SLOPE AND DEFLECTION IN SIMPLY SUPPORTED BEAM WITH POINT LOAD BY CONJUGATE BEAM METHOD SOLVED

‪@CivilSAC‬
In this video, we will learn how to use the conjugate beam method to find the slope and deflection in a simply supported beam.
We will find the slopes at supports and deflection under the point loads.
The solution is done in a very easy manner step-by-step.
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Link to other videos -
SLOPE AND DEFLECTION IN A CANTILEVER BEAM BY CONJUGATE BEAM METHOD | POINT LOAD | VARYING SECTION
• SLOPE AND DEFLECTION I...
SLOPE, LOCATION & VALUE OF MAXIMUM DEFLECTION IN SIMPLY SUPPORTED BEAM BY DOUBLE INTEGRATION METHOD
• SLOPE, LOCATION & VALU...

[@CivilSAC]

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[@abhishekbilwal483]

Sir no words for your explanation, mind-blowing

[@CivilSAC]

Thanks a lot.

[@techrunner9640]

Easy explanation ty sir

[@CivilSAC]

Keep watching !

[@foysalahmed4466]

Thankss

[@CivilSAC]

You're welcome!

[@knightedits822]

I have questions how to send it plz tell

[@rohitgawde4217]

sir in last triangle we haven't multiplied by 2 the centroid location will be 2/3 *2. Please clarify sir

[@chongotripple36]

No actually in last triangle cg is at 1/3 from a which is 1/3×base of last triangle which is 2 ,so cg= 1/3×2 then adding distance from A 6+1/3×2

[@pepitotaloloto8685]

😂😂😂😂😂😂

[@iqraabidiqraabid9629]

190 kese Aya?

[@CivilSAC]

Just add the three values and divide the sum by 8.