Single Rivet, Double Shear - Example
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- เผยแพร่เมื่อ 26 ก.ย. 2024
- A single rivet holds three sheets of steel together, and is loaded as shown below. If the maximum average shear stress allowed for the material is 125MN/m2, and a factor of safety of 3 is required by the design standards, find the minimum rivet diameter.
Where was this video 2 years ago when i took material. Great video lol
Haha, no worries. Glad you found it useful
In calculating its bearing stress is the area use in equation being doubled as well?
Wouldn't the cross-sectional area of the rivet be half? There are two shear planes on the rivet.
Since there are two shear planes, that means the force applied needs to be able to cut through the bolt at the top and at the bottom @3.44.
That means the total area that is cut through by the 10kN load will be the area of bolt above and the area at the bottom.
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Another way of thinking about this question is that the bottom sheet only supports 5kN of load, and that 5kN cuts across one portion of the area.
Why does
125(10⁶)/3 = 41,666,666.67N/mm²
Converted into 41.6 MPa
When 1N/mm² = 1MPa?
Hi Panacea, it looks like you have an error in the first line.
125MPa =125 (10⁶) Pa
125 (10⁶) Pa / 3 = 41,666,666.67 Pa -> 41,666,666.67 N/m² -> 41.67N/mm²
41.67N/mm² = 41.67MPa
I'm not sure if I can answer the why question well, but I do have a video showing examples of unit conversions that may help:
th-cam.com/play/PLk9xM6UeGau1V-xhAkwGPW69mhCxhkOno.html
Hi all, fyi the video does not include bearing stress or crushing stress as it is assumed the point of failure is shear within the rivet.
EXCELENT
MN not Mpa
best video ever
When the problem says "average shear stress allowed for the material" are they referring to the material of the pin or the material of the steel sheets?
It should state which component is made of which material in the question. You are right to point out this error. In this case it meant the material of the bolt.
Were they already mention "material for the rivet?"