Ahhhhh.....I'm just going to be more truthful right now. You are the only person who has been able to explain this to me😭😭😭😭😭😭, thank you so much sir. God Bless You. Please don't stop bringing out videos like these. Thank you so much sir.
You're a great teacher. I'm new at electronics. I eventually want to make a lie detector or a device similar to the Scientology E-Meter. Can I just use a multimeter and attach 2 tin cans to it to act as an E-meter or a primitive lie dectector?
Kirchhoff’s loop rule states that if you travel against the current over a resistor, then +IR and if you travel with the current over a resistor then -IR. So im confused as to how you get the opposite at 4.20 in your video
Basicly its same thing,if u go your way E-I1R1+I3R3=0 or if u go his way E=I1R1-I3R3 he just should wrrite at end E not 0.I also use this way,if u have + of E following the direction of loop it will stay +,also if your current follow direction of loop on resistor it will be +,but u will write +E=+IR and not +E+IR
Ahhhhh.....I'm just going to be more truthful right now. You are the only person who has been able to explain this to me😭😭😭😭😭😭, thank you so much sir. God Bless You. Please don't stop bringing out videos like these. Thank you so much sir.
Thanks so much! My university professor did not explain this well at all, but with this video I now completely understand it.
Extremely well explanation sir. Thanks very much
You are most welcome
thanks mate. got ready for my test
You're a great teacher. I'm new at electronics. I eventually want to make a lie detector or a device similar to the Scientology E-Meter. Can I just use a multimeter and attach 2 tin cans to it to act as an E-meter or a primitive lie dectector?
Kirchhoff’s loop rule states that if you travel against the current over a resistor, then +IR and if you travel with the current over a resistor then -IR. So im confused as to how you get the opposite at 4.20 in your video
Yea..
I think he switched the signs...
Basicly its same thing,if u go your way E-I1R1+I3R3=0 or if u go his way E=I1R1-I3R3 he just should wrrite at end E not 0.I also use this way,if u have + of E following the direction of loop it will stay +,also if your current follow direction of loop on resistor it will be +,but u will write +E=+IR and not +E+IR
Simple and concise explanation. Thanks.
thank youu so much I finally see why those potential differences are equal ! my uni professor couldnt be more useless
Thanks! You got this!
Thank you so much
750ohm
55.5 ohm
Thanks for suggesting! It's really helpful 😁
If R3 doesnt showed/tell any kilo ohms or ohms... How to solve it?
hi. RA is my (RX) whilst my RB is my variable resistor. RC and RD are known. How would I go about calculating this?
Love you
What an explanation......
👍👍👍👍
high precision Wheatstone bridge are capable to measure the resistance between ?
When the current flow through the resistor and the current is opposing the loop direction. Shouldn't the voltage drop be positive and not negative.
Seems to help, let's see if I retain it
Ex1 Rx = 750 ohms Ex2 Rx = 55.5 ohms. Is this corrects? Perhaps you could have showed us the answers on your video😬
Boom, you’ve mastered the Wheatstone bridge! Well done.
Yeah me too
Thank you sir !
Thank you for your video explanations.
im not goot at neither physics nor english,
but you helped me both !!!! \^-^/
Thanks bro
Is it ok to arrnge the r1 r2 r3 rx randomly
No! Be careful. If it’s balanced only some ratios will balance the bridge
@@PhysicsNinja how to find the parallel equivalent resistance and capacitance
I have AB=1ohm, BC=4ohms, CD=5ohms, DA=3ohms and AD=2ohms.
Find value of current in branch AB, AD, and BD
Thanks sooo much merrr
Actual king
ex 1 x=750
ex 2 x=55.5
is it right??
Nicely done!
Thanks a lot !
8:09 for lazy people. Jump there :)
🖕🏿
15 goes into 900, 60 times. Missed a 0 in your example. Because 6 times 50 is only 300
But great video none the less.
thanx
Example 1: Rx= 75 ohms, example 2: Rx=55 ohms
Ex 1: 750 :) close enough
Exteremly Confusing
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