Charged Particle between parallel plates

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  • เผยแพร่เมื่อ 24 ธ.ค. 2024

ความคิดเห็น • 51

  • @ilyassnaji3351
    @ilyassnaji3351 3 ปีที่แล้ว +4

    the best physics teacher ever
    greetings from morocco

  • @bananastickman2
    @bananastickman2 6 ปีที่แล้ว +12

    Thanks for publishing these video. It helps alot in Engineering Physics.

  • @chadchaddington7453
    @chadchaddington7453 3 ปีที่แล้ว +1

    Thank you for helping me pass my exams!

  • @ayushdubey108
    @ayushdubey108 11 หลายเดือนก่อน +4

    Raise your hand if you're a JEE Aspirants 🚩 one of the toughest exam in the world 🚩🙂

  • @LEUPAGEPLUS123
    @LEUPAGEPLUS123 2 ปีที่แล้ว +1

    Sir, is there any condition of charge particle could leave the space between two plate that contains the electric field? Some, case charge particle couldn't leave.

    • @PhysicsNinja
      @PhysicsNinja  2 ปีที่แล้ว

      Absolutely, you have to consider the trajectory of the particle and see what is the y deflection vs the x direction. Eliminate time! Your y deflection will be in terms of initial velocity, mass, charge and electric field strength.

    • @LEUPAGEPLUS123
      @LEUPAGEPLUS123 2 ปีที่แล้ว

      @@PhysicsNinja @Brian Swarthout If in problem asks, Could charged particle leave the space (uniform electric field) between the plate? How could we convince, it can leave or can not leave.

  • @amiyancandol4499
    @amiyancandol4499 4 ปีที่แล้ว +3

    Hey, man can you please upload a video regarding movement of a charged particle in Combined Electric and magnetic field when they are perpendicular to each, and thus discuss the the general equations of differential equation and path of motion, would be a great help buddy!

  • @JudgePOWERLAB
    @JudgePOWERLAB 4 ปีที่แล้ว +1

    thanks for the video
    my question is ,how do you calculate the angle at which the electron beam or the proton is deflected?

    • @PhysicsNinja
      @PhysicsNinja  4 ปีที่แล้ว +2

      Once you know both components of velocity vx, vy, you can use some trigonometry to find the angle. Tan(theta)=vy/vx. Solve for theta.

    • @JudgePOWERLAB
      @JudgePOWERLAB 4 ปีที่แล้ว +1

      @@PhysicsNinja Thanks Sir for your help.

  • @valent9260
    @valent9260 3 ปีที่แล้ว

    Ive heard in other explanation.. If both plates were (-) and the particle (+) why the sum of electric force is upward? Isnt it must be downward since the charge become neutral but then pulled by gravity so it goes down?

  • @shairamaliha5495
    @shairamaliha5495 ปีที่แล้ว

    What happens if its a negative particle?

  • @saminakhan8000
    @saminakhan8000 2 ปีที่แล้ว

    A charged particle is in the electric field between two horizontal metal plates
    connected to a battery, as shown. There is a force F on the particle due to the
    electric field.
    The separation of the plates is double. What is the new force on the particle?
    Sir it's answer is F/2 but can u explain why it is F/2.

  • @eternallong7821
    @eternallong7821 3 ปีที่แล้ว +1

    if it is a electron calculation is the same right

    • @PhysicsNinja
      @PhysicsNinja  3 ปีที่แล้ว +1

      same calculation but the force is acting up because of the negative charge of electron.

    • @eternallong7821
      @eternallong7821 3 ปีที่แล้ว

      @@PhysicsNinja and does it also mean the charge is -1.6*10^-19 instead of 1.6*10^-19. thank you

    • @PhysicsNinja
      @PhysicsNinja  3 ปีที่แล้ว +1

      @@eternallong7821 i usually don't put negative signs into the equations because they only tell me the direction of the forces or acceleration. But you know the direction just by looking at the charge on the plates.

  • @tejalpatel9429
    @tejalpatel9429 6 ปีที่แล้ว +1

    First of all, great video! My question is if the aim is to have the charge deflected by 0.3 mm by the time it reaches the end of the plates(that are separated by 1cm), what is the amount of charge (+Q) that the molecule has to have? Would I have to change the displacement of y to be 0.03 or 0.01m-0.0003m instead of the d/2? and then of course just directly solve for q?

    • @PhysicsNinja
      @PhysicsNinja  6 ปีที่แล้ว +1

      Sorry for the late reply, Physics Ninja has been busy. You would have to set the displacement in the y-direction to be 0.0003 [meters].

    • @tejalpatel9429
      @tejalpatel9429 6 ปีที่แล้ว +1

      @@PhysicsNinja Thank You!

  • @aloshgaming9864
    @aloshgaming9864 6 ปีที่แล้ว

    when two objects attract each other electrically , must both of them be charged ?and when they repel each other must they be charged? can explain it

  • @tejalpatel9429
    @tejalpatel9429 6 ปีที่แล้ว +1

    Also, if my charge is moving towards that negative plate, how can I find the time it takes to travel through the plate?

    • @PhysicsNinja
      @PhysicsNinja  6 ปีที่แล้ว

      the time will only involve the x-direction velocity. t=length of plates/vx

    • @tejalpatel9429
      @tejalpatel9429 6 ปีที่แล้ว

      but there is a force in that direction that the particle is traveling to change its speed in that direction so I can't just simply use my initial velocity and length as the length is different @@PhysicsNinja

    • @PhysicsNinja
      @PhysicsNinja  6 ปีที่แล้ว

      Tejal Patel no you’re right, that case is different

    • @tejalpatel9429
      @tejalpatel9429 6 ปีที่แล้ว

      So how would I solve for time in that case? The plates are capacitors and the positive charge is going towards the negative plate by 0.3mm.@@PhysicsNinja

  • @petergoh5628
    @petergoh5628 3 ปีที่แล้ว

    Hi, is there a way for me to know if a particle is going to exit the plate or hit the plate without knowing height which the particle entered the plate. In this case we know that it was d/2 but if that info wasn’t given, can I find still find a way to know if it would exit?

    • @PhysicsNinja
      @PhysicsNinja  3 ปีที่แล้ว

      Calculate the amount of deflection for a given length and initial speed. Then you can know if it will hit the other plate depending on where it starts.

  • @nirbhikexplorer69
    @nirbhikexplorer69 2 ปีที่แล้ว +1

    thank you sir !

  • @aloshgaming9864
    @aloshgaming9864 6 ปีที่แล้ว

    how does the error in the distance between plates influence results????

    • @PhysicsNinja
      @PhysicsNinja  6 ปีที่แล้ว

      if you look at equation for Qmax (11:47) you see that it depends linearly with distance between the plates. Therefore is the uncertainty on d is 10%, then the uncertainty on Qmax would also be 10%. Hope this helps!

    • @aloshgaming9864
      @aloshgaming9864 6 ปีที่แล้ว

      Physics Ninja if we have this law (mg=qv/d) what is your answer??

  • @picnicbros
    @picnicbros 4 ปีที่แล้ว

    I have just one question: what about the weight of that charge? If weight counts, is it F+W-ma?

    • @eternallong7821
      @eternallong7821 3 ปีที่แล้ว

      late answer but it does
      i got a question and they give you the mass of the charge and they want you to determine whether the electron will hit one of the plates or emerge from
      between the plates.

    • @picnicbros
      @picnicbros 3 ปีที่แล้ว +2

      @@eternallong7821 thank you for your answer. I asked it last semester now I dont even know what's going on lol. I somehow got away with a B in that physics class. Anyway, good luck on yours.

    • @eternallong7821
      @eternallong7821 3 ปีที่แล้ว

      @@picnicbros yeah man good luck to you two.

  • @johngrissom1504
    @johngrissom1504 4 ปีที่แล้ว

    would a gama photon just go straight through?

    • @PhysicsNinja
      @PhysicsNinja  4 ปีที่แล้ว

      Yes

    • @johngrissom1504
      @johngrissom1504 4 ปีที่แล้ว

      @@PhysicsNinja Thank you! I had an MCAT question revolved around that

  • @sabbyxx
    @sabbyxx ปีที่แล้ว +1

    thank you.

  • @quasiqidwai6464
    @quasiqidwai6464 3 ปีที่แล้ว

    hey man, won't it be more accurate to say Fg + qE = ma (since gravity is also acting on the proton)

    • @PhysicsNinja
      @PhysicsNinja  3 ปีที่แล้ว +1

      Fg is too small because the mass of the proton is to the order or 10^-27kg. If you are going to include FG then you may as well add a series of other forces too. We usually leave out the tiny stuff

    • @quasiqidwai6464
      @quasiqidwai6464 3 ปีที่แล้ว

      @@PhysicsNinja okok fair enough - i was just thinking about the millikan oil drop experiment in which it seems quite important. thank youu :)

  • @kredziieditz4088
    @kredziieditz4088 4 ปีที่แล้ว

    Why dont u just use potential gradient formula

    • @PhysicsNinja
      @PhysicsNinja  4 ปีที่แล้ว +1

      That’s like using a hammer to break open a peanut.

  • @aloshgaming9864
    @aloshgaming9864 6 ปีที่แล้ว

    hello