SIMPLY SUPPORTED BEAM WITH OVERHANG - SLOPE AND DEFLECTION USING MOMENT AREA METHOD | SOLVED PROBLEM

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  • เผยแพร่เมื่อ 4 ต.ค. 2024
  • #CivilSAC
    This shows how to find slope and deflection in a simply supported beam with an overhang using the moment area method. The is done in a very simple way to understand and learn the procedure easily.
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ความคิดเห็น • 10

  • @CivilSAC
    @CivilSAC  3 ปีที่แล้ว +1

    Subscribe to my youtube channel for more tutorials.

  • @saqlainmustafa7443
    @saqlainmustafa7443 3 ปีที่แล้ว +2

    Masha Allah Bhai

  • @samkeloinnocent8316
    @samkeloinnocent8316 3 ปีที่แล้ว +1

    thank you so much

  • @ChrisPhord
    @ChrisPhord 6 หลายเดือนก่อน

    I tried using the vertical intercept from A to the tangent at B to calculate for the slope at B I had a different answer

  • @ggez7156
    @ggez7156 4 หลายเดือนก่อน

    Can you solve for the maximum deflection for this?

  • @steveharvey4329
    @steveharvey4329 2 ปีที่แล้ว +1

    0A /B here geometrically will be equal to 0A + 0B...and the answer will be -208.33...i found 0B by tA/B divided by 5....for 0A getting same value of yours but applying exactly same method to 0B , where i am getting 208.33 /EI...correct me if iam doing anything wrong

  • @saikatdas3296
    @saikatdas3296 ปีที่แล้ว +3

    Whole load 50kn,then how can be reaction force 75 kn😮,I think it should be 25 kn

    • @CivilSAC
      @CivilSAC  ปีที่แล้ว +1

      The net reaction is 50 kN. Please understand that one reaction is taken upward and the other downwards. If you add them with appropriate signs, it will be 50 kN. I hope this clears your doubts.

  • @ChrisPhord
    @ChrisPhord 6 หลายเดือนก่อน

    Why didn’t you use tA/B for the slope at B?