Norton Equivalent vs Thevenin Equivalent

Physics Ninja compares Norton and Thevenin Equivalent Circuits. We first show how to calculate the equivalent Norton resistance and current source and then show how to find the Thevenin Voltage. At the end we include a resistive load between the open terminals and use Norton and Thevenin equivalent circuits to find the current flowing through the resistor.

[@Oxcentric]

One of my problem sheet problems was similar to this but my lecture notes didn't cover how to approach having only a current source. This video was very useful for helping me fill in the gaps in my knowledge - thanks!

[@EEDiffusionC2]

You should have used the current divider formula to obtain I2 at 16:34 : I2 = (50/(50+40))(3A). It's easier to perform.

[@veritasiumaequitasius3530]

Yes, but it's good to practice different methods to stay familiar. Also, it's better to be in the habit of using the full formula for 3 or more paths, i.e. Io = I • (1/Ro / (1/r1 + 1/r2...)) Which is expressed as conductance, so Io = I • (Go /sum of G's)

[@kelvinbyabato]

masterpiece😉

[@jamiesonz7936]

im fairly sure the thevenin and norton resistance found in this video are incorrect. short circuiting the supply leaves 0 current going through Rp, so it should not be added in series with the 2Rs. The thevenin resistance should just be 2Rs

[@theodoremercutio1600]

you are correct

[@_Say_My_Name_]

6:50 wrong maths?

[@jonk8893]

Λέανδρος Θωιδης Rp in stead of 1

[@gideonz74b]

Indeed

[@veritasiumaequitasius3530]

Fraction bar was accidentally too long when taking the reciprocal fraction. The math and concept is otherwise correct.

[@_a_las_ka]

yes, I just went to check it hahaha

[@mortenh7802]

"That's the current Ip" i'm childish