Uniform Electric Field (2 of 9) Motion of Charged Particles Perpendicular to the Field

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  • เผยแพร่เมื่อ 23 ธ.ค. 2024

ความคิดเห็น • 118

  • @a.robberts4225
    @a.robberts4225 4 ปีที่แล้ว +19

    I'm studying at university and of all the videos I've covered, THIS... is the most professional and simplest of them all!!

    • @stepbystepscience
      @stepbystepscience  4 ปีที่แล้ว +2

      Thank you for the very nice, very positive comment. Means a lot to me!

  • @galaxywanderer4608
    @galaxywanderer4608 3 ปีที่แล้ว +2

    I have been trying to figure out a theoretical variant of this problem for like 6 hours and NOW I FINALLY KNOW HOW TO DO IT! Bless you man!

  • @hiteshsingh244
    @hiteshsingh244 4 หลายเดือนก่อน +1

    I am an Indian High School student this Explanation is remarkable. Not many people are able to explain it that perfectly and smoothly. I am very thankful.

    • @stepbystepscience
      @stepbystepscience  4 หลายเดือนก่อน

      Thank you for such a nice comment.

  • @be4913
    @be4913 2 ปีที่แล้ว +5

    Professors make this concept much more complicated than it needs to be... thank you

  • @epic-simataamushe6975
    @epic-simataamushe6975 3 ปีที่แล้ว +1

    The explanation is clear, his workings are good i have to say this is genuine.

  • @Anonymous-pe1tk
    @Anonymous-pe1tk 9 หลายเดือนก่อน +1

    These explanations are so clear and simple. Thank you sir, much appreciated!

    • @stepbystepscience
      @stepbystepscience  9 หลายเดือนก่อน

      Glad you like them, you're most welcome!

  • @joeLotfy
    @joeLotfy 2 ปีที่แล้ว +1

    My professor made it over compilicated in his slides
    But know it's much easier
    I am 1st year Computer Engineering from Egypt and happy I found this video
    Keep up the good work

    • @stepbystepscience
      @stepbystepscience  2 ปีที่แล้ว +1

      Thanks for your comment and best wishes for your studies.

  • @mjackson435
    @mjackson435 3 ปีที่แล้ว +5

    I was struggling in physics today with a very similar question. I could not thank you enough for this video! Awesome job :D

    • @stepbystepscience
      @stepbystepscience  3 ปีที่แล้ว +1

      Glad to hear the video helped! Thanks for your comment.

  • @laurence-emmanuellebedard4629
    @laurence-emmanuellebedard4629 4 ปีที่แล้ว +4

    Thank you so much for the detailed explanation! You're a savior :)

    • @stepbystepscience
      @stepbystepscience  4 ปีที่แล้ว

      You are very welcome, thanks for the great comment.

  • @mihirbose1532
    @mihirbose1532 ปีที่แล้ว +1

    I'm so glad I found this video , Thank You

  • @fifaham
    @fifaham 3 ปีที่แล้ว +1

    Amazing analysis, I have tons of questions related to Earth motion in relation to electron motion and the warbling effect of earth around the sun. This is just a mind blowing phenomenon. I was thinking about the electron speed vector at the right side of the field, and now I can sleep better.

  • @monaelyakoubi1731
    @monaelyakoubi1731 ปีที่แล้ว +1

    thank you for your effort, clear and simple

  • @madhobe
    @madhobe ปีที่แล้ว +1

    The best teacher ever

  • @tsoojbaterdene7793
    @tsoojbaterdene7793 3 ปีที่แล้ว +1

    Your videos are so helpful. Thank you so much.😊

  • @allieblount4582
    @allieblount4582 ปีที่แล้ว +1

    so helpful!! couldn't survive physics II without :)

  • @LEUPAGEPLUS123
    @LEUPAGEPLUS123 2 ปีที่แล้ว +1

    Sir, is there any condition of charge particle could leave the space between two plate that contains the electric field? Some, case charge particle couldn't leave.

    • @stepbystepscience
      @stepbystepscience  2 ปีที่แล้ว

      if the particle is moving fast enough or if the electric field is not ver strong then it could leave the space between the plates.

    • @LEUPAGEPLUS123
      @LEUPAGEPLUS123 2 ปีที่แล้ว

      @@stepbystepscience If in problem asks, Could charged particle leave the space (uniform electric field) between the plate? How could we convince, it can leave or can not leave.

  • @mary._.2859
    @mary._.2859 3 ปีที่แล้ว +2

    Thank you so much! My final is in 5 hours you helped me so much

  • @quasiqidwai6464
    @quasiqidwai6464 3 ปีที่แล้ว +2

    hey, to calculate the acceleration wouldn't we also have to take into account the effects of gravity? thank you for the video

    • @MM-lj1jl
      @MM-lj1jl 3 ปีที่แล้ว

      The effect of gravity in these cases is negligible i guess

    • @omgskip
      @omgskip 2 ปีที่แล้ว

      neglectable, normally for questions for this kind of stuff, the answers don't have to be 100 spot on, as long as they are accurate. If you use Fg in the equation, your answer won't be far off from when you solve w/o Fg, since the weight of the particle is so tiny.

  • @valent9260
    @valent9260 3 ปีที่แล้ว +1

    I'm confused where the accell equation a=qV/md come from? I usually see other use common one (v')^2=(v)^2 + 2as (well thts if the velocity were known)

    • @stepbystepscience
      @stepbystepscience  3 ปีที่แล้ว

      Starting from a = qE/m. The potential difference (voltage) across the plates is U = Ed, rearrange for E gives E = U/d and substitute into the equations acceleration equations for E....finally you have a = qU/dm...Does that help?

    • @valent9260
      @valent9260 3 ปีที่แล้ว

      @@stepbystepscience oouu thnkss i just know theres other equation U = Ed thnkss :D

  • @muss9306
    @muss9306 3 ปีที่แล้ว +1

    explained really well, thank you!

  • @ddarrsh
    @ddarrsh 4 ปีที่แล้ว +3

    Best explanation ever 👌👌

    • @stepbystepscience
      @stepbystepscience  4 ปีที่แล้ว

      Glad you think so and thanks for the comment.

  • @prakrutidas3727
    @prakrutidas3727 ปีที่แล้ว +2

    While everyone is writing they are studying this in University......I am studying this for grade 12 CBSE boards in India 🤦🙇.... Btw ,Thankyou for the well versed explanation....I am a subscriber now 😄

    • @stepbystepscience
      @stepbystepscience  ปีที่แล้ว

      Thanks for the comment and happy to have you as a subscriber!

    • @ranonymous27
      @ranonymous27 ปีที่แล้ว

      also grade 12 Boards, but not Indian curriculum

    • @sprihar.17
      @sprihar.17 11 หลายเดือนก่อน

      Studying this for the Canadian grade 12 curriculumn too you're not alone!!!

    • @jayjayvah
      @jayjayvah 9 หลายเดือนก่อน

      I did. this first term grade 11

  • @sketchonice8698
    @sketchonice8698 6 หลายเดือนก่อน +1

    Great explanation!💪

  • @raymondxu5969
    @raymondxu5969 4 ปีที่แล้ว +1

    For part B, you used the time in the x, which is d/v and got 7.2*10^-9s. Shouldn't the y time also be the same though? If I used y=1/2(at^2), I get a different number for my answer. Unless, I am falsely assuming that the x-axis is in the midpoint of the capacitor. Since I used .025m as my y.

    • @stepbystepscience
      @stepbystepscience  4 ปีที่แล้ว

      Yes, the time in the y-direction is the same as the time in the x-direction.

    • @sundare4754
      @sundare4754 4 ปีที่แล้ว

      No, y value is not 0.025m, instead 0.0137m needs to be applied in the equation, because after leaving the electric field, the electron has only travelled 0.0137m in y-direction

  • @aaronyap2477
    @aaronyap2477 4 ปีที่แล้ว +1

    how does the acceleration of an electron compared to a alpha particle?

    • @stepbystepscience
      @stepbystepscience  4 ปีที่แล้ว

      Would be much greater because it has a much lower mass.

  • @bengt-erikandersson2930
    @bengt-erikandersson2930 3 ปีที่แล้ว

    When the charge exit the plates it has increased its kinetic energy. Where dies this energy comes from?

  • @ginamarie7603
    @ginamarie7603 4 ปีที่แล้ว +1

    Thank you! Great job

  • @perumallaharishkumar3079
    @perumallaharishkumar3079 4 ปีที่แล้ว +2

    Sir... What is the force of electric field on an electron....

    • @stepbystepscience
      @stepbystepscience  4 ปีที่แล้ว

      Do you mean what is the force on an electron from the electric field? It is F = Eq.

  • @NabunyaKevinClayton
    @NabunyaKevinClayton ปีที่แล้ว +1

    This was so helpful

  • @erwinlucena4353
    @erwinlucena4353 5 ปีที่แล้ว +1

    Really helped me in our assignment

  • @mike-024
    @mike-024 ปีที่แล้ว +1

    Thank you!

  • @Baseman12
    @Baseman12 4 หลายเดือนก่อน +1

    Well explained Sir💯

  • @shalininareti102
    @shalininareti102 4 ปีที่แล้ว +1

    Thank u☺️
    U clear my doubt by just diagram 😄

  • @irsathsview
    @irsathsview 11 หลายเดือนก่อน +1

    Its very helpful ❤

  • @sarikazamanullah124
    @sarikazamanullah124 4 ปีที่แล้ว +1

    you just saved my grade

  • @vanijha1250
    @vanijha1250 3 ปีที่แล้ว +1

    Thanks a gazillion timesssss

  • @madelinemclaughlin489
    @madelinemclaughlin489 3 ปีที่แล้ว +1

    Very helpful !!

  • @matthewpotvin8194
    @matthewpotvin8194 4 ปีที่แล้ว

    Hey, man thanks for the lesson but the question I was trying to attempt gave me the initial velocity in the x-axis, the length of the plates and magnitude of the electric field. They want me to solve for the final velocity as the electron leaves the uniform field. What equations would I use in this case? Thanks

    • @ayushp7807
      @ayushp7807 3 ปีที่แล้ว

      s=ut + 1/2 at^2

  • @ethanbaldinger8358
    @ethanbaldinger8358 4 ปีที่แล้ว +1

    Very nice and clear. However, you've confused tangent with its inverse in a significant way. The *tangent* of the angle is equal to the ratio of the side lengths given. The inverse tangent is simply used in the *solution* of the equation, to solve for the angle.

  • @khanshareen7177
    @khanshareen7177 4 ปีที่แล้ว

    U really explain very well sir 😃. Thank u soo much 😊

  • @GromitThaGangsta
    @GromitThaGangsta ปีที่แล้ว +1

    ur a king 👊😎

  • @tta1390
    @tta1390 2 ปีที่แล้ว

    i'm a bit confused on the arctan part. why cant it just be regular tan theta

    • @stepbystepscience
      @stepbystepscience  2 ปีที่แล้ว

      because you need to find the angle and not the tangent of the angle

  • @merzz5085
    @merzz5085 4 ปีที่แล้ว +1

    Glad i find this

  • @shamimahmed6422
    @shamimahmed6422 4 ปีที่แล้ว +1

    Great u helped me to solve my quiz

  • @muriloaugustoferlinteixeir2691
    @muriloaugustoferlinteixeir2691 4 ปีที่แล้ว

    Thank you so much man!!!!!!

  • @zamanmehdi8357
    @zamanmehdi8357 2 ปีที่แล้ว +2

    Thanks

  • @antimatter31
    @antimatter31 2 ปีที่แล้ว +2

    Nice positive comment!

  • @izzahbintirosli1861
    @izzahbintirosli1861 4 ปีที่แล้ว

    wow this is soo good . thanks

    • @stepbystepscience
      @stepbystepscience  4 ปีที่แล้ว

      Glad you like it! And thanks a lot for commenting.

  • @Shackled
    @Shackled 4 ปีที่แล้ว

    So damn good!
    Thank you

  • @chufuonlinestudy3074
    @chufuonlinestudy3074 4 ปีที่แล้ว

    Woyooooo nice one sir,,thanks alot

  • @supergammer9691
    @supergammer9691 4 ปีที่แล้ว

    Wow.....thank you sir...

  • @suhaqq
    @suhaqq 11 หลายเดือนก่อน +1

    GOATed

  • @ayimanatedofftopic
    @ayimanatedofftopic 5 หลายเดือนก่อน +1

    nice positive comment

  • @s.s.z.3969
    @s.s.z.3969 ปีที่แล้ว +1

  • @ngjierukm-pelajar2168
    @ngjierukm-pelajar2168 2 ปีที่แล้ว

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  • @noodlesm6726
    @noodlesm6726 11 หลายเดือนก่อน

    Bart