Pulley Physics Problem - Finding Acceleration and Tension Force
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- เผยแพร่เมื่อ 19 พ.ย. 2024
- This physics video tutorial explains how to calculate the acceleration of a pulley system with two masses with and without kinetic friction. It also discusses how determine the tension in the rope as well. The formulas and equations are all provided in the two practice problems & examples presented in this tutorial. The full version of this video also explains how to solve the pulley problem with two hanging masses as well as how to determine the direction in which the system will move. It also explains how to solve pulley problems with inclined planes.
Full 1 Hour 28 Minute Video:
/ mathsciencetutor
Direct Link to The Full Video:
bit.ly/3QdBavj
PDF Worksheet - 8 Problems:
bit.ly/3X9hAT0
Forces - Free Formula Sheet:
bit.ly/4duMv3W
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Full 1 Hour 28 Minute Video:
• Pulley Physics Problem...
Forces - Free Formula Sheet: bit.ly/4duMv3W
Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html
Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections
Full 1 Hour 28 Minute Video: www.patreon.com/MathScienceTutor
Direct Link to The Full Video: bit.ly/3QdBavj
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Wow, this solved all the confusion I had when trying to find Tension.
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Yo this is what I've been finding yesterday...how to find the acceleration
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Great video, although, my main problem in understanding was when solving for tension. When we made the tension equation, why couldn't we plug in the value at that moment itself?
when he was solving for the acceleration he used T= to make two equations to set the whole solving part up. at that point we did not know the tension, which is what he solved for later
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so then a = (m2g - T)/m2 and a = (T - Mkm1g)/m1 also work if you have tension. That's pretty cool. But because we haven't found T, we're substituting the T instead.
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(a) angle of each part of the string to the vertical
(b) Tension in each part of the string.
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By seeing just first 2mins of the video u will understand how to find acceleration
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Hi, there's something I'm confused about. When considering the rotational inertia of the pulley and doing a problem with it, it becomes apparent that each side of the rope has its own unique tension that is not equal to each other. In this case, doesn't the method to solve problems without the consideration of pulleys violate this principle? What assumptions are made in order to solve it like this? If it's the existence of the pulley itself that causes the uneven tension, what exactly is the pulley doing to the string to essentially split apart its effects?
(the assumption made, by the rope being massless, is that tension is evenly distributed in the rope)
Frictionless pulley; massless and perfectly inelastic rope
Massless pulleys to be added to the assumptions
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Sir I. from watching your video? now I have questions what was the tension in the system and what was the purpose of driving that equation?
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