Uniform Electric Field (1 of 9 ) Motion of Charged Particles Parallel to the Field

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  • เผยแพร่เมื่อ 24 ธ.ค. 2024

ความคิดเห็น • 40

  • @Shackled
    @Shackled 4 ปีที่แล้ว +12

    Brilliant work there. Your consistent breakdown of how equations are derived is next level compared to almost everyone else I have been looking at.

  • @vincentruel9515
    @vincentruel9515 4 ปีที่แล้ว +2

    Sir, I am a graduate of BSEE, preparing for licensure exam and I just wanna say your videos are very helpful for reviewing the concepts of different subject. Thank you sir

    • @stepbystepscience
      @stepbystepscience  4 ปีที่แล้ว +1

      Glad to hear that the videos are helpful. Thanks for your comment!

  • @ferhanibrahim8822
    @ferhanibrahim8822 2 ปีที่แล้ว +2

    Very attractive and breef, my question is the charged body has also gravitational acceleration which mess up everything here. Is it neglected because it is small or to make the calculations easy?

    • @stepbystepscience
      @stepbystepscience  2 ปีที่แล้ว +1

      Yes, it is neglected to simplify the problem and also it is relatively small when compared to the acceleration from the electric field.

  • @muriloaugustoferlinteixeir2691
    @muriloaugustoferlinteixeir2691 4 ปีที่แล้ว +1

    Thank you very much man, I'm Brazilian and here I had a lot of difficulty relating the equations with their origin

  • @suhaqq
    @suhaqq 11 หลายเดือนก่อน

    why didnt you add a negative sign for the charge of the electron?

    • @stepbystepscience
      @stepbystepscience  11 หลายเดือนก่อน

      When calculating the magnitude of the force we leave the signs off of the values because the magnitude is a scalar value. We take the sign into consideration when we want to know the direction of the force/accleration/velocity etc.

  • @MohaMohamoud-r2d
    @MohaMohamoud-r2d 9 หลายเดือนก่อน +1

    what an amazing teacher thank you so much these concepts were hard for me and u made it easy u got new subscriber and also anew student thanks for ur time

    • @stepbystepscience
      @stepbystepscience  9 หลายเดือนก่อน

      Thanks for the nice comment and welcome to the channel!

  • @gunelaghakishiyeva7670
    @gunelaghakishiyeva7670 5 ปีที่แล้ว

    Hello. Thanks for the explanation. I have one question.
    Why do we consider the distance between plates when the particle moves perpendicular to the field, but we don't when it moves parallel to the field?

  • @MrWadmaths
    @MrWadmaths ปีที่แล้ว

    Does this only apply when plates are placed horizontally?

    • @stepbystepscience
      @stepbystepscience  ปีที่แล้ว

      for these problems we generally ignore the effect of gravity, therefore the orientation of the plates would not matter.

  • @s.s.z.3969
    @s.s.z.3969 ปีที่แล้ว +1

    thank you for un frying my brain (my hero)

  • @eShredz
    @eShredz 2 ปีที่แล้ว

    shouldn't U = qEd and V = Ed?

    • @stepbystepscience
      @stepbystepscience  2 ปีที่แล้ว

      U = qEd is the change in potential energy or the work done and V = Ed is the potential difference between parallel plates.

  • @fifaham
    @fifaham 3 ปีที่แล้ว +1

    Those parameters of speed and acceleration and time it takes the electron to travel are totally beyond the human physical practices, imagine the human moving at those velocities - it will convert human into energy LOL

  • @sfisosibiya4911
    @sfisosibiya4911 ปีที่แล้ว +1

    Best🔥❤️👌

  • @aanuoluwapoakinz7926
    @aanuoluwapoakinz7926 2 ปีที่แล้ว +1

    It was helpful.
    Thanks.

  • @ab-gp7uc
    @ab-gp7uc 3 ปีที่แล้ว +1

    Thank you soooooooomuch

  • @sepehryazdani5560
    @sepehryazdani5560 3 ปีที่แล้ว +1

    Thanks

  • @Rainfrieren
    @Rainfrieren ปีที่แล้ว +1

    The best🫡🫵

  • @advicemaluka1395
    @advicemaluka1395 ปีที่แล้ว

    Ok im camping here wow physics is easy😂

  • @bokool
    @bokool 4 ปีที่แล้ว

    work is not q delta U, it is just the change in potential energy.

    • @stepbystepscience
      @stepbystepscience  4 ปีที่แล้ว

      Sure.

    • @bokool
      @bokool 4 ปีที่แล้ว

      I think you should have written q delta V instead of q delta U.
      V and U are different quantities.

    • @parthivganguly6300
      @parthivganguly6300 3 ปีที่แล้ว

      @@stepbystepscience if work is equal to change in potential difference then why you took W=q delta U. Plz explain it will be great help

  • @ngjierukm-pelajar2168
    @ngjierukm-pelajar2168 2 ปีที่แล้ว

    /

  • @beinsport183
    @beinsport183 2 ปีที่แล้ว +1

    thanks