Japanese | Can you solve this? | Math Olympiad

[@СергейИванчиков-р8д]

Good, very good

[@MasterTMathsClass]

Thank you very much

[@bartligligen2196]

Logically k=2

[@MasterTMathsClass]

🎉

[@alfredofettuccine9425]

Using Euler’s identity, Y=2*e^niPi/3

[@MasterTMathsClass]

🎉

[@robertloveless4938]

Pos or negative 2. ANY other answer will be a convoluted mess with no use in the real world.

[@alfredofettuccine9425]

You could not be more wrong about the use of complex numbers in the real world…

[@tinkerman9525]

Either -2 or 2 . Test your answer. Prove your answer.

[@MasterTMathsClass]

👍

[@namha2487]

If this problem has more correct answers, so you can use that way but not.

[@CharlesChen-el4ot]

y^6- 2^6=0
(y^3+2^3)*(y^3-2^3)=0
y^3 + 2^3=0
(y+2)(y^2-2y+4)=0
y = -2 or
y = 1/2*(2+/-(4-16)^1/2
y = 1+/-3^1/2
y^3-2^3=0
y =2
y^2+2y +4 =0
y = 1/2*(-2+/- (4-16)^1/2
y = -1 +/- 3^1/2 i

[@MasterTMathsClass]

Nice