@@reyesandrea8588 In the problem, diamater of each pin were given. Since they're in mm(millimeters), we need to convert them into meters. Then he used radius to find the area instead of diameter, so the converted diameter in meter was divided by two, because a radius is half of a diameter. You can still find the are using diameter, but you have to use a slightly different formula for it. Like, A = (pi(D)^2)/4.
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this is one of the easier examples out there
AA or AB= pi r^2?
other answer said ===> p(dia)^2/4
they're the same, both are correct
How did u get those .0125m?
The one u used for getting the area
@@reyesandrea8588 In the problem, diamater of each pin were given.
Since they're in mm(millimeters), we need to convert them into meters.
Then he used radius to find the area instead of diameter, so the converted diameter in meter was divided by two, because a radius is half of a diameter.
You can still find the are using diameter, but you have to use a slightly different formula for it. Like, A = (pi(D)^2)/4.
Don’t we have to *10^3 at 4:45