel with the 3 ohms resistor and its an open circuit??
not that, the end of the 3ohm is touching with the start of the other 3ohm so they are in series not parallel! Unless i am wrong
You make everything easy.. ♥️
Nicely done.
Just an advice for your tutoring from what i personally find confusing. Can you explain where you get point C in your nodal analysis? I understand A and B but does C come from? lets say you have different circuit with things all over the place. How you determine where are you going to put that point C ? Like whats the logical reasoning for it...
Nodal analysis deals with node voltages. So place your point C,D,E… on the essential nodes. Search essential nodes if you don’t know what they are. It’s where 3 or more branches meet.
how will I know at this node I have to find Thevenin voltage?
Very consice video. Thanks a lot- The Organic Chemistry Tutor
Awesome video! Thank you!
Grateful for your existence.
Amazing content !
bro knows everything
Why on 2:00 you calculated as a parallel and on 4:24 as in series? Sorry I dont understand,to me looks the same ,beacuse you removed "Rl" ; I see only one way for current to flow.
Your videos is one of the most helpfull!You use better concept than school`s.
2 years and still no reply:( do you have the answer already by any chance? I want to know
Please I need reply please @@allyhanaffy2329
I've got a question.... At 2:40, we're supposed to add a short circuit to 6 ohms load, right? As far as I know, we need to add a short circuit on the load, when we use Norton's theorm, and open circuit when we use Thevinin's theorm. Correct me, if I am wrong, please.
yes
@@pawanbhatt1767 so we shouldn't calculate r3 i think
i need to meet you IRL to just thank you.
Hi thanks the beautiful explanation. I remembered my university days...
By the way, what app or software do u use to show all the working?? I am a high school maths and physics teacher and this would be handy for preparing videos too. Hope u can help.
Try Microsoft Whiteboard
Question; at one point Vc was 66.8V, then at the end it was 60V. Is this because the load resistors was connected?
watching this the night before my test help
Greats and its very simplified
nice, or to get straight to norton current, shorten the load and that short loop would turn into In or norton current plus it would also open the parallel resistances. then do a nodal to get the voltage then use ohm's law with In.
You are the BEST
You didn't really explain why you put point C where you did at 2:58. I have now no idea how to apply this to a larger or even just different circuit because you just went through without explaining your reasoning.
Cuz he's using a method which is its own topic. Go through his nodal analysis video
@@Fullmetal_Savi makes sense. I would have appreciated if he would have mentioned that though, and referenced the method
Can someone explain how in 2:05 they are parallel they seem to be in series?
there's a node in between, they aren't directly connected
@@HansSensei but he says in 4:19 that they are in series?
Thank you so much sir 🙏🏻
at 1:56 you say the 3 ohm resistor is in parallel with the resistance to the left. But at 4:20, you say the 3 ohm resistor is in series with the resistors to the left. I am confused. Can you explain this? Perhaps an analogy would help here? Thanks!
i guess the 1:56 one is the ckt which detached the current source and the power source that why the node share is different. you need to look at the node and process of the method. one of the step is detached the current source and power to get he total resistancn.
.One easy way to find if the resistances are in series or in parallel is to see if the current is dividing from a point or not. if the current is dividing the resistances are in parallel. if the same current is flowing through without dividing the the are in parallel. . in the first case when he was calculation R(th) /R(N), the load was detached and the norm is to look at the ckt from the direction of load (where it was before detaching) i.e. from right to left. but in the next the current was from left to right so the equivalent resistance changed.
just follow the current division pattern and you will understand. hope it helps
How to identify the Load Resistor? Is it always the one on the far right side of the circuit or is there any other specific method to identify it? Btw, superb explanation, you are really helping me for my exam!
Load Resistor is always the resistor that you define as the output of the circuit. Usually, it is on the far right of a circuit schematic.
Usually denoted by RL
Usually its on the far right, but if the circuit is decently complex your professor should be telling you what the load resistor is anyways.
note: voltage short circuit, current open circuit.
2. cal rth/zth
3.use kcl find voltage
حسبنا الله في هندسة شبرا و في قسم اتصالات وفيا و شكرا جزيلا لصاحب الفديو
This was new to me thanks
İ cant speak English but i am this is understant , teşekkürler
Why did you specifically use 24 to multiply everything to get rid of the fractions?
Get rid of the denominators and solve the equation
I legit had the same question too.. common denominator is 24.
Great video! But why not go with (R1.R2) / (R1+R2) for the parallel of 2 resistors? Makes it faster and easier.
For me plugging in (1 / (1/R2 +1/R3)) into my calculator is much faster, maybe that's why? just preference at the end of the day
How did you get the 24 that you used to solve the Norton's resistance ?
24 is used to get rid of the fractions, 24 is in the table of 6 and 8.
Oh yeah, and checking the answer too ! Super! Always did that ! Great !
Thanks. What software are you using?
It's honestly probably Paint or Photoshop with a drawing tablet connected
Thank you sir 🙏
why is this channel called organic chemistry tutor
his first videos were all about organic chemistry, and seems like he changed his mind later and went on with other topics.
He primarily likes Chemistry, he actually has a degree in Chemistry. But he has the ability to do other things.
Maybe he originally wanted to tutor chemistry, but lucky for us he changed his mind and tutors all of stem!!😂
Good explanation tqvm
how do you know which resistor is the RL? is it stated in the question already? genuinely asking :) great video btw
Thank you so much man.
Did you understand the whole process???
Y’all this is basic theorem. Try the one with dependent sources you surely like it
Great methods
I understood every step of your calculations and circuit simplifications however I am not sure that I understanding the significance of Norton's current or Norton's resistance or Thevenin's current or Thevenin's resistance. Why are these points given special assignations? Also why is Rl the load resistor? What makes it a load resistor?
I didn't understand why the two resistors in calculating RN were considered in parallel, yet, later we considered th 5ohm and 3ohm resistors in series because there was no current flowing from A to B ..i mean isn't ist the same for the calculation of RN?