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Input8^(log(8, 1.5) + 2) = 96 x=Log[8,1.5]+2ResultTrueLogarithmic form(log(8, 1.5) + 2) log(8, 8) = log(8, 96)
8^x=96. Solución:Aplicamos logaritmo decimal a ambos miembros de la igualdad:Log8^x=Log96Por propiedad de Log:xLog8=Log96Despejamos la variable x y será:x=Log96/Log8x=1,982372
((1 2/3)+(1/3)Log[2,3])=(5+Log[2,3])/3
Very simple just take log on both sides and after simplifying we get x=log_8(96)
👍
x=(1 2/3)+(1/3)Log[2,3]
Good, very good 👍
It’s in my head.
8^x=96x=log96/log8=1+log12/log8
lg96/lg8.
Cambridge my ass! I did this problem at my Flagstaff, Iowa, community college entrance exam 😊.
Input
8^(log(8, 1.5) + 2) = 96 x=Log[8,1.5]+2
Result
True
Logarithmic form
(log(8, 1.5) + 2) log(8, 8) = log(8, 96)
8^x=96. Solución:
Aplicamos logaritmo decimal a ambos miembros de la igualdad:
Log8^x=Log96
Por propiedad de Log:
xLog8=Log96
Despejamos la variable x y será:
x=Log96/Log8
x=1,982372
((1 2/3)+(1/3)Log[2,3])=(5+Log[2,3])/3
Very simple just take log on both sides and after simplifying we get x=log_8(96)
👍
x=(1 2/3)+(1/3)Log[2,3]
Good, very good 👍
It’s in my head.
8^x=96
x=log96/log8
=1+log12/log8
👍
lg96/lg8.
Cambridge my ass! I did this problem at my Flagstaff, Iowa, community college entrance exam 😊.