had to work through a few cobwebs, in prep for the FE exam, you nailed it. then i see you have a whole library! as well as being pretty. thank you ma'am, from me to down under.
Sorry i dont understand why you devided Pi by 4 ... You got 1.7 i got 1.9 ... would it still be acceptable to have 1.9 or am i missing a step here im confused when working out the cross sectional area...
Could you explain this- the lateral strain is the change in length and longitudinal strain is the change in diameter, you wrote the opposite. Why is this so?
That was part of the formula since the lateral strain is decreases. But when lateral strain is increasing (compressing force), the lat strain must be positive
The internal axial force is just F. You could show this by taking a cut through the member, drawing a FBD of 1 side, and solving for the internal force as an unknown.
Thank you for giving me the ability to pass my exam :D You are a genius, easy to listen to clear and thorough in your workings.
thanks for sharing this video... i was stuck in a problem and this will now help me to prepare myself for my end semister exam :)
Honestly you helped so much. My professor doesn’t explain the basics and I always have to come to TH-cam for help. Thank you for the video!
its my finals tomorrow and i am now doing my best to understand all of this, thannkkkyouuu Ma'am
Hello can you help me in some quostions?????
had to work through a few cobwebs, in prep for the FE exam, you nailed it. then i see you have a whole library! as well as being pretty. thank you ma'am, from me to down under.
Thank you so much I'm writing a test in the next 25 minutes
Turn. It's on universal level and you gpt the next Nobel Prize
couldn't you just use delta=PL/AE to solve for change in length?
Sorry i dont understand why you devided Pi by 4 ... You got 1.7 i got 1.9 ... would it still be acceptable to have 1.9 or am i missing a step here im confused when working out the cross sectional area...
It is 1.7
Then that's the formula for the cross sectional area
Why is 2.7 raised to 3 power and 1.7 isn’t for the stress
Could you explain this- the lateral strain is the change in length and longitudinal strain is the change in diameter, you wrote the opposite. Why is this so?
thank yu very much
How statically it's become a possibility ??for any given data volume ???
Sorry I'm not sure what this question is asking exactly.
Please why do we have a negative elat or is it part of the formula?
That was part of the formula since the lateral strain is decreases. But when lateral strain is increasing (compressing force), the lat strain must be positive
you have to write n / mm instead of saying it.
Why not 2F Ma'am?
The internal axial force is just F. You could show this by taking a cut through the member, drawing a FBD of 1 side, and solving for the internal force as an unknown.
Thank you Ma'am 😊
your voice... :)