Brilliant explanations, and done without editing! Best available mechanics clips on youtube, I don't know how lecturer's in Sydney have a job after watching you. You make them look like mumbling fools. You're on the ground level of the next generation of education and I truly hope you prosper and grow in this field. Keep up the good work mate!
You are such a good teacher, I watched you as a student, I now watch you as a teacher and you hit home runs every time. Your videos are invaluable for many to fill that gap by giving the correct and detailed background of the theory.
You are most welcome. I'm glad the videos are helpful. I like to collect TH-cam hits. If you like these videos, please help me spread the word :-) - RMF
I think there are only a few videos in your channel that I haven't seen. Right now I am WAY ahead of my mechanics of solids class :D thank you so much!
Thanks! I'm studying for the FE exam and I have no experience in Mech. Eng. The study guide does not explain concepts at all! Though, in the book, they solved the problem using the Transformation of Stress Equations. I don't understand which angle to plug in for those equations. If you ever do a video on that, please let me know. Thanks!
For once we have a mechanics of solids teacher that does not make the assumption that everything will come to us naturally and goes through everything in a slow but steady manner ensuring the viewer is taking in a good amount of information. Looking forward to future videos
sir can you please give me your whats app number. I need a help of person like you, in my thesis work. please its request. waiting for your positive response.
what about if i have a bending force perpendicular to the block i have and a torque acting on the block(torisinal force stress ) so how do i calculate these stresses on an inclined plane????????
thank you so much for this video. Was wondering if you have a video showing an explanation of stresses on an inclined plane in a two-dimensional stress system.
Dear Prof. RM French, Thank you for your videos they are very helpful! Please if possible could you do a cantilever beam connected to another wall, with pin joints at a section in the beam, or a similar problem and explain what happens to a beam if you(after solving it) add another moment. Thank you in advance. Best wishes!
"please" also calculate stresses on an oblique section in a) two mutually perpendicular directions, b) subjected to simple shear stress c)subjected to direct stress in one plane and accompanied by a simple shear stress d)subjected to direct stress in two mutually perpendicular directions accompanied by a simple shear stress.
When you have an inclined plane, your axial force always have two components, therefore, unless it is 0 degrees both type of stresses are present in the element
First of all better use X- Axis and Y -Axis not N & S , for simplicity. Secondly if we consider such case , then it shall be Cos Degree on S and Sin Degree on N . Thanks
I sure did. What you can't see in the video is the light stands I had in my little office. I never really got it right, though. This video is pretty old. Check out the newest ones with the cool LED lights - way better. Thanks for watching :-)
I spent hours and hours trying to understand this, but this video has cleared it up for me in 10 minutes! Thanks!
Brilliant explanations, and done without editing!
Best available mechanics clips on youtube, I don't know how lecturer's in Sydney have a job after watching you. You make them look like mumbling fools.
You're on the ground level of the next generation of education and I truly hope you prosper and grow in this field.
Keep up the good work mate!
You're always very good at explaining things, Prof! Thanks.
The way you drew the figure in the first sight explained every thing, great job. lucid and clear. Thanks
You are such a good teacher, I watched you as a student, I now watch you as a teacher and you hit home runs every time. Your videos are invaluable for many to fill that gap by giving the correct and detailed background of the theory.
I tried many Vdos out there, but yours is the best and was able to understand the concept very clear !! Thank you very much
better explanation than any person or book gave me, thanks! I finally get it now.
i have read many articles on that topics but this was the best lecture which gave me more understanding than those articles
Beautiful explanation. Straightforward and great use of examples
The good teacher is a teacher with excellent art skill
I hope this means that my drawing was OK. I think all Engineers should take art classes :-)
Great teaching skills much better than here in India in 2022. Thank you professor.
Thanks a lot sir. Love from India ❤️🙏
You're most welcome. It's great to hear from a viewer so far from where I live :-)
If only youtube was around when I was in engineering college. These videos would surely have been very helpful!
Very nice explanation Professor. This lecture is excellent for undergraduate students.
you are a saviour my man.
Very good, clear, concise, easy to follow video. Thank you very much, its made it clear for me!
You are most welcome. I'm glad the videos are helpful. I like to collect TH-cam hits. If you like these videos, please help me spread the word :-)
- RMF
I think there are only a few videos in your channel that I haven't seen. Right now I am WAY ahead of my mechanics of solids class :D thank you so much!
GR8 ONCE AGAIN,,,,GUESS WHAT ..MY SEMESTER EXAM IS TOMORROW AND I AM LEARNING FROM UR VIDEOS...
THANK YOU SIR You reduced a one hour lecture into 10 minutes.
simple and clear explanation, I made some progress. thanks to you. :) have a great day.
dude I love you so much, my teacher for materials as sweet as she is, she is not good at explaining and I need your help
this video explanations is clear, big up
im like super dumb in strength of material but this video actually helps
Thanks, I'm glad it helped :-)
Big like from Jordan
Big thanks :-)
Thanks! I'm studying for the FE exam and I have no experience in Mech. Eng. The study guide does not explain concepts at all!
Though, in the book, they solved the problem using the Transformation of Stress Equations. I don't understand which angle to plug in for those equations. If you ever do a video on that, please let me know. Thanks!
For once we have a mechanics of solids teacher that does not make the assumption that everything will come to us naturally and goes through everything in a slow but steady manner ensuring the viewer is taking in a good amount of information. Looking forward to future videos
Thanks very much. It's great to hear that these videos have been a help to you.
RMF
Sir can you please explain me how the cross sectional area become bh devided by cosin theta
sir can you please give me your whats app number. I need a help of person like you, in my thesis work. please its request. waiting for your positive response.
thank you very much you make it vert convenient for student like me
sir u have been amazing al the time i wish our professors were qualified as u are :)
So well explanation thanks !
BEAUTIFUL!
Thank you! Great Video. Explained perfectly.
u taught it soo well!!
thank u sir!
Thank you so much sir ....
This topic is cleared😊😊
very helpfull video.... waititng for more videos
Nice explanation,Thanks.
thnq sir.... east or west u r the best....
Thanks for such excelent explanation!
Thank you professor.
Thanks for this lesson
Sir thank you for making such videos i am a die hard fan of yours.
SO helpful 🙏🏼 thanks
you are great sir....
what about if i have a bending force perpendicular to the block i have and a torque acting on the block(torisinal force stress )
so how do i calculate these stresses on an inclined plane????????
Awesome video,thanks a lot Prof 😁😁😁😁
Thank u so much
I have an exam tomorrow
And u helped me
420th like! Great video, clarified the confusion for me. Especially love the correlation to the breaking of columns on an angle
nice learning videos .. particularly fr me bcoz i need to recall everthing learnt earlier
Is it only applicable for forces who have the same magnitudes in both directions?
Hello sir plz try to deliver in clear tone . Anyway it's so good and easily visualize able
Sir, how does a Normal Force produce a shearing effect on an inclined plane?
Thank you sir it is an amazing.
thanks, helped me with my work
hello sir.. that was great.. could u make a video on understanding moments nd forces in a piping system
you are a god sir, thank you so much
Superbbbb.. ..
Sir can you please explain why the cross sectional area become bh devided by cosin theta.....
Really helpful, thank you!!!
EXCELENT VIDEO BTW!!!!! THANK YOU!!!!
Very nice
that was great!!
Thank you very much!!!
its too amazing thnax
thank you so much for this video. Was wondering if you have a video showing an explanation of stresses on an inclined plane in a two-dimensional stress system.
thank you!
Dear Prof. RM French, Thank you for your videos they are very helpful! Please if possible could you do a cantilever beam connected to another wall, with pin joints at a section in the beam, or a similar problem and explain what happens to a beam if you(after solving it) add another moment. Thank you in advance. Best wishes!
"please" also calculate stresses on an oblique section in a) two mutually perpendicular directions, b) subjected to simple shear stress c)subjected to direct stress in one plane and accompanied by a simple shear stress d)subjected to direct stress in two mutually perpendicular directions accompanied by a simple shear stress.
How did u find out the shear stress cross sectional area? 4:00
The cross sectional area is the same as the normal stress area. It is the component of the force what makes the difference
thank you so much...
Awesome!!!
Nice and thank you .
Thank you !
Thanks a lot sir.
thank you so much!!!
Tq so much ❤
thank you sir
thanks again !
Thanks Sir
good video
Ten out of ten!!!! Thank you!!
Thanks.
nice 3d drawings
Sir why did u use both shear and normal stress here thank u
When you have an inclined plane, your axial force always have two components, therefore, unless it is 0 degrees both type of stresses are present in the element
I still don't understand why A= bh/cos(theta).
Your very welcome :D
thanks a lot
great
thanks
Fn = Fcos0
Fs = Fsin0
Im usin trig but its not working can you explain it ?
He's dreamy.
thxxxxx sir
thx sir
Why bh/cosθ = A/cosθ ?
Because A=b*h. A_theta=A/cos(theta). Thanks for watching my videos. I hope they are helpful. I wish you the best in your studies :-)
why is A=bh/cos theta
i get it now ...But how is A=AthetaCOStheta from geometry
First of all better use X- Axis and Y -Axis not N & S , for simplicity. Secondly if we consider such case , then it shall be Cos Degree on S and Sin Degree on N . Thanks
best
Thanks :-)
Like Like Like!!!
Man! You need better lightning.
I sure did. What you can't see in the video is the light stands I had in my little office. I never really got it right, though. This video is pretty old. Check out the newest ones with the cool LED lights - way better. Thanks for watching :-)
Level he nahi hai
Thank you sir
thanks