SIMPLY SUPPORTED BEAM (VARYING CROSS-SECTION)-SLOPE, LOCATION,MAXIMUM DEFLECTION, MOMENT AREA METHOD

#CivilSAC
Solved Numerical
In this, we will learn how to find the slope at a given point. We will also find the location of maximum deflection and its value by using the moment area method.
The given beam is simply a supported beam having varying cross-sections. We will also learn how to draw the M/EI diagram for such cases in detail.
Link to other videos-
SIMPLY SUPPORTED BEAM WITH OVERHANG - SLOPE AND DEFLECTION USING MOMENT AREA METHOD | SOLVED PROBLEM
• SIMPLY SUPPORTED BEAM ...
PROPPED CANTILEVER WITH INTERNAL HINGE || SLOPE & DEFLECTION MOMENT AREA METHOD || SOLVED PROBLEM
• PROPPED CANTILEVER WIT...
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THANKS.

[@saurabhkumar8884]

Thanks sir for all doubts clearing in simple way😊

[@CivilSAC]

Thanks 😃, keep watching!

[@yavuzbulamadik4106]

Thanks a lot

[@umairahmad2418]

Thank you sir ji

[@CivilSAC]

Welcome.

[@nmkh8053]

can you tell me how you are calculating CG or x bar

[@alexklausenstock3974]

It is probably a bit late, X bar is the center of each area from the origin (x=0), so for the first segment AC it is the base width divide by 2/3 (only I think he messed it up and took the distance from the left hand side IE 1/3), For the second he has decomposed it into a square (base width /2) + a triangle (base width /3) and for each of these areas he adds the distance of the block to the left edge of the shapes to account for the fact that they are not abutted to the origin (x=0). so + AC which is 10m in this case. hope that clears things up!
If you want more examples for finding X bar you can probably look up videos that calculate the second moment of inertia for I beams and stuff.

[@vedanshgarg7938]

6:54

[@vaibhavnagare727]

Sir Te/a and Te/b is same or not at y max

[@jesusalejandroandrademeza1840]

Hi bro! I have a question, when you calculate theta_E/a, shouldn't you multiply by the centroid of it's area to get theta_a?

[@CivilSAC]

No need to multiply it by x bar.

[@ashok2681]

Why you are multipled CG distance in theta....

[@abhilashc.m378]

Bro ,how to calculate X value , everything is understand but X value 🙄 please solve that in comment box

[@CivilSAC]

The x is the distance of the assumed location where the slope of deflected shape of beam is zero.

[@aaronako5219]

So you wouldn't load the diagram on the conjugate beam

[@yogirajsinghal2502]

sir isko macauly se kaise krengey?

[@CivilSAC]

I think, it will be difficult to solve because of varying section.

[@yogirajsinghal2502]

@@CivilSAC sir we cannot do it normally just by taking a section x-x?

[@michealtayo4213]

Rb is wrong

[@CivilSAC]

Prove it, how is it wrong.