AC Thevenin Equivalent Circuit Problem
ฝัง
- เผยแพร่เมื่อ 22 ม.ค. 2016
- Get the full course at MathTutorDVD.com. In this lesson the student will learn how to calculate Thevenin Equivalent circuits in the AC Phasor domain. We will solve this problem step-by-step to build skills and discuss the theory along the way.
![เจอประจำ ตอน เปิดเทอมวันแรก [EP.29]](http://i.ytimg.com/vi/eFK-B836i60/mqdefault.jpg)
Amazing tutorial. I am a 3rd year Electrical Engineering student. Thevenin Theorem is now a very easy and old thing for me. Your tutorial is very much clear to understand for beginners and the concept you are giving here is really important.
Chuch here!
Thank you so much. i always feel that i am hard to understand how to calculate. Your clear explanation helps me a lot. I have watched a lot of videos about the sample topic but no one like you can help me to learn one thing so clear. Also, I am not a English native speaker, but your accent is easy to understand without any subtitle. Thanks a lot again.
I totally aced my test thanks to this insanely helpful video! thank you so much Sir!
Started a new computing internals course last week, and the first day of class the professor assigned homework on circuits. 95% of the class (including me) had never even heard of a circuit because it's not a prerequisite for the course, so we were completely lost. What a coincidence you just uploaded a lesson on circuits hahaha.
I am so loving your videos sir. You're such a blessing. Thank you very much.
I love your videos.. they are so much helpful not only did I learn complex numbers but also much more about my TI 89 calculator which i never had thought could be so useful.
Great video, easy to follow and very helpful. Thank you
Your a good teacher I really appreciate your work.
Dude you're back!
I wanted to say I myself have wanted to be a Electrical engineer since I was 10 and am ecstatic I came across your videos on Amazon and saw your story on your website of struggling with math and working for NASA.
Thank you for making videos .
+The Slacker Engineer You're very welcome. Thank you!
+mathtutordvd I have the same dream. o.o I dream of working for nasa as an aerospace engineering or even an astronaught, but i never finished school. After years of time off, i turned 18 and did a diploma and went to uni, struggling with maths but i'm getting through it thanks to your videos.
VT Gaming You just gotta work your ass off for it.
Engineering Truth is a good channel for career advice and tips like that
Wow !! Explained in the easiest possible way
Very clear. Very clean. Very coherent.
Thank you so so much !
Thank you so much! I really like how you made it so easy to understand it.
I am an indian.....but thnx
This is so helpful! Thank you!
Thank you so much ,, i have an exam in two days about this ,,
Mate thanks a lot your explanations are the best
Thank you my teacher
👏👏👏 you are really an engineer
this is a good video, play on 2x even better
You're the man
Sir please explain this type of problem using Casio FX 82 ms
THANK YOU :)
thank you sooooo much!!!!!
Are you a baldwin brother per chance?
Thanks brother
i love you !!!
I like this channel
thank u sir....
Do a nortons of this bro please
Is current across the short in method 2, Norton's current?
Am I right if I call the short circuit current... Norton current??
How did you get 6-j2?
Can u explain star and delta in ac
Do you have a tutorial that shows the mutual inductance?
Like, you got an inductor of j20 ohms and a mutual inductance of j5 ohms and then find thevenin circuit
Why you are using polar and rectangular form?
your many lectures are only 4 minutes. plz upload the full lectures on dc circuits.
God bless the camera person
pakcik lu memang style
nice
240 V is Vpeak or Vrms?
How did you get Zab= 3.6+j10.8 ohms?
For future reference because I was confused too: multiply the top so the top becomes 432j and then multiply the fraction by the complex conjugate and simplify
Z= 18/5 + 54/5 i
How you got Z= 6 - 2i ?
I think that you found the drop voltage on the R=36 and this is not the voltage between a and b 5:28
it is the same because its parallel with a and b
Yeahh
still no idea how you managed to get 6-j2
just use calculator it will solve for ya
@@oraoraoraoraora6959 But its fucked up anyway...
how did you get 6-2j..?
It was the division of 240 phasor 0 deg divided by 36+j12. At first glance, they cannot be divided by each other because they are in different, non-compatible notations. If you convert 240 phasor 0 deg to a complex number, it is just 240+j0, or simply 240 since the imaginary part is zero. Now that the numerator and the denominator are both complex numbers, you can divide them with no issue, which equals 6-j2.
but then how do u get j12?
You can change the numerator into complex numbers, then multiply both the numerator and denominator by the denominator conjugate, keep in mind that j^2 is equal to -1, hence you'll get 6-2j.
Lost you at 4min when you said to do the math to getI= 6-j2. Any chance you have any videos going into how you got there?
or at least explain what you mean by putting in the calc polar and rectangular numbers
Hi, I think you need to review complex numbers and how to work with them. There are 2 ways to represent a complex number. Rectangular form and polar form. You need to be able to work with both by hand and in the calculator. Please search my channel for that as I have lessons on these topics. Good luck! Jason
are you om facebook? Is there any way we can chat ?
those problem are two board long and it will take too long!!!
1:48 did he say "All of these in penises"?
"All of these impedances"
Lol, but no. "Impedances"....its like resistance but applies to AC circuits.
Tumse na ho paaega
أستاذ ممكن تتكلم عربي
Thank you my teacher
+محمود اليعرب welcome!