Circuit Power Dissipated & Supplied Analysis Practice Problem (Electrical Engineering Basics Review)
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- เผยแพร่เมื่อ 11 ก.ย. 2024
- Solving for power dissipated and power supplied within a circuit is pretty simple to do. In this video we take a look at a circuit with a voltage supply and current supply and solve for the power supplied and consumed by each. For more videos, subscribe and check my EE playlist - bit.ly/EEReview....
Remember, P = IV = (I^2)(R).
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Hey, Just wanted to thank you,years ago i had seen your videos a night before my basic electrical engineering exam,your videos helped me clear the exam somehow. Thanks.
You explained this in a simple way and helped me understand since my professor sucks at explaining 🙏
Fantastic! Just what I was looking for, super clear explanation!
how I know that where should I assign positive n negative for that dependent currenct source?
When finding p4, why did we use i=5A ?
Because that’s a dependent current source on the voltage source, so it depends on the original I
How about the power delivered by the voltage source ?
Thank you so much for such a great video!!!!
What if the voltages in those resistors were replaces with ohms and the current dependent current source was replaced by a voltage dependent voltage source?
And also that 6 A is unknown
FANTASTIC SIR
Sir why didn't you take the sign convention for when voltage is taken into picture
Thankyou so much sir, just exactly what I was looking for
Thank you sir!🙌🏾
very well explained
hey man, I have an question for you. why did not we use 20 v for p4 instant of not using 8 v?
Because p3 and p4 are on the same node.
Dude thank you so much
Thank you, your way is too good 👍
I got the last one by adding al the previous calculated data together and adding what would make zero. Seems like it works and it's a lot easier. xD
well then people couldn't learn how to find the power dissipated by the current source in more general applications.
Thank you sir!
Thank you :)
Thank you!
i thought if the current went out the positive battery it would be positive? why is it negative?
because we are finding power dissipated, but current source is supplying power hence negative sign before that. Same is the case with voltage source
Peter C the reason why it's done like that is because if you look at the final results and add up the different powers calculated, they come out to zero, which is what we want. Means that exactly as much power is being supplied to the circuit as is being used in the circuit.
Thank you so much sir
How does a resistive circuit element consume power? Everything I've seen says electric current moves extremely slowly, like a millimeter per hour. So, it's going to take many hours for a specific electron to get from one end of the RESISTOR to the other! This "drift velocity" seems more or less constant. I always assumed current flow occurred at a high enough speed that its speed wouldn't be any kind of issue. I see a simple circuit diagram and try to realize that the electrons that make up the current flow will take centuries to move around the circuit ONE TIME! Then, too, what is a "current waveform"?
The resistive element has many more scattering centres (impurities, lattice defects, etc.) than a less resistive one. Power is lost to the resistive element via inelastic scattering of the conduction electrons with these scattering centres. Look up Drude's theory of electrical conduction in metals.
@@faizmalik9210
@@StoneShards Hi Peter! I'm not here to teach or argue with you. Sorry if I gave you that impression. It was very tempting to answer your question!
This is the first time I hear that current is conserved. I know that charge is conserved but never current. When current passes through a resistor we say ENERGY (or power to say it loosely) is comsumed, not current. My mental picture of an electric current is a rotating rubber belt driven by the car engine, the belt representing a chain of electrons and the current the rotation of the belt. Power is extracted from the belt through friction with a non rotating member. No electrons is lost due to the friction. Hope that makes sense to you.
@@faizmalik9210
Happy to engage with you too. You might care to go to my channel "Johan Arif" and watch some "tedious" videos on there on Thevenin and Norton's theorems.
thanks a lot
I can't understand why current (-0.2 A) ?
Because it flows backwards than normal.. Which is from positive to negative.. I hope i helped you
Fuck yes. Thanks for the awesome swift explanation
i thought voltage in a parallel stayed the same.
Because by KVL, the sum of the voltage in a closed loop must equal to 0 and since P3 is 8v then P4 must be 8v too
Awesome
thanks 💐💐💐
Sources supply power, whereas resistors obsorb that power
thnkx bro.......
isn't the power across a resistor found with I^2 x R ??
it's the same as 'V x I'
Great video! Thank you!
Your explanation is not clear, u should explain its details too , u r just calculating and saying it should be calculate like this u didn’t say anything about how and why it should be calculated like that. 👎🏻
Thats because he is only explaining the power not how to analyze the circuit
Red does not sound good actually