This was actually sooo useful!! You explain Modular Arithmetic better than any online video or course I've found on the internet. Everything makes sense now!! Every video I come across explain as they solve congruences, but you are the only one who actually proved the operations and made things make sense. Thanks so much! New Subscriber
You have explained this better than anyone I have come across either on the internet or at my university. Thankyou, SO much. Truly a lifesaver before my mid semester exams!!! New subscriber :)
Really nice video , I am a slow learner of Maths , This explains step by step very clearly . Many videos I watched regarding the basics of Modular Arithmetic but all those were for quick learners I think . This one is really helpful for a person like me who is slow and little bit poor in maths , Thank you
Thank you for these videos, I was studying cryptography and it assumes you know a lot about modular arithmetic. I took a lot of math in primary school and college, and I don't seem to recall ever going through this (but I never took a cryptography course to be fair, and I could have forgotten about it)
I wanted to learn this as this is very important for number theory which is very interesting. I was able to find only the long lectures on youtube. Since I didn't have time for all this, I was not able to learn this thing. THANK YOU FOR THIS VIDEO
I could be wrong so go easy on me, but isn't there a limitation when multiplying linear congruence by a constant. I think the constant cannot be a multiple of your n, cause that would be like multiplying a regular exuation by zero. example: 4≡1(mod 3) multiplying both sides 3 would give 12≡3(mod 3) , which we know is not he case. Splendid video by the way, i think you just forgot to stress this fact. :)
I just realised that 12≡3≡0(mod 3), which is still true, but the eqution is now trivially true. My bad, so sory.😅 Anyway, like i was saying, the identity becomes trivially true. A simple example: 4=2^2 \multiplying both sides by zero, we get 0*4=0*2^2 0=0
Yo my guy, next time, actually use those variables and put some values in them. Writing a ton of letters all over the board is DRY. I get that you're explaining the laws and being very technical, but you have to throw some practical examples in there to show how the laws are applicable. For Christ's sake. This is where people fall out of mathematics. APPLICATION, APPLICATION, APPLICATION.
This is obvious. You should explain the modular exponenciation or solve modular equations in which the number X to be guessed is the exponent of the power to be divided or the residue, like b.
This was actually sooo useful!! You explain Modular Arithmetic better than any online video or course I've found on the internet. Everything makes sense now!! Every video I come across explain as they solve congruences, but you are the only one who actually proved the operations and made things make sense. Thanks so much! New Subscriber
You have explained this better than anyone I have come across either on the internet or at my university. Thankyou, SO much. Truly a lifesaver before my mid semester exams!!! New subscriber :)
Really nice video , I am a slow learner of Maths , This explains step by step very clearly . Many videos I watched regarding the basics of Modular Arithmetic but all those were for quick learners I think . This one is really helpful for a person like me who is slow and little bit poor in maths , Thank you
You explain this far better than my university lecturer.
Looking forward to this if it becomes a sort of series!
Thank you for starting this Series! I know the basics, but there are many things that I should memorize as well :)
As always, great video by even greater teacher!
Thank you for these videos, I was studying cryptography and it assumes you know a lot about modular arithmetic. I took a lot of math in primary school and college, and I don't seem to recall ever going through this (but I never took a cryptography course to be fair, and I could have forgotten about it)
I love this video, it is very clear and accurate
wow.... just wow... that was in depth very good explanation. thank you.
thank you a lot!!! it was a great explanation. Also, your english is super clear and easy to understand
Thank you! You answered my question of operations!
very good explanation. Thank You for explanation.
I wanted to learn this as this is very important for number theory which is very interesting. I was able to find only the long lectures on youtube. Since I didn't have time for all this, I was not able to learn this thing. THANK YOU FOR THIS VIDEO
underrated video
Very clear and well explained, new subscriptor here!
Thnks for the very clear explanation!
Good as always
Wow.. What a beautifull explanation...
Good video for quick rivision
i do not get this
I just write a % n instead of rem(a,n) when I'm working out math on paper, I just use the C notation, it's succinct.
If a, b positive integers and 1+ab divides a^2+b^2 then (a^2+b^2)/(1+ab) is a square of integer can you prove this?🤔
You should do a series on Complex Analysis!
Thanks a lot this video help me a lott and was soo clear .
I am seeing from Laluk College Assam India
0.34 ..(a-b)/n should be a non zero integer . Whole numbers are 0,1,2,3.. but here it can also be negative . But nice explanation .
Exactly
and the symbol Z is the integer set not the whole number
again great explanation
Very clear, thanks a lot!!
Thank you 🌸
That’s awesome man!
Damn this is another channel I am watching to understand this but instead I am getting more and more confused totally
hello sir can you solve this one:
4x + 1 5mod12....i cant understand when it comes like this..please sir im begging you
give an example to show that a²=b²(mod n) need to imply that a = b (mod n)
Very nice
You teleported in 1:25
I've been practicing!
Well done.
Excellent
wow amazing
I could be wrong so go easy on me, but isn't there a limitation when multiplying linear congruence by a constant. I think the constant cannot be a multiple of your n, cause that would be like multiplying a regular exuation by zero.
example:
4≡1(mod 3) multiplying both sides 3 would give 12≡3(mod 3) , which we know is not he case.
Splendid video by the way, i think you just forgot to stress this fact. :)
I just realised that 12≡3≡0(mod 3), which is still true, but the eqution is now trivially true. My bad, so sory.😅
Anyway, like i was saying, the identity becomes trivially true. A simple example:
4=2^2 \multiplying both sides by zero, we get
0*4=0*2^2
0=0
Yes, in that case it is like multiplying an equation by zero. When we do that, it's usually not very helpful. However, we're still allowed to do it!
We are beginning with the easiest contents, all right
Yes, I am starting a series on basic number theory. We will get to more difficult stuff once we get through the basics!
exepting by null 3:51 ZIRO
goat
Hi handsome sir,thank you
Yo my guy, next time, actually use those variables and put some values in them. Writing a ton of letters all over the board is DRY. I get that you're explaining the laws and being very technical, but you have to throw some practical examples in there to show how the laws are applicable.
For Christ's sake. This is where people fall out of mathematics. APPLICATION, APPLICATION, APPLICATION.
This is obvious. You should explain the modular exponenciation or solve modular equations in which the number X to be guessed is the exponent of the power to be divided or the residue, like b.