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X=3/2. Next ??

What is such result good for ?

Зачем формула? Я в уме решил

Где проверка ответов?!!!

Pos or negative 2. ANY other answer will be a convoluted mess with no use in the real world.

Logbase8de27==1,4859942891369484 Porque lo hace tan largo

If this problem has more correct answers, so you can use that way but not.

25

y^6- 2^6=0 (y^3+2^3)*(y^3-2^3)=0 y^3 + 2^3=0 (y+2)(y^2-2y+4)=0 y = -2 or y = 1/2*(2+/-(4-16)^1/2 y = 1+/-3^1/2 y^3-2^3=0 y =2 y^2+2y +4 =0 y = 1/2*(-2+/- (4-16)^1/2 y = -1 +/- 3^1/2 i

Of course 2😊

5^x*5^x= 4^x*(5^x+4^x) (5/4)^x=1+(4/5)^x y =( 4/5)^x 1/y = 1+y y^2 + y - 1=0 y = 1/2*(-1+/-(1+4)^1/2 log y = x * log 4/5

X=8 y=-9

Good, very good

It is more easy if we take 4^x =8 Because 8+8=16 only

He visto cómo se complican en matemática, pero este si que se lleva el campeonato... aquí nace la razón por la que muchos estudiantes odian la materia...

x=1

25^Log[(5/4),(1+Sqrt[5])/2]-20^ Log[(5/4),(1+Sqrt[5])/2]=16^Log[(5/4),(1+Sqrt[5])/2] x=Log[(5/4),(1+Sqrt[5])/2]= Log[1.25,0.32+0.32Sqrt[5]]+2

Either -2 or 2 . Test your answer. Prove your answer.

Logically k=2

x⁴-8x³+24x²-32x+16=x⁴ => x³-3x²+4x-2=0; x=±1,±2 => x=1 (x³-3x²+4x-2)÷(x-1)=x²-2x+2 (x-1)(x²-2x+2)=0 => x=(1, 1±i )

(x-1)(x^2-2x+2)=0 , x=1 , 1+i , 1-i ,

Devide both side by 2^x will have (X^0.5/2)^X=2^16=(16^0.5/2)^16 X=16

Sqrt[25]+Sqrt[25-9]=9 x=25

b=a^2-13 , a^4 +/- a^3 -26a^2 - a + 156 = 0 , (a+4)(a^3-4a^2-10a+39)=0 , a= -4 , a^3-4a^2-10a+39=0 , (a-3)(a^2-a-13)=0 , a= 3 , +1 +4 +1 -3 -4 -16 -1 +3 -10 -40 -13 +39=0 , +39 +156 = 0 , a^2-a-13=0 , a=(1+/-V(1+52))=2 , a=(1+/-V53)/2 , /not integer/not a solu , b=a^2-13 , solu , (a, b) = (-4 , 3 ) , ( 3 , -4) , test , (a, b) = (-4 , 3 ) , (-4)^2=b+13 , 16=3+13 , -> 16 , OK , test , (a, b) = ( 3 , -4) , 3^2= -4+13 , -> 9 , OK ,

Il y a plus simple : X^1/2 et Y^1/2 sont solutions de t^2 - 10t + 10 = 0 d'où les valeurs de Xet Y ...

X(1×2×3×4×5)=120 😂

Х=1 должен быть двукратным корнем.

1

Solving it by bending over and backwards makes your solution completely idiotic.

5

6,-4

8/3

5:26-6:40 x²-4x+4-x²=0 -4x+4=0; 4=4x => x=1 😁

13 minutos para aplicar una propiedad básica de potencia? X=6

Х/2+Х/2+Х/2=4, 3Х/2=4, Х=8/3.

What is the question?

X=0, okay?

HVALA❤

Hvala❤

There are two more solutions (x,y), because you do not consider the case x = y. (2:21) Hence solve also x² - x = 73.

Где проверка ещё с двумя корнями?

These are typically relatively challenging. Hard to imagine most people with even some mathematics knowledge not getting 3/2 right off the top of their head

Since this is cubic and no exam creator can solve cubic analytically (they would have a real job if they could) it must have a trivial root to turn it into quadratic. Then solve with delta formula as they teach in school

Решение в одно действие! А тут 😂

m should be equal to 5. 5³ -5² = 125-25=100

the powers , 1/2*4=2 , 2+2=4 , 1/2*4=2 , 1+2=3 , 1/2*3=3/2 , 3^((3/2)x )=3^4 , (3/2)x=4 , x=8/3 , test , 3^((3/2)(8/3 , ))=3^(24/6) , 3^( 24/6)=3^4 , 3^4=81 , same , OK ,

m^3-m^2=100 , we get , (x-5)(x^2+4x+20)=0 , x=5 , x^2+4x+20=0 , x=(-4+/-V(16-80))/2 , x= -2+/- 4i , test , 5^3-5^2=125-25 , --> 100 , OK ,

x,= 8 y= -9 8²-(-9) =64+9=73 (-9)² -8 ,81-8=73

x^2-x=y2-y (x-y)*(x+y-1)=0 x=y or x+y = 1 x^2 - x =73 x = 1/2(1+/- (1+292)^1/2