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Interesting 🎉
Glad you think so!
Hvala❤
You're welcome 🎉
Perdi troppo tempo per cose semplici.
Let X=√x, Y=√yRemove Y: X(10-X) = 10 > X² - 10X +10 = 0 > X = √x = 5 ± √15 > X² = x = 40 ± 5√15From symmetry, we get two solutions: x = 40 + 5√15, y = 40 - 5√15, and vice versa.
Nice
Il y a plus simple : X^1/2 et Y^1/2 sont solutions de t^2 - 10t + 10 = 0 d'où les valeurs de Xet Y ...
You are the rival of Srinivasa Ramanujan the most intelligent mathematician in India
Interesting 🎉
Glad you think so!
Hvala❤
You're welcome 🎉
Perdi troppo tempo per cose semplici.
Let X=√x, Y=√y
Remove Y: X(10-X) = 10 > X² - 10X +10 = 0 > X = √x = 5 ± √15 > X² = x = 40 ± 5√15
From symmetry, we get two solutions: x = 40 + 5√15, y = 40 - 5√15, and vice versa.
Nice
Il y a plus simple : X^1/2 et Y^1/2 sont solutions de t^2 - 10t + 10 = 0 d'où les valeurs de Xet Y ...
You are the rival of Srinivasa Ramanujan the most intelligent mathematician in India