Sir, is there any condition of charge particle could leave the space between two plate that contains the electric field? Some, case charge particle couldn't leave.
Absolutely, you have to consider the trajectory of the particle and see what is the y deflection vs the x direction. Eliminate time! Your y deflection will be in terms of initial velocity, mass, charge and electric field strength.
@@PhysicsNinja @Brian Swarthout If in problem asks, Could charged particle leave the space (uniform electric field) between the plate? How could we convince, it can leave or can not leave.
Hey, man can you please upload a video regarding movement of a charged particle in Combined Electric and magnetic field when they are perpendicular to each, and thus discuss the the general equations of differential equation and path of motion, would be a great help buddy!
Ive heard in other explanation.. If both plates were (-) and the particle (+) why the sum of electric force is upward? Isnt it must be downward since the charge become neutral but then pulled by gravity so it goes down?
A charged particle is in the electric field between two horizontal metal plates connected to a battery, as shown. There is a force F on the particle due to the electric field. The separation of the plates is double. What is the new force on the particle? Sir it's answer is F/2 but can u explain why it is F/2.
@@eternallong7821 i usually don't put negative signs into the equations because they only tell me the direction of the forces or acceleration. But you know the direction just by looking at the charge on the plates.
First of all, great video! My question is if the aim is to have the charge deflected by 0.3 mm by the time it reaches the end of the plates(that are separated by 1cm), what is the amount of charge (+Q) that the molecule has to have? Would I have to change the displacement of y to be 0.03 or 0.01m-0.0003m instead of the d/2? and then of course just directly solve for q?
but there is a force in that direction that the particle is traveling to change its speed in that direction so I can't just simply use my initial velocity and length as the length is different @@PhysicsNinja
So how would I solve for time in that case? The plates are capacitors and the positive charge is going towards the negative plate by 0.3mm.@@PhysicsNinja
Hi, is there a way for me to know if a particle is going to exit the plate or hit the plate without knowing height which the particle entered the plate. In this case we know that it was d/2 but if that info wasn’t given, can I find still find a way to know if it would exit?
Calculate the amount of deflection for a given length and initial speed. Then you can know if it will hit the other plate depending on where it starts.
if you look at equation for Qmax (11:47) you see that it depends linearly with distance between the plates. Therefore is the uncertainty on d is 10%, then the uncertainty on Qmax would also be 10%. Hope this helps!
late answer but it does i got a question and they give you the mass of the charge and they want you to determine whether the electron will hit one of the plates or emerge from between the plates.
@@eternallong7821 thank you for your answer. I asked it last semester now I dont even know what's going on lol. I somehow got away with a B in that physics class. Anyway, good luck on yours.
Fg is too small because the mass of the proton is to the order or 10^-27kg. If you are going to include FG then you may as well add a series of other forces too. We usually leave out the tiny stuff
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Thanks for publishing these video. It helps alot in Engineering Physics.
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Sir, is there any condition of charge particle could leave the space between two plate that contains the electric field? Some, case charge particle couldn't leave.
Absolutely, you have to consider the trajectory of the particle and see what is the y deflection vs the x direction. Eliminate time! Your y deflection will be in terms of initial velocity, mass, charge and electric field strength.
@@PhysicsNinja @Brian Swarthout If in problem asks, Could charged particle leave the space (uniform electric field) between the plate? How could we convince, it can leave or can not leave.
Hey, man can you please upload a video regarding movement of a charged particle in Combined Electric and magnetic field when they are perpendicular to each, and thus discuss the the general equations of differential equation and path of motion, would be a great help buddy!
thanks for the video
my question is ,how do you calculate the angle at which the electron beam or the proton is deflected?
Once you know both components of velocity vx, vy, you can use some trigonometry to find the angle. Tan(theta)=vy/vx. Solve for theta.
@@PhysicsNinja Thanks Sir for your help.
Ive heard in other explanation.. If both plates were (-) and the particle (+) why the sum of electric force is upward? Isnt it must be downward since the charge become neutral but then pulled by gravity so it goes down?
What happens if its a negative particle?
A charged particle is in the electric field between two horizontal metal plates
connected to a battery, as shown. There is a force F on the particle due to the
electric field.
The separation of the plates is double. What is the new force on the particle?
Sir it's answer is F/2 but can u explain why it is F/2.
if it is a electron calculation is the same right
same calculation but the force is acting up because of the negative charge of electron.
@@PhysicsNinja and does it also mean the charge is -1.6*10^-19 instead of 1.6*10^-19. thank you
@@eternallong7821 i usually don't put negative signs into the equations because they only tell me the direction of the forces or acceleration. But you know the direction just by looking at the charge on the plates.
First of all, great video! My question is if the aim is to have the charge deflected by 0.3 mm by the time it reaches the end of the plates(that are separated by 1cm), what is the amount of charge (+Q) that the molecule has to have? Would I have to change the displacement of y to be 0.03 or 0.01m-0.0003m instead of the d/2? and then of course just directly solve for q?
Sorry for the late reply, Physics Ninja has been busy. You would have to set the displacement in the y-direction to be 0.0003 [meters].
@@PhysicsNinja Thank You!
when two objects attract each other electrically , must both of them be charged ?and when they repel each other must they be charged? can explain it
Also, if my charge is moving towards that negative plate, how can I find the time it takes to travel through the plate?
the time will only involve the x-direction velocity. t=length of plates/vx
but there is a force in that direction that the particle is traveling to change its speed in that direction so I can't just simply use my initial velocity and length as the length is different @@PhysicsNinja
Tejal Patel no you’re right, that case is different
So how would I solve for time in that case? The plates are capacitors and the positive charge is going towards the negative plate by 0.3mm.@@PhysicsNinja
Hi, is there a way for me to know if a particle is going to exit the plate or hit the plate without knowing height which the particle entered the plate. In this case we know that it was d/2 but if that info wasn’t given, can I find still find a way to know if it would exit?
Calculate the amount of deflection for a given length and initial speed. Then you can know if it will hit the other plate depending on where it starts.
thank you sir !
how does the error in the distance between plates influence results????
if you look at equation for Qmax (11:47) you see that it depends linearly with distance between the plates. Therefore is the uncertainty on d is 10%, then the uncertainty on Qmax would also be 10%. Hope this helps!
Physics Ninja if we have this law (mg=qv/d) what is your answer??
I have just one question: what about the weight of that charge? If weight counts, is it F+W-ma?
late answer but it does
i got a question and they give you the mass of the charge and they want you to determine whether the electron will hit one of the plates or emerge from
between the plates.
@@eternallong7821 thank you for your answer. I asked it last semester now I dont even know what's going on lol. I somehow got away with a B in that physics class. Anyway, good luck on yours.
@@picnicbros yeah man good luck to you two.
would a gama photon just go straight through?
Yes
@@PhysicsNinja Thank you! I had an MCAT question revolved around that
thank you.
hey man, won't it be more accurate to say Fg + qE = ma (since gravity is also acting on the proton)
Fg is too small because the mass of the proton is to the order or 10^-27kg. If you are going to include FG then you may as well add a series of other forces too. We usually leave out the tiny stuff
@@PhysicsNinja okok fair enough - i was just thinking about the millikan oil drop experiment in which it seems quite important. thank youu :)
Why dont u just use potential gradient formula
That’s like using a hammer to break open a peanut.
hello