Hardest Math Olympiad Problem | Can You Solve This Hardest Junior Math Olympiad Algebra.

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  • เผยแพร่เมื่อ 7 ก.ย. 2024
  • Hello my good people, welcome to today video 🎞️🎞️.
    I consider this junior math Olympiad problem one of the hardest question for this level.
    How to solve this math algebra step-by-step is the tip or aim of this video and to make everyone know the secret to solving algebra of this kind.
    Drop a comment in the comments section on what you think about the steps applied here.
    Like, and share this video with as many that are preparing for Junior Math Olympiad.
    Link below.
    • Hardest Math Olympiad ...
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ความคิดเห็น • 21

  • @danielfranca1939
    @danielfranca1939 2 หลายเดือนก่อน +1

    At line 6, you wrote -(-6)^2 on the LHS instead of +(-6)^2 although you gave the right expression in line 7 which corrects everything. No cause for alarm, you did a very nice work sir.
    ❤❤❤

    • @abrahamgaladima3581
      @abrahamgaladima3581 2 หลายเดือนก่อน

      I am not sure line 7 corrects what happened in line 6. The left side is not the same as the right side. To the left side you subtracted and on the right side you added. Video needs to be edited is my suggestion. Thanks Sir.

    • @onlineMathsTV
      @onlineMathsTV  2 หลายเดือนก่อน

      Yes, you are right. So sorry about that sir/ma

    • @onlineMathsTV
      @onlineMathsTV  2 หลายเดือนก่อน

      It is a mistake on my parts, so sorry about that pls,

  • @nagarajahshiremagalore226
    @nagarajahshiremagalore226 2 หลายเดือนก่อน +1

    Violated the rules of simple Algebra.

  • @abrahamgaladima3581
    @abrahamgaladima3581 2 หลายเดือนก่อน +1

    Please help put another video out as the error of adding half coefficient -12 confused me. Thanks always!

  • @KheemchandRai-j1g
    @KheemchandRai-j1g 2 หลายเดือนก่อน +3

    how is it possible sir one side you add -(-6^2) and the other side +(-6^2)

    • @samueldeandrade8535
      @samueldeandrade8535 2 หลายเดือนก่อน

      He does it on purpose. To make people comment.

    • @onlineMathsTV
      @onlineMathsTV  2 หลายเดือนก่อน

      Oops!!! It is a sleep of hand...🤣🤣🤣😂
      Am so sorry about that and thanks for the good observation sir.

    • @onlineMathsTV
      @onlineMathsTV  2 หลายเดือนก่อน

      Ah!!! How could you make such unreal conclusion dude?
      That is far from it sir. All the same your view of things or perception to life is peculiar to you and I pretty respect that, because, that is what makes you unique and different from the other number of billions of human on the surface of the earth.
      Thanks for watching and commenting sir 🙏🙏.

  • @WorldwideBibleClass-qr9jk
    @WorldwideBibleClass-qr9jk 2 หลายเดือนก่อน

    Wonderful as always.
    Thanks for the effort you put in your explanations, sir.
    Greater heights.

  • @-basicmaths862
    @-basicmaths862 หลายเดือนก่อน

    (x,y)={3,4}&{ 4,3}

  • @kassuskassus6263
    @kassuskassus6263 2 หลายเดือนก่อน

    Where are the 12xy ? And why did you add -36 left and +36right ?

  • @papkenhartunian186
    @papkenhartunian186 หลายเดือนก่อน

    Sir, (0,7) and (7,0) must be rejected because x and y ae not positive.

  • @sureshdave7
    @sureshdave7 หลายเดือนก่อน

    READ VERY CAREFULLY: I see a very innovatve but easy path to the solution>>>>> if one explores graphical solution. Key features are : #1 : >>>>> x^2 + y^2=49 is a circle with (0,0) as center a radius of 7...... #2 >>>>> we want to identify points on the above circle that would satisfy the following condition: all the terms, remaining after keeping the ones needed for making circle, should add up to zero. write this as another key feature. For examle, see the terms that make "xy-14 =0" is a par of two hyperbolas: with x & y xaxes as asymptotes. Cross points of these hyperbolas and cicle are four points of your answer. there are two or more poiints .. do you need help to calculate thee se cross points?

    • @papkenhartunian186
      @papkenhartunian186 หลายเดือนก่อน

      I like this method better. It is a very powerful method. Because you do not need the hypothesis that solutions must be positive.