NET FORCE - Inclined Planes Practice Problems

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  • เผยแพร่เมื่อ 25 พ.ย. 2024

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  • @robxnguyen
    @robxnguyen 7 ปีที่แล้ว +17

    I know that he messed up with the 9800, but imo he did a better job than my professor LOL. Nice video man.

  • @nickl.9856
    @nickl.9856 10 ปีที่แล้ว +16

    Yeah, like a couple people here have already said, he was off by 1 decimal point (he had 98,000 when he should have had 9,800); so he was almost right, just divide all his numbers by 10. :-)

  • @tashajones4299
    @tashajones4299 11 ปีที่แล้ว +3

    Static and Kinetic are types of friction. Static means that an object is stationary, or not moving. Kinetic refers to moving objects, but only if they have a constant speed. Hope this helps!

  • @noahlegge411
    @noahlegge411 8 ปีที่แล้ว +49

    9800N........ Not 98000😂

    • @deesse4531
      @deesse4531 6 ปีที่แล้ว

      I even try it to my calcu... HAHAHA

  • @Stvrfiire_
    @Stvrfiire_ 7 หลายเดือนก่อน

    Sir please keep making physic 20 videos. I’ve watched over 100 teachers on this app, but NOBODY has ever helped me so much, I’m literally gonna cry, thank you

  • @blade913
    @blade913 7 ปีที่แล้ว +1

    Thank you so much for the help...I've been having so many problems with people being unable to properly label, or keep things simple and with as little diagrams as possible. I've seen people draw up to 4 triangle on that type of diagram, and can't word anything into a comprehensible thought. I was able to grasp this, which I was sure I was just not bridging some simple piece of information, and you helped! Thanks again!

  • @Kayla-dr5hv
    @Kayla-dr5hv 10 ปีที่แล้ว +14

    Brilliant, thank you so much! Simple and easy to understand.

    • @sciencepost
      @sciencepost  10 ปีที่แล้ว +2

      Kayla de Beer Got to keep it simple. Thanks for the good vibes!

  • @Cobba7
    @Cobba7 9 ปีที่แล้ว +5

    The mg value should be a positive value... correct me if I'm wrong... and the friction value should be negative.

  • @InclinedWerld
    @InclinedWerld 11 ปีที่แล้ว +2

    I'm so happy right now.

  • @ayubjulany3824
    @ayubjulany3824 7 ปีที่แล้ว +2

    being at rest doesn't mean that the forces sum is zero. it means that the velocity is zero, not the forces. when the acceleration is zero, that means that the sum of forces is zero. right? it could be at rest, but have forces acting on it and accelerating...

  • @hornedlobster
    @hornedlobster 10 ปีที่แล้ว +2

    THANK YOU! i needed this video!

  • @sharonli3076
    @sharonli3076 9 ปีที่แล้ว +1

    Helped me a lot. Thanks!

  • @sarahgo7811
    @sarahgo7811 11 ปีที่แล้ว +10

    i hink it should be 9800??

  • @apalmer12
    @apalmer12 10 ปีที่แล้ว +1

    You're the BEST!

    • @sciencepost
      @sciencepost  10 ปีที่แล้ว

      apalmer12 You are too kind! Best wishes learning!

  • @lala-qr4mh
    @lala-qr4mh 3 ปีที่แล้ว

    Thank you so much this really really helped!!

  • @jalalahmadfarooka7543
    @jalalahmadfarooka7543 7 ปีที่แล้ว +5

    how can weight be 98000 N when w=mg makes it (1000)(9.8)=9800N

  • @RocksmithPdl
    @RocksmithPdl 8 ปีที่แล้ว +1

    Nice and clear 👍🏼

  • @guzmanxp4906
    @guzmanxp4906 7 ปีที่แล้ว

    You are the best!

  • @1ultimate100
    @1ultimate100 10 ปีที่แล้ว +17

    its wrong, 9.8 x 1000 = 9800 not -98,000 lol.

    • @vissvaalan7535
      @vissvaalan7535 10 ปีที่แล้ว

      you are wrong lol.. you gotta convert the kg to N first then multiply..

    • @phasmafortis1926
      @phasmafortis1926 10 ปีที่แล้ว +9

      ***** nope, it should be 9,800. kg times m*s^-2 equals N.

  • @KarimLaaiadiVlogs
    @KarimLaaiadiVlogs 11 ปีที่แล้ว +1

    If we need to figure out the acceleration , do we have to add up all forces or use F II or F parallel ??? thanks

  • @siddhantrahulpatil
    @siddhantrahulpatil 3 ปีที่แล้ว

    Thanks!

  • @adeosunbhimbie4105
    @adeosunbhimbie4105 8 ปีที่แล้ว +1

    thanks man

  • @suneethapurli3722
    @suneethapurli3722 10 ปีที่แล้ว +7

    Isn't 9.8 multiplied with 1000 , 9800

  • @tosonaldam-tajima1936
    @tosonaldam-tajima1936 3 ปีที่แล้ว +2

    wow all these comments are so old. i wonder where everyone is now

    • @siddhantrahulpatil
      @siddhantrahulpatil 3 ปีที่แล้ว

      Still here :) I have a test on this tomorrow, how about you?

  • @makabongwemdluli3907
    @makabongwemdluli3907 10 ปีที่แล้ว +1

    thanks a lot this video was helpful

    • @sciencepost
      @sciencepost  10 ปีที่แล้ว

      That is awesome to hear. Best wishes in learning.

  • @lesmayjacobs5468
    @lesmayjacobs5468 3 ปีที่แล้ว

    Thank you

  • @patrickmole9645
    @patrickmole9645 7 ปีที่แล้ว

    thank you sir

  • @19jewels95
    @19jewels95 9 ปีที่แล้ว +1

    THANK YOU

  • @alanzollner3381
    @alanzollner3381 5 ปีที่แล้ว

    Fg calculation aside, nice job explaining the components and friction force, but the value you found for the coefficient of static friction would only be correct if the object was just on the brink of sliding, or if you found the kinetic coefficient of friction if the object was sliding at a constant velocity. Recall that for static friction, the friction force is written as an inequality: Ff

  • @arifhakiminadnan4880
    @arifhakiminadnan4880 9 ปีที่แล้ว +1

    thanks

  • @niccatipay
    @niccatipay 10 ปีที่แล้ว +3

    Many of my brain cells died...
    Nuff said

  • @hamiltonmabep441
    @hamiltonmabep441 4 หลายเดือนก่อน

    Is it static friction?

  • @keithenaficionadobrown4853
    @keithenaficionadobrown4853 10 ปีที่แล้ว +1

    9,800×sin(15)
    =2,536.42664198

  • @Music-lv8xf
    @Music-lv8xf 11 ปีที่แล้ว

    hi sir i am confused. is friction , kinetic friction , static friction are different from each other?? if the question asking only for friction then if i have the parallel F that is equal to friction right? that is what you said but what if the question is asking for kinetic friction do i need to use the formula coefficient of kinetic friction multiply to FN?

    • @hamiltonmabep441
      @hamiltonmabep441 4 หลายเดือนก่อน

      When the object slides down I think it would experience Kinetic friction. It's resting so thus it should be static friction

  • @dlfinnan911
    @dlfinnan911 10 ปีที่แล้ว +1

    no he is right you don't convert kg to n mg is equal to mass times force of gravity....units of mass are in kg and force of gravity is in N....then you multiply them together and get 9800 NOT 98000 1000*9.8 is NOT 98000

  • @anjusaraswat9584
    @anjusaraswat9584 6 ปีที่แล้ว

    Koi bat nhi error to god sebhi ho jati hai but sir thnks

  • @snowpro5ryusmc
    @snowpro5ryusmc 9 ปีที่แล้ว +1

    OMG! It is 9,800, not 98,000!

  • @amhaaygoda7142
    @amhaaygoda7142 7 ปีที่แล้ว

    you asked for the value of fiction not for the value of coefficient of friction.

  • @treeky3
    @treeky3 11 ปีที่แล้ว

    1000*9.8=9,800

  • @huwsamuel6227
    @huwsamuel6227 11 ปีที่แล้ว

    Yep he dropped a decimal point folks , shouldn,t happen

  • @lucasondo3603
    @lucasondo3603 8 ปีที่แล้ว +1

    hey why g= - 9,8 ???? it must be g = 9,8

    • @mzain325
      @mzain325 8 ปีที่แล้ว +1

      +Lucas Ondo its minus because gravity is acting downwards.

  • @kiruuthayanan4910
    @kiruuthayanan4910 3 ปีที่แล้ว

    9810 i swear its 9.81

  • @barcorn6991
    @barcorn6991 5 ปีที่แล้ว

    I THINK IT IS 9810 N

  • @tabaicanking3701
    @tabaicanking3701 6 ปีที่แล้ว

    kkkkkkk

  • @Gorguduck
    @Gorguduck 2 ปีที่แล้ว

    The reason why he put 98000N instead of 9800 is because the 1000 is in kg, not N, to convert kg to N the 1000 must be multiplied by 10. So the calculation not shown is 1000 x 10 = 10000 x (-9.8) = -98000 N