hello, sir! what if the proton (positive charge) is at rest? what happens to its potential and kinetic energy? the work done is zero, right? your video is so helpful thank u !
Sir,i had a question.When we talk about intensity between Oppositely charge parallel plates we say that it is independent of distance/r.But from the same oppositely charged plates we derive E=-potential gradient and say that E is in inverse relationship with r. Confuses me.
Sorry but I do not know what you mean about the "intensity" between the charged plates....the force of attraction is dependent upon the distance between the plates.
Ok these questions can be hard to answer online this way but...I would say "electric field strength". The potential difference (V) between two charged plates is calculated as V = Ed, E is the electric field strength and d is the distance between the plates. E is therefore E = V/d, and the field strength is inversely proportional to the distance between the plates. Does that help?
When a positive charge is moved from a negative plate to a positive plate, its potential energy increased i.e delta U > 0. Because W = - delta U, W is negative. Is this right, Sir?
It has gained the potential to go back to the negative plate. Therefore yes, the potential energy has INCREASED. So why did you say W is negative? The work done by the field is negative because it has lost energy. But the work we've done to raise the potential of the particle is positive
hlw sir,i've a problem and the question is positively charged oil drop has a mass 9.79×10^-15 kg held at rest between two parallel conducting plates A and B. the potential difference between the plates is 5000V and plates B is at a potential of 0V. distance between the plates is 2.50cm. is plate A positive or negative? (please sir make a vedio on this)
What a beautiful video...short, to the point and easy to follow. Thank you!
You're welcome. Glad you enjoyed it!
Sir what formula can i apply to calculate electric potential where AB=BC
hello, sir! what if the proton (positive charge) is at rest? what happens to its potential and kinetic energy? the work done is zero, right? your video is so helpful thank u !
if the proton is at rest at the positively charged plate then it will have potential energy but no kinetic energy.
Sir,i had a question.When we talk about intensity between Oppositely charge parallel plates we say that it is independent of distance/r.But from the same oppositely charged plates we derive E=-potential gradient and say that E is in inverse relationship with r. Confuses me.
Sorry but I do not know what you mean about the "intensity" between the charged plates....the force of attraction is dependent upon the distance between the plates.
@@stepbystepscience electric field intensity
@@stepbystepscience E=sigma/episilon for oppositely charged parallel plates i.e independent of distance between plates
but from same apparatus we calculate E=del V/del distance (btwn plates)
Ok these questions can be hard to answer online this way but...I would say "electric field strength". The potential difference (V) between two charged plates is calculated as V = Ed, E is the electric field strength and d is the distance between the plates. E is therefore E = V/d, and the field strength is inversely proportional to the distance between the plates. Does that help?
I loved the way you explained it and your voice too :) You can't imagine how much i needed this, Thank you so much!
That that it helped and thanks for commenting. You can see a listing of all my videos at www.stepbystepscience.com
When a positive charge is moved from a negative plate to a positive plate, its potential energy increased i.e delta U > 0.
Because W = - delta U, W is negative. Is this right, Sir?
It has gained the potential to go back to the negative plate. Therefore yes, the potential energy has INCREASED. So why did you say W is negative? The work done by the field is negative because it has lost energy. But the work we've done to raise the potential of the particle is positive
Not just energy or potential energy but.......
ELECTRIC POTENTIAL ENERGY, kowabunga!
Step-by-Step Science Ss
Sir, what happens to the electric potential as a positive charge moves along the electric field ?
decreases
@@stepbystepscience
Thank you so much,
I appreciate your reply
hlw sir,i've a problem and the question is positively charged oil drop has a mass 9.79×10^-15 kg held at rest between two parallel conducting plates A and B. the potential difference between the plates is 5000V and plates B is at a potential of 0V. distance between the plates is 2.50cm. is plate A positive or negative? (please sir make a vedio on this)
No
why positive plate has more potential ?
thank you sir.
It is because of the positive test charge, this positive charge has more potential energy when it is near the positive plate or just by definition.
Brian Swarthout
I got it. Thank you sir.
+Md Sadiqur Rahman much force is exerted on the test charge at the positive plate than at the negative (repulsion)😊
Excellent explanation, thank you!
Glad it was helpful!
Thanks, this helped me so much!
Jo chaiye wo to bata nahi raha hai
Is that good or bad?
Step-by-Step Science
Well that was critique
nice
Thanks!
so helpful, thanks a lot
Great, glad you found it helpful.
if possible could you please do one on coulumbs torsion experiment if you have the time.
Tega Akpovbovbo sorry but at the beginning of the school I won't have time to do one.
Beautiful
wow !
Crisp & Clear