ฝัง
- เผยแพร่เมื่อ 10 ก.ค. 2024
- Zac Sutton of UConn HKN determines the Thevenin and Norton Equivalents of an electrical circuit.
Still don't get it? Have questions relating to this topic or others? Suggestions for other problems you'd like to see us do? Post in the comments below or email us at "questions.hkn.uconn@gmail.com" - วิทยาศาสตร์และเทคโนโลยี
Aren't the 10 and 40 ohm resistors in series, not parallel?
Nope! an easy way to see this is to look at the circuit with the sources set to zero. We can then see those two resistors share equipotentials nodes!
~andrew
No because the wire with the 20ohm and 4a above it
excellent response.
Yes, for the mesh loop, but not for outputs a and b.
@@UConnHKN I dont understand they still look in series to me :/
You explained this concept better in 12 minutes than my school in 2 hours.
This guy explained this concept better in 12 minutes than my professor did in a week. I've been going to my 8 AM lecture for weeks, listening to my thick-accented professor mumble for an hour when I could've just watched these videos...
Watching this 15 minutes before my final exam in circuit 1. THANK YOU SO MUCH
Thank you so much. I will be using this video for the rest of this semester. I really appreciate you putting this up
I would never come over this concept.untill I watched this..Thanks a lot
Wow that last part about being able to use 2 of the values to solve for the 3rd is awesome. Thank you!
Thanks Zac, your teaching is very clear! Helped a lot
Very clear and comprehensive review! Thanks for making this vid 👍🏼
i chilled tf down then i watched it for the second time ..now i understand it better ..thank you dude
Wow thanks, this really helped to explain the fundamentals as well. Great for revision. Cool way of doing videos also.
yall explained this so well, your the reason I passed EE 213 last quarter
Love these analysis things. Interesting to see how it all works out.
Thank you 4 saving me 3 hrs of revision
you make circuits a cakewalk, your awesome, keep being awesome.
Your video is rad, and you should feel rad. Thank you.
that's a really unique way to prepare a video.. very well done. Useful video aswel. Thumbs UP!
If anyone is having issues following any of these videos, your goldem ticket to understanding is to learn about the principle of superposition of linear circuits. Organicchemistry tutor did a video on this. In a nutshell, its the idea that you can sum up the current contributiins of each individual power source. Makes it so much easier and you can forget about all of this norton and thevenin equivalent stuff which is offputting
for anyone wanting it th-cam.com/video/EX52BuZxpQM/w-d-xo.html
Thanks. Needed a quick refresher for my FE exam.
Thank you so much, sir. You made it seem so easy.
Clear as day! Thanks!
Wow thank you! Awesome explanation!!
awesome video, helped a lot. I understood the concept clearly
This is great great review, thank you :)
Thank you very much! Very good video, really helped me!
First video to actually make me understand this
Thank you
I really appreciate your work :)
The product over the sum trick to find parallel eq resistance... GENIUS
Best explanation! Got myself ready for my EE finals later! Thank you!
my proffessor explained the thevenin much better. The only think we need is the logic behind what we do. Not all the calculation. And everyone do basic calculations (summing, dividing ; of course we can do these things!?) and dont tell what is the logic. I think this video is not different!
this was incredibly helpful
thanks for your generosity
what a fantastic explanation! Great video :3
Nice video! Thank you.
Thanks Sir!😊
Loop1:
60=10(i1-i2)+40i1,50i1=100,i1=2a
Loop2:
I2=4a
and then Rth=10//40=8
Vth=40*i1=80v,Isc=Vth/Rth=80/8=10A
Great insight about removing voltage & current sources by removing the effects they would generate, stop a current with an open yet eliminate a voltage with a short
Finally clicked how this all works in this video XD Thanks man
thank you for the explanation .. I understand now
hes good at writing backwards too
I think they film him writing normally then just mirror the video when editing. Would be far easier than writing it all backwards I would think haha
that's not possible.
Some people are just backwards thinkers! ha! sorry, I just couldn't....resist ha!
video is flipped sideways so we can read
It was a joke honey
Thank you so much. This helped me
Super helpful, good explanation
7:45 just made my life so much easier. Great video!
Thanks bro..
why?
Hey thanks for the video man good explanation
When solving for for Norton, when the current flows around from B and onwards, is it not possible for the current to flow upwards throw the 40 ohm resistor. All three branches have resistors?
i just got 99% on my test thanks
wow tats amazing
Amazing! Keep it up!
U SAVED MY LIFE!!!!!!
Thank you, you helped me a lot,,, I request you from Iraq
what if i put a resistor between points a and b? can i short those? (eliminating the resistor) and when i draw the norton equivalent should i draw the resistor too between points a and b?
Holy shit this actually helped me get it. Thanks a lot!
if 10 and 40 ohm resistor are in parallel than the current should be divided?
nice methode presenttion and very clear. good luck
Nicely done.
why part of 4A current after 20Ω recistor doesn't pass throught 40 Ω resistor ?
A very helpful video.
should the loop analysis of mesh 1, treat the voltage source as positive because it is going from neg to positive
Legend
very clear. thank you
Thanks a million!
To everyone wondering, it looks like he’s writing on a glass and the video is flipped horizontally, so all writings appear right and not back to front.
why was the 40 ohm resistor used in getting the thevenin voltage?
Hi Guys, not sure if you still answer questions in the comments or not, but I was wondering. Why isn't IN 14 amps(the 4 amp source plus the new i1 of 10 amps)? Doesn't KCL say that all currents must equal at a junction?
Shouldn't the 8 ohm and 80 V battery of the simplified circuit be in parallel not series? There's a difference yes?
awesome video thanks!
Thank You!
this guy teaches way better than my college professor
from Vth and Rth norton current can be easily done...just divide vth/rth i.e 80/8 =10 amps...just using source transformation...
okay im glad i wasn't the only one who thought this
so is the thevenin current congruent to northen current?
when doing the first loop, shouldn't it be -60+10(40+i1)+40i1?
Why didn't we take the 20 ohn resistor for Rth? Because no current flows through it?
very nice explanation
Very nice video thankyou
thank you, I think you've tried hard to write in an opposed way, which deserves to be respected!
So real world use age. Let’s move on to line load impedance matching, or implementing the termination resistor, same thing remember that. Great stuff keep it up.
thnx a lot .. very helpful
How did you record this video ?
To find the Norton (short circuit) current, couldn't you just short A to B in the thevenin circuit, then find the current there? 80v/8ohms = 10A
Thanks for sharing...
can we apply node analysis..?
Awesome video GG
on the thevenin why is the secound resistor not multiplied by i1-4 ?
best video man
Awesome!!
i'm still trying to figure out if he's looking at us from behind a glass wall and writing backwards on it or what. that alone is too distracting for me to pay attention to the lesson of the video....
i know right me too
Our biggest clue to what is going on is that he appears to be writing with his left hand. Since there is a ninety percent chance he is right-handed, we can assume the technology being used is flipping the original image into a mirror image, and he is in actuality writing normally, and writing with his right hand,
me too :(
It's a black reflective surface! Kinda like mirror...
It probably is backwards for the camera but it's just reversed in post
Huge respect for being able to write all that backwards
He did not, lol. It's on glass and the video is simply mirrored horizontally after filming.
Good stuff! :)
WHY DO YOU CHOOSE I1 TO SOLVE FOR THE THEVENIN`S VOLTAJE?
Awesome!
Why the 20 ohms resistor is not included tho? Shouldn't it be 20 times 4A?
thank you
He's right handed. I can't believe the comments on this video, the video is simply mirrored. This is not a difficult concept.
he is very much left handed...
Nicolas Palmeiro mirror it the other way not the way you think
If the video was mirrored he'd have to be writing backwards right handed.
Why is i2 4A? Wouldn't the 60v source create some further current through there? Like if you follow the path of the positive charge from the voltage source it first has the option of no resistance vs 10 ohms, so at least some current should go to i2. Or do voltage sources treat current sources as open circuits?
The independent voltage source will apply the same voltage regardless of the current source. Hope that makes sense.
Thank you. How about the 10 ohm resistor and 40 ohm resistor?
A big thanks
Great video! I think the part where you explain what happened to the 20 ohm resistor when doing your first Thevenin could have used a bit more explanation as to why you can ignore it. Really well done though. I like your idea of mirroring the image so you're not writing backwards. :-)
Samwhell he ignores it because it’s an open circuit and no current flows there
Why isn't the current through the 40 Ohm resistor i1 + i2 and just i1? What happened to i2?
I think because the i2 current was eliminated through the mesh analysis.
can we just simply get In by diving Vn/Rn ? which is the same answer, 10 ohms
Good one❤️
Thank you sir
Why does i2= 4A?
Is it because:
Mesh currents are made for every non inclusive loop. So there would be two non inclusive loops for this circuit. Loop 1 would contain the 20 ohm and 10 ohm resistor. Loop 2 would contain the 40 ohm and 10 ohm resistor. Because Loop 1 has only resistors in series, the current around loop 1 is a constant 4 A. (**** note: the 10 ohm resistor is in both loops)
Is my reasoning correct?
Hello!
Thanks for commenting! This isn't entirely right. A loop current can be assigned to any of the smallest closed loops in the circuit. This means loop one consists of the loop with the voltage source, 10 ohm resistor, and 40 ohm resistor. Loop 2 consists of the current source, 10 ohm resistor, and the 20 ohm resistor. The current in any element is then the sum of all the loops currents that have the element in the loop. Since the current source only exists in loops 2, the current in the current source is the same as the second loop current. THis is why the second loop current is the value of the current source.
I hope this helped!
~Andrew
because anything in series the current is the same across
hi, what if you are not given that 4A and instead just given another resistance?
In this case you would simply find the thevenin resistance the same way, just ignore the step with the current source. if you have a more targeted question we will do our best to explain it better!
~Andrew
Good video