Calculating Distance Off Track using a VOR Radial & Distance

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  • เผยแพร่เมื่อ 25 ส.ค. 2024
  • This is a tutorial showing how to calculate the distance off track using VOR radial course deviation and distance.
    This will help you understand VOR indications and navigation principles like the 1 in 60 rule.
    #microsoftflightsimulator #aviation #avgeek #flightsimulator #vor #navigation #flightinstructor #xplane11 #xplane
    Please like and subscribe if you find it useful!

ความคิดเห็น • 7

  • @astorp12345
    @astorp12345 6 หลายเดือนก่อน +1

    It’s funny no one seemed to catch that. Great video though. Thank you!

  • @richavery66
    @richavery66 ปีที่แล้ว +1

    Thank you for this. I got the right answer with the wrong calculation - I saw that the aeroplane was 5 degrees off and approximately 60 nm away from the VOR station. However, instead of using the radial that the aircraft is flying along, I took the target radial and, as that is the adjacent side in the right-angled triangle, I multiplied 60 by the tangent of 5 degrees. This gave me 5.25 nm; at this distance and angle the answer was correct, but for greater values my calculation would have been way off... And that mistake was made sitting on the sofa, cup of coffee at hand - far easier to make such an error when flying the aeroplane, talking to ATC, looking out for traffic, etc!

    • @Taylair
      @Taylair  ปีที่แล้ว +2

      It's not really something I'd be doing in the aircraft anyway to be honest... I suppose the Tan of the distance between the abeam point and the VOR would work but that information might not be readily available

  • @mishmish1968
    @mishmish1968 ปีที่แล้ว

    Thanks for the informative videos you putting in the channel , it's very helpful.

    • @Taylair
      @Taylair  ปีที่แล้ว +1

      My pleasure!

    • @Aviationnerd857
      @Aviationnerd857 3 หลายเดือนก่อน

      Great video!

  • @lojzekiki8572
    @lojzekiki8572 ปีที่แล้ว

    You could also mentally calculate with the 1 in 60 rule: angle = H (lateral deviation) / S (distance in this case ~60NM) * 60. So you need to get H. And the result is also 5 :D