NET FORCE PRACTICE - INCLINED PLANES - Forces on Inclined Planes - 2 Dimensional Forces

NET FORCE PRACTICE- INCLINED PLANES - This tutorial is part of a series that shows how to solve for forces on inclined planes. show you how to solve for the force parallel, force perpendicular, normal force, force friction, net force and acceleration. It's an awesome problem. Try it on your own first.

[@Stressed_PhD_0831]

Thank you!!!ive got my M1 on Monday and this has helped me a lot!

[@princee8203]

this is the best i ve ever seen...

[@sciencepost]

You are welcome mike! It's not an easy topic. Good job sticking with it.

[@nathankelalukusa4520]

You are literally my hero rn and keep up with the good work cause a life saver fr

[@wesleykill33]

Thank you I got very far behind in psychics and this just saved me

[@tyrapanganiban9084]

Such a great help. thanks.

[@AizoozKWT]

You made it so simple for me! Thanks a lot.

[@sciencepost]

Thanks. Please pass it along. Best wishes in learning.

[@Highfunda]

B

[@sciencepost]

Thanks for the kind words. Please share if it was truly helpful. Keep up the studies!

[@sciencepost]

Good question. If I didn't give the coefficient of friction, I would have given the force of friction and asked you to solve for the coefficient.

[@sciencepost]

Glad to help. Keep learning amigo!

[@jxdjdjdjdkksc6198]

That was a great video!

[@masonbodle8917]

Thank you so much!

[@christianbenson6788]

Awesome video, thanks! Huge help.

[@rr7972]

Thank You So Much Helps a lot !!!!!!

[@tjabbar]

This helped me a lot
Appreciate it

[@sinigdhabiswas36]

How is the gravitational force -400 N, if the formula is Fg= (m) (a)? Wouldn't it result to 392N, if we follow this formula? Also, this video was extremely helpful; thank you for the thorough explanations.

[@austinchandler3079]

I know this is way too late for you, however to potentially help someone else, the gravitational force is not equal to ma, it's equal to mg. g being the gravitational acceleration (9.81 m/s^2). But the force is already given to us as 400 N in the problem. So really this formula just allows us the mass which we got as 40.82 and if you multiply that by g (9.81) you'll get approximately 400 N.

[@KaranSingh-nl6sp]

@@austinchandler3079 why did it become 400n to -400n

[@syednaqvi7989]

thanks for posting many helps. i want to know why we take cos for perpendicular and sin for parallel not cos for parallel and sin for perpendicular. i appreciate if you answer my rpoble. thanks.

[@richardtian]

Thanks bro, really helped a lot.

[@azharhassan9048]

I didn't understand how you calculated the friction. What is the exact meaning of giving coefficient of friction. Why'd you multiply the perpendicular forced to the coefficient of friction? How does that give the value of friction?

[@zhaji4163]

THANK YOU!!!

[@pipturbine473]

exactly same thing came in my exam and i smashed it thanks bro

[@sciencepost]

+Henry Chikelu I'm stoked to hear it, great job learning and smashing the exam.

[@ayeshasaleh8669]

So when It's left and downward It's always negative??

[@princeofrage925]

using acceleration is equal to the net force - the coefficient of friction x the normal force, you should show that the normal force is zero which is why you don't need to calculate your coefficient of friction, because in equations where the normal force is not zero its really important to not forget your coefficient of friction!

[@mikeduji]

Thanks bro huge help :)

[@Cassie120212015]

we use fx and fy for the F perpendicular and F parallel. but i understand this more than in class

[@sciencepost]

Legit. Yeah, its easy to use different symbols, but its the concept that matters. Thanks for leaving feedback, keep being awesome!

[@shvanrocky1441]

thanks budy

[@kingjptv]

sir why is the 400N of force becomes negative when you put it on force of gravity ?

[@tyrapanganiban9084]

+Jean Philippe Narido
negative sign denotes direction

[@Ninja_Drummer]

Wouldn't it be better to reverse the x axis so positive was to the left (down the ramp), so that the acceleration was a positive value at the end? Otherwise looks like decceleration?

[@jeffreyok3549]

The rent is f parallel -Ff not f parallel +F f