The Thevenin Equivalent Circuit

[@rogeliobarraza1772]

Can I just say thank you?! I’m currently dealing with a Neanderthal professor who just doesn’t know how to teach. He makes one simple concept more complicated than it should be. But this I can follow!

[@rahilmirza5620]

Same

[@sihlegidzana]

🙆🏾‍♂️😂😂😂

[@hari-sn5jj]

No it is understandable 😌

[@mr_xmath]

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[@mr_xmath]

@@hari-sn5jj th-cam.com/video/CLEd_i0yQ9A/w-d-xo.html

[@davidgittens3165]

Good explanation for students taking a first course in circuit analysis

[@ThatFroKid]

Honestly incredible you compressed a couple lectures into 9 minutes. This is awesome. Seriously best explanation I could find. Thank you!

[@TrevorHeadley]

Hello Douglas, thanks for your very encouraging comment.

[@yannrezk5735]

@@TrevorHeadley you are so hot i saw you walking in my garden next december

[@naasifn]

This is the best video of explaining Thevenin theorem. Please upload more videos like that!

[@TrevorHeadley]

Thanks for your encouraging comment.

[@Markel_A]

Great video, been trying to wrap my head around the basics of not only calculating Rth, but also Vth and you concisely explained both! Thanks a lot!

[@Trenz0]

You just made Organic Chem Tutor look like a fool in this topic! Fantastic video. Very helpful to recap my knowledge before my midterm tomorrow.
Great work!

[@dervaken3902]

coz chem tutor is a fool lol. He covers all possible topics from varios areas, but specifically he knows nothing

[@AzeezahIbrahim-w9f]

Only God knows how many videos I have watched on Thevenin. Your video is very helpful, simple and concise. This is the first time I am able to grab something from a Thevenin question. Thank you 😊

[@Aidandgreat]

I have been struggling with this all day, I have not been able to make heads or tails of how to tackle these. You my good sir have helped me drop this penny, excellent explanation!

[@mr_xmath]

th-cam.com/video/CLEd_i0yQ9A/w-d-xo.html

[@brucecleef6895]

My instructor made this way more difficult than it should have been. I was completely lost until I watched your instruction. Thanks!

[@tahoon2009]

Clear and easy to follow, Big Respect and wish you the best

[@philguitar3058]

Thank you for this Trevor. It was incredibly useful in helping me complete my laboratory report for university.

[@frostxd5194]

As simple as this video is, it helps me to understand better than videos with extra effect. Thank you

[@darrenloh1835]

thank you! The part where you mention how the O/C leads to no current flow through it and hence no voltage drop was so useful.

[@TrevorHeadley]

Thanks for your comments. All the best with your studies.

[@mr_xmath]

th-cam.com/video/CLEd_i0yQ9A/w-d-xo.html

[@gabrie-elbrowne7738]

The best explanation I've seen tonight. God bless you very clear and straight to the point .

[@mbizi4573]

Ever since I came across your channel, this is where I come if I want to learn the easier way. Thank you very much sir. Your teaching methods are amazing!

[@mr_xmath]

th-cam.com/video/CLEd_i0yQ9A/w-d-xo.html

[@MrDoneboy]

Excellent video explanation. And I worked for 3 years with a Nigerian lady, so I really love the accents!

[@JoshuaThomas-p1m]

Never had a more simple explanation , Thankyou

[@TrevorHeadley]

Glad it helped!

[@akaragoldson-deacon4068]

Wow! I truly commend you! After watching a number of videos, I must say that you explained it the best! All the best. #Blackand Smart #JamaicaRepresenting

[@TrevorHeadley]

Thanks for your kind remarks.

[@CameronSMoore]

Dude my professor just spent over an hour explaining this and I was completely lost, but your video makes so much sense! Thanks!

[@TrevorHeadley]

I am happy to have helped. Thanks for your comment.

[@TrevorHeadley]

With the voltage source removed and the points where the voltage source was
connected now shorted, the top ends of resistors R1 and R2 are connected
and the bottom ends of R1 and R2 are connected, hence resistors R1 and
R2 are in parallel.

[@ShishiraMahunta]

solve it with more complicated circuit.it is easy to explain in simple circuit

[@SnuckleRound]

Thanks you for explaining that, once I saw this comment it helped clear up my confusion. Cheers!

[@thomassankara1391]

When finding the Thevenin Voltage, why do you multiply it by R2? I don't understand that. Vth= (Vs/ R1 + R2). What's the purpose of multiplying R2 in there? I don't get it.

[@TrevorHeadley]

@@thomassankara1391 The Thevenin voltage is the voltage across R2. But VR2 = IR2 X R2. Since IR2= Vs divided by (R1+R2). Then VR2 = IR2 x R2 = Vs /(R1+R2) x R2

[@KelvinBwalya-eu8xh]

I still don't understand, can you show me a diagram of what you mean

[@SabrinaOnTheGo]

I am an electrical student and I have exams soon. I watched so many videos on this theorem and understood nothing but you explained exceptionally well thank you.😊

[@TrevorHeadley]

Thanks so much for your feedback!

[@sabarauf2829]

Thank you so very much, nobody could explain it any better. Thanks alot.

[@TrevorHeadley]

Thanks for your comment. All the best!

[@chinthanahewavithana719]

This video helped me lot. Thank you soooooooooooooo mush. You are the best.

[@TrevorHeadley]

Thanks so much for your feedback.

[@user-od1mo3gi3f]

Thank you. I was struggling to understand this topic but you explained it so clearly. Thank you once again.

[@TrevorHeadley]

You're welcome and thanks for your comment.

[@akmalkhairy]

thank you Sir. you make this lesson so much easier to understand

[@imagidan]

Best explanation. As simple as can be.

[@DATRATMANZ]

EXCELLENT EXPLANATION! I Thank you for your time and sharing your knowledge with the world.

[@gregmusto3336]

Thank you for a very straight forward explanation. I have a test on Tuesday and this has helped massively with my revision. I have been struggling to understand this topic.
Thanks again.

[@rickbronx8528]

Thanks. I finally get it, best explanation I've seen.

[@animexarmyindia8382]

Awesome sir, you are better than notes of top universities.

[@SurjeetSumanAcharya]

VERY EASY AND THOROUGH EXPLANATION..#RESPECT

[@trevorheadley2391]

Surjeet Suman Acharya
Thanks for your comment.

[@SurjeetSumanAcharya]

Sir,upload a video on maximum power transfer theorem and solve some problems on it..

[@trevorheadley2391]

Surjeet Suman Acharya
Hello Surjeet,
have a look at this useful site :
www.electronics-tutorials.ws/dccircuits/dcp_9.html

[@SurjeetSumanAcharya]

Thanks sir, it was worth reading..#LOVE from India

[@mdgayanvijithapriya3719]

O wow mazing explaination , thank you verry much sir 🙏, sir can you please explain about nortons theorem and super position ?

[@thomasappaix549]

thank you, very well and thoroughly explained. Cheers from an electrical engineering student.

[@trevorheadley2391]

Thomas Appaix
Thanks for your feedback. All the best with your studies .

[@perrkons]

Simple, yet elaborate explanations, thank you!

[@terra3673]

I saw this during my examination...got all my answers..thanks alot

[@josephbridge6884]

Brilliant video, the worked example and final drawing helped me so much! Thank you.

[@ncj8879]

You are AWESOME! I can’t thank you enough for helping me out!!! Please keep the videos coming! 🖤✨

[@vinaychary6185]

excelent explanation sir hat's off to you

[@TrevorHeadley]

Thanks for your kind comment !

[@pavolpanisz3251]

Thank you. I've watched a couple other videos on this topic, but your wording finally made it click for me. I was struggling with the concept of having "Voltage at some node". How can you have voltage at a single point, if voltage is always measured across some distance? Lots of tutorials phrased it like this. But you used the sentence "A voltage at a point with respect to another point". This finally made it apparent what everyone meant. Thank you for that. Words really do matter when teaching.

[@TrevorHeadley]

I am really happy that I was able to clarify that issue. Thanks for taking time to let me know.

[@nedzla100]

Amazing!The only video that explains everything so nicely!

[@TrevorHeadley]

Thanks for your comment!

[@mridulsharma7091]

Oh wow..thankyou so much for teaching us and helping us in such a nice way.. Its becomes very easy.

[@TrevorHeadley]

Thanks for your comment!

[@inventing...3717]

Thank you sooo much you have truly helped me understand this method...Thank you for your videos

[@TrevorHeadley]

Thanks for your comments!

[@bix833]

thank you very much sir.
cant thank you enough.
I have exam tomorrow and you made me clear about this theorem in this night.

[@cerglabs3646]

Thank you so much for this. Perfect in it's simplicity of explanation!

[@mr_xmath]

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[@happyhome-technoworld3025]

Excellent explanation. Highly recommended video. Thanks.

[@LeonhardWelebny]

This entire concept made no sense to me, even after reading through the provided materials from my professor several times. It was complete nonsense to me. Your video just explained everything so perfectly, now I am getting it!

[@nikkopeeko]

thank you for this video ive tried watching other ones and they were so confusing but this one helped alot, thanks!

[@TrevorHeadley]

Thanks, I am happy that it helped.

[@matthewc.thornton1409]

The way he says Thevenin has got to be one of the coolest things ever

[@mikeyoung7208]

Oh wow. Good job, I am very fortunate to have stumbled upon this video. Thank you.

[@TrevorHeadley]

Thanks for your kind comment.

[@panosalphaman6197]

I was trying to figure this out for hours now, thank you so much

[@righteousness185]

much more simplicity in this explanation..thank you.

[@williamskidmore8992]

Really good explanation - fully understand how to solve these Q's now thanks!

[@mr_xmath]

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[@AyomideJoseph-u3n]

Thanks 🙏 for this. I really appreciate 🙏
Best explanation ever ❤

[@allenthabanimoyo]

you explained very well Mr headley.I really understood

[@zailuanshuoyou955]

❤😢Thank you for saving my school life

[@DATRATMANZ]

If your somehow still confused about why V_Th is calculated by (V_s/R_1+R_2)*R_2 think of it like this. V_Th is the voltage at the terminal before R_3 which is the same as the voltage across R_2. How do we calculate R_2? V = iR right? V_Th = i*R_2.... we need i......... i = V_s/R_eq..... R_eq = R_1 + R_2.... All he did here was simplify this process into one equation.
So now....V_Th = (V_s/(R_1+R_2))*R_2.
Basically.... to find V-Th all we need to do is recognize that V_Th is the same as the voltage across R_2 and we need to find the current through the new circuit so that we can find V_2.
V_Th = i * R_2.
i= (V_s / (R_1 + R_2))

[@axh759]

Thanks a lot for this simple explanation

[@drevi1980]

Thanks you, that was the best explanation that i found on-line.

[@izclovenssevere9881]

Amazing video. You helped me with my Hw.

[@josepinheiro5733]

The only one that truly help me

[@nomnom4346]

I am extremely grateful for your video. :)

[@rizzzlleee3540]

Thank you this help me so much

[@TrevorHeadley]

Hello Randy, I appreciate your comment. Thanks

[@nooriqbal285]

Love love love it .... your a great teacher thanks keep it up

[@alexfirthmusic]

Thank you very much for uploading this!

[@davidpinto5042]

Great video sir. Very nice explanation ! Thank you

[@hhsul]

May God have mercy on you in this world and in the hereafter, you do not know how you helped me🙏💚

[@brianna1347]

Thank you so much, I was really struggling with this concept.

[@tenzin8773]

Short and concise. I love it!

[@Pholc25]

How would one calculate the first example if R2 would be replaced by another source like Vs and the R1 and R2 would je mirrored on the other side as well

[@SaltyFishh]

This is very helpful. Thank u so much. Miracle.

[@makiamattison5357]

Needed this Thank you Trevor!

[@ramilkhalilli4948]

Thank you very much , this video helped me a lot

[@JohnDowelll]

Good work Trevor!

[@TrevorHeadley]

Thank you!

[@happyjulius7258]

Thank you very much. My phy 202 exam wil be so exciting.💃

[@mikeatlanta9306]

Very clear explanation 👍👍👍

[@damienkubik1380]

Thank you, made way more sense than my university professor.

[@TrevorHeadley]

You are most welcome Damien ! Thanks for the comment.

[@debnarayandutta8551]

Very good explaination sir...thank you very much

[@ludovicoferrari6258]

Lol.. I am an Italian guy, I was searching some videos because in few days I have the electrician test, and I learn more in this English video than in the Italians videos

[@jannickemile-smith1497]

an excellent explanation

[@charlescastle4533]

Crazy how people learn jack squat from their own professors, but some random person on TH-cam explains it perfectly in 5min.

[@suan_tech2019]

this is what i needed
thumps up

[@whocares8019]

I love this video, now I get it...
Idk why teachers can't teach like this..

[@theclawsoftime2304]

Thanks! You explained this very well.

[@dorfinhorg9458]

Thank you very much! This video helped me a lot.

[@dylanlloyd2177]

Thank you so much for your video! You say at the end VL can be whatever it wants, but in my assingment thats what im trying to find.. thank you!

[@michaelparsons8328]

Best video I've found, thanks!

[@TrevorHeadley]

Thanks Michael for your encouraging feedback.

[@n051de4]

such a great explanation.

[@tomkirkland9437]

Great explanation, love the accent

[@AfriTalesOfficiall]

All i can do, is to say thank you sir.

[@soumyajitsarkar2372]

That was very well explained !! Thanks Sir :))

[@PatchFact]

Excellent explanation, thank you!

[@dardanaufal3457]

this explanation is good....thanks a lot!!!!

[@kittykitkat7348]

If R1 and R2 make a voltage divider circuit, then how come you treat them as if they are parallel when calculating the total resistance since two resistors must be in series to be treated as voltage dividers

[@tomas_soeterik]

Amazing video best explanation

[@voldemort576]

You made everything easy.

[@TrevorHeadley]

I am happy to have been of help. Thanks for your comment.

[@HowTo5min-co3ni]

Great job good teaching technique. New sub🎆

[@muhammadrizwan9002]

Thank You Very Much, Sir. It was Really helpful......

[@TrevorHeadley]

You're most wecome! Happy to have been of help.

[@ramelaramela8985]

Thank you so much , that was well explained

[@jashanpreet9077]

Great Content 🔥

[@shivamkhajuria1726]

best explanation.. thnku soo much sir

[@sohailjanjua123]

Hi, I like your lecture. Thanks