I am a btech student in DTU, despite studying in such a college ,your lectr far -far better than my professor, thank you so much to having such a wonderful lecture. 🙂🙂
🎯 Key Takeaways for quick navigation: 00:25 📝 Norton's Theorem states that a linear, bi-directional two-terminal network can be replaced by an equivalent circuit consisting of a current source \(i_n\) in parallel with a resistor \(R_N\). 02:23 📝 Thevenin's equivalent resistance (\(R_{th}\)) is equal to Norton's equivalent resistance (\(R_N\)), and Thevenin's equivalent voltage (\(V_{th}\)) divided by \(i_n\) is also equal to \(R_N\). 03:11 📝 Norton's Theorem and Thevenin's Theorem are collectively known as source transformations, a crucial concept in electrical engineering. 04:06 📝 In Norton's Theorem, independent sources are turned off, but dependent sources are left as they are during the calculation of \(i_n\). 10:45 📝 Norton's Theorem allows us to replace a complex network with a current source (\(i_n\)) in parallel with a resistor (\(R_N\)), simplifying the analysis of the circuit.
at 8.11 you said that the second path also has 4 ohm ! but the second path was 2 ohm. so we should apply the KVL there to find out the current. By the way, thank you so much for this wonderful video.
After resistor 2ohm there is resistor 3ohm and 6ohm on parallel. So (3.6) /(3+6) giving u new resistor 2ohm so 2ohm +2ohm =4ohm That why the current split to 10A
@@mohamedkhettar4883 but next turn m In find krne ke liye resistance ka values fir se Kyu use Kiya jbki vo phle ek baar use Kar liya current distribution ke liye
I'm in central university of Karnataka persuing b tech in EE having prof. Who studied From renowned institutions still they r unable to deliver such a nice explanation and clearance ...I have exam tomorrow and after listening to ur class I think I will score decent marks atleast ...thank you sir ....
am a bit confused about the last part are we not finding the current across the load resistor instead it seems we found the current across the norton resistor. pliz do correct me if am wrong.
i dont understand when calculating Rn, why we should look at the circuit from the left side instead of the right side? Hope sb can explain that for me, thank you.
Sir I would request you to complete maximum power transfer theorem after Norton theorem because other theorem are not in Gate syllabus so you can complete remaining theorems slowly. Thank you.
Sir these vedios are helpful but sir these being a long time as compared to your previous vedio. Sir pls make rest vedios as fast as possible for you . THANKS TO YOU , your help and your team (neso).
Sir, I love your teaching and presentation is so good. I also want to know which "Font Face" you are using for your presentation. Because I want to use them for programming.
Why didn't you apply current divide rule in the first branch of the circuit which would have given the current in 2ohm branch as 20X4/2+4 rather than you calculated the equivalent resistance of the further circuit and divided the current equally.
I also thought so @ first, but that would be wrong as the current going to the 2ohm resistor is the sum of currents in 3ohm n 6ohm thus he used R equivalent them current divider giving 10A each
@@tsireledzogiven7642 U r ri8 but u changed the direction actually it is ... The current entering to the node between 2, 3 and 4 ohm is sum of current coming from 2ohm and 4 ohm resistors so if we solve both by current divider also we will get 80/9 which is not the answer .
When calculating Rn, you said to calculate it as viewed from the right to the left side of the circuit, but you calculated it from left to right... WHY???? Thanks
@@devilogesh8874 Because after 2ohm there is a parallel resistor connected of 6 and 3 ohm so 3.6/3+6 gives 2 ohm ,which is in series with first 2 ohm now 2+2 =4 ohm so the current gets divided equally with 4 ohm and 4 ohm.
@Sarah Miller I know that parallel circuit will have voltage divider effect but the voltage will be divided across the resistors. You need to have more knowledge about that?
@@aagfalcon3190 its easy bro. Just simplify the ckt n u will observe that the 4ohm resistor is in parallel with another 4ohm resistor. Hence the currents will be equal.
how come the current be divided equally in 4 ohm and 2 ohm resisitor? shouldn't it be 40/3 and 20/3 instead of 10 and 10. edit: okay now i get it. as 2 ohm and the effective 2 ohm are in series the current through them will be the same. so 10 A.
no bro, because its current source not a voltage source , if a current source is present then the current flowing will be equal to the value on the current source.
The ac ripple voltage is 1 V peak to peak. The dc (average) load voltage is 5 V. What is the Q-point current in the Zener diode? What is the maximum dynamic resistance allowed for the Zener diode if the output ripple is to be less than 10 mV peak to peak? Someone help me solve this
Can someone help explain why the 6ohm and 3ohms are considered Parallel to each other and not in series with each other, but the 2ohm and 6ohm aren't considered parallel nor why the 2ohm and 3ohm aren't immediately added together because they're technically in series. I'm thinking it's because of the flow of current, but nothing in my book states that.
the farthest resistors are solved first, it's just like ohm's law. By redrawing the new circuit and solving it, the 2 and 5 ohms resistor are in series and then the process goes easily. Just think of the Rn as the voltage source and we're finding the total resistance. Correct me if I'm wrong
Some of the current goes through other parts of the circuit. Norton's equivalent current only reflects the current over the load at the far right side, not the parts that are "lost" over the 4 Ohm and 6 Ohm resistors.
Studying in Top NIT...still found ur lectures far better than what our college prof delivers.... You're a saviour ✨
Hi
me too
Same Here. I'm studying in IIT and still studying from here
same here bro i study in iit but i found it to be the most helpful then attending those 2 hrs lectures
@@shrutis9881 we just go for attendance rest our class resides in youtube😆
You are doing a great service to student community 🤠
student community?
More like students only lol
@@enjigaming11 did someone asked for your opinion 🧐
@@shivamkumarsingh1444 define student community
@@enjigaming11 am I your student Or are you my teacher to ask a question
@@shivamkumarsingh1444 if you are not
Don't interfere.
I also feel like i have found best online teacher for my physics syllabus❤❤💕
The explanation is outstanding!!!!! This video helps to understand the concept in a very simple manner.
Thank You!!
Ur the only reason I am going pass my EEE exam today , thanks you
I am a btech student in DTU, despite studying in such a college ,your lectr far -far better than my professor, thank you so much to having such a wonderful lecture. 🙂🙂
I'm also a btech student but in a arya group of colleges.
😂 m bhi DTU se hun
🎯 Key Takeaways for quick navigation:
00:25 📝 Norton's Theorem states that a linear, bi-directional two-terminal network can be replaced by an equivalent circuit consisting of a current source \(i_n\) in parallel with a resistor \(R_N\).
02:23 📝 Thevenin's equivalent resistance (\(R_{th}\)) is equal to Norton's equivalent resistance (\(R_N\)), and Thevenin's equivalent voltage (\(V_{th}\)) divided by \(i_n\) is also equal to \(R_N\).
03:11 📝 Norton's Theorem and Thevenin's Theorem are collectively known as source transformations, a crucial concept in electrical engineering.
04:06 📝 In Norton's Theorem, independent sources are turned off, but dependent sources are left as they are during the calculation of \(i_n\).
10:45 📝 Norton's Theorem allows us to replace a complex network with a current source (\(i_n\)) in parallel with a resistor (\(R_N\)), simplifying the analysis of the circuit.
U are god❤
Concept explained by you are better than our college teachers. Thank You
Thank you sir very much for uploading this content...
Most underrated channel
THANK YOU SIR FOR UPLOAD ING SUCH VIDEOS THESE ARE SO HELPFUL TO US @neso academy PLEASE MAKE SUCH VIDEOS MORE
this video should have 1M views.thanks from the bottom of my heart.❤
your explanation doesn't need to repeat again best among best i have seen so far thank you for delivering such amazing videos
the current flowing through the 2 ohm resistor is 13.33 A
exactly
What an amazing teaching..excellent! I can't resist my self without giving this comment. Thank you a lot sir.
that was a nice lecture. Your way of teaching is so vivid. Thanx a lot sir for making subject easier for us.
Crystal clear explanation
Tq for uploading videos... @neso academy... Upload more videos....These videos are very helpful
superb explanation!! Thanks.
Best online teacher ever thank u
Clear cut explanation thank you sir
Very well explained by you sir :)
I had a question.
How come the first 20 amperes splits into 10A and 10A since there are 2 ohm and 4 ohm resistances exist respectively.
He reduced the resistors to two
Yes.. Otherwise use current to voltage transformation..
Really great work thanking you so much sir
at 8.11 you said that the second path also has 4 ohm ! but the second path was 2 ohm. so we should apply the KVL there to find out the current. By the way, thank you so much for this wonderful video.
After resistor 2ohm there is resistor 3ohm and 6ohm on parallel. So (3.6) /(3+6) giving u new resistor 2ohm so 2ohm +2ohm =4ohm
That why the current split to 10A
Actually I also noticed the same thing.
@@mohamedkhettar4883 but next turn m In find krne ke liye resistance ka values fir se Kyu use Kiya jbki vo phle ek baar use Kar liya current distribution ke liye
I'm in central university of Karnataka persuing b tech in EE having prof. Who studied From renowned institutions still they r unable to deliver such a nice explanation and clearance ...I have exam tomorrow and after listening to ur class I think I will score decent marks atleast ...thank you sir ....
9:26 how can we understand the parallels and series easily?
Best teacher of the decade love u sir, 💝💝💝
Studying in IIT but you lecture are far better than them
Phenomenal!
am a bit confused about the last part are we not finding the current across the load resistor instead it seems we found the current across the norton resistor. pliz do correct me if am wrong.
Thank you Sir
11:05 I think there will be total resistance in bottom while calculating the I and as these resistance are in parallel
i dont understand when calculating Rn, why we should look at the circuit from the left side instead of the right side? Hope sb can explain that for me, thank you.
sir, please complete the signals and system remaining topics. And try to do videos on control systems also.
Thank You, Sir
sir you should also give a brief lecture on linearity principle of circuits plz
Awesome sir
Thank you so much sir
9:27 there is a current source so we should make it short circuit.Correct value of Rth is 4.5 ohms
No Rth is right, i is wrong
Sir I would request you to complete maximum power transfer theorem after Norton theorem because other theorem are not in Gate syllabus so you can complete remaining theorems slowly. Thank you.
Tq for using ur simplest English 🤠
Thank you sir🤗🤗
sir please upload atleast 1 or two lecture daily so that we can complete syllabus before exam
very helpful
one of the best channel for EE. Love you man :)
Awesome 👍🏻😎
Sir these vedios are helpful but sir these being a long time as compared to your previous vedio. Sir pls make rest vedios as fast as possible for you .
THANKS TO YOU , your help
and your team (neso).
At 8:35 Why did Sir did not follow current division rule???
Please Someone Explain
Why are you keeping those resistances to calculate IN when you already calculated equivalent resistance 4 ohm out of them
Very nice sir
This video has become exactly 4 yrs old (as of writing, April 11!)
Thnk u
how is the current divided into 10A ? cant understand it sir. can someone explain ?
Boss..take love from Bangladesh
អរគុណThank❤
So if I have already found the Thevenin circuit, then I can make Nortons circuit using relationship in beginning of video? Rn = Rth, In = Vth/Rth.
At 10:55 why is I=(20/3)*6/6+5 instead R and RL are parallel and I=(20/3)6*5/6+5 ?
Please make videos on beie all topices
Im finding it hard to tell if these resistors re in series or parallel..can someone plss help me
It has diff resistors 2 ohm and 4 ohm how will current divided equally ?
Sir, I love your teaching and presentation is so good. I also want to know which "Font Face" you are using for your presentation. Because I want to use them for programming.
LOTS OF THANKS FROM STUDENT OF IIIT
Sir plz also make videos on aptitude
Sir please increase videos on Power System
Dear SIR ❤️ I HOPE YOU HAVE COMMITTED A MISTAKE IN THE SPLITTING OF CURRENT...BTW LOVE YOUR VIDEOS 🔥🔥
Why didn't you apply current divide rule in the first branch of the circuit which would have given the current in 2ohm branch as 20X4/2+4 rather than you calculated the equivalent resistance of the further circuit and divided the current equally.
I also thought so @ first, but that would be wrong as the current going to the 2ohm resistor is the sum of currents in 3ohm n 6ohm thus he used R equivalent them current divider giving 10A each
@@tsireledzogiven7642 U r ri8 but u changed the direction actually it is ... The current entering to the node between 2, 3 and 4 ohm is sum of current coming from 2ohm and 4 ohm resistors so if we solve both by current divider also we will get 80/9 which is not the answer .
sir this is a humble request
When calculating Rn, you said to calculate it as viewed from the right to the left side of the circuit, but you calculated it from left to right... WHY???? Thanks
@Sarah Miller Thanks so much for your reply. I will ponder it.
🔥🔥🔥
From one of the top IIIT still u teach better than my professor 🙏♥️
Which IIIT?
@@DivyanshGoel-xx9gb gwalior
When 20A will go it won't be divide in 10-10 A .....because there are 2-4 ohms are there .....how can it be devide in equal .....?
How will the current be divided equally for the 2-ohms and 4-ohm resistor?
I have same doubt
@@devilogesh8874 Because after 2ohm there is a parallel resistor connected of 6 and 3 ohm so 3.6/3+6 gives 2 ohm ,which is in series with first 2 ohm now 2+2 =4 ohm so the current gets divided equally with 4 ohm and 4 ohm.
@@sankethp3138 but next turn m I(n) find krne ke liye yeh resistance fir se Kyu use kiye ??
@Sarah Miller you are the one who need to search!!!
@Sarah Miller I know that parallel circuit will have voltage divider effect but the voltage will be divided across the resistors. You need to have more knowledge about that?
Sir 8:16 how u divided current in 10Aand 10A
I to got same doubt resistances offered in two branches is not same
@@aagfalcon3190 its easy bro. Just simplify the ckt n u will observe that the 4ohm resistor is in parallel with another 4ohm resistor. Hence the currents will be equal.
If you see 1st branch from source side apply kcl at two nodes
(6 ohm|| 3ohm) series with 2 ohm
@@veereshkammara9139 there was a short circuit so why should we consider 6 ohm .
how come the current be divided equally in 4 ohm and 2 ohm resisitor? shouldn't it be 40/3 and 20/3 instead of 10 and 10. edit: okay now i get it. as 2 ohm and the effective 2 ohm are in series the current through them will be the same. so 10 A.
then I n should be also 10 A right
if it 4 ohm 4 ohm shouldn't i be 20*4/4+4
no bro, because its current source not a voltage source , if a current source is present then the current flowing will be equal to the value on the current source.
8.16 y is it dividing equally
In should be 40/9, I think sir did make a mistake and interchanged 2 ohm to 4 ohm resistance in the beginning of 8:45
Me Ashutosh kumar first year student at NIT Surat still I don't get what they deliever😊
Nesx vedio post sir early
The ac ripple voltage is 1 V peak to peak. The dc (average) load voltage is 5 V. What is the Q-point current in the Zener diode? What is the maximum dynamic resistance allowed for the Zener diode if the output ripple is to be less than 10 mV peak to peak?
Someone help me solve this
Can someone help explain why the 6ohm and 3ohms are considered Parallel to each other and not in series with each other, but the 2ohm and 6ohm aren't considered parallel nor why the 2ohm and 3ohm aren't immediately added together because they're technically in series. I'm thinking it's because of the flow of current, but nothing in my book states that.
the farthest resistors are solved first, it's just like ohm's law. By redrawing the new circuit and solving it, the 2 and 5 ohms resistor are in series and then the process goes easily. Just think of the Rn as the voltage source and we're finding the total resistance. Correct me if I'm wrong
AS I GUESS 4 OHM AND 2 OHM SHOULD BE IN PARALLEL
Yea I dont know how you got 10 amps split.
Yes, its mistake. May be he didn't get attention on the value of resistor in to parts.
I have exam tomorrow that why am here
👍🏼
sir why u upload 1video only in a week it will take 2-3year to complete 1subject means not useful for us
jitna mil rha h usme khush nhi rehna
you have made a mistake while taking current will be divided in two paths that is 10 10 you said but the resistances are not same
Anyone frm NSUT here?
u should write each steps 1st
haha great
Why can't we take 20 amps directly as the Norton's equivalent current?
Some of the current goes through other parts of the circuit. Norton's equivalent current only reflects the current over the load at the far right side, not the parts that are "lost" over the 4 Ohm and 6 Ohm resistors.
resistance 4 ohm nahi hai 2 hai to qually divide nahi hoga
Assam Engineering College😂
Nice sir ......Hindi me padhao sir ... please.... because better understanding sir ..... please...
American aur dusre desh walo ko nahi samaj aayr ga
There are people from other states and countries also watching it mate.
Thank you sir
Thank you so much sir
Thanks a lot sir