CAPACITOR WITH SERIES REACTOR SIZING|DETUNED REACTOR|L-C BANK CALCULATION.
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- เผยแพร่เมื่อ 15 ก.ค. 2019
- CAPACITOR IS WIDELY USED IN INDUSTRY TO IMPROVE POWER FACTOR. BUT CAPACITORS NEED A SERIES REACTOR TO LIMIT THE STARTING INRUSH CURRENT. ALSO THIS SERIES LC CIRCUIT ACTS LIKE A HARMONICS FILTER. THIS SERIES REACTOR IS ALSO CALLED DETUNED REACTOR. AND THE CAPACITOR BANK IS CALLED DETUNED FILTER. SO IN THIS VIDEO WE SEE HOW THE SERIES REACTOR, AND CAPACITOR IS CALCULATED.
POWER FACTOR CAPACITOR BANK CONNECTION
HOW TO CONNECT THREE PHASE POWER FACTOR CAPACITOR
SERIES REACTOR WITH CAPACITOR
CAPACITOR BANK DESIGN
DETUNED REACTOR
DETUNED FILTER
LC FILTER
WHY INDUCTOR IS USED WITH CAPACITOR
DESIGN OF POWER FACTOR IMPROVEMENT CAPACITOR BANK
SERIES REACTOR IN CAPACITOR PANEL
INDUCTOR USED IN LC CIRCUIT FOR POWER FACTOR AND HARMONICS FILTER
HOW TO CALCULATE CAPACITANCE AND INDUCTANCE OF A CAPACITOR BANK
POWER CAPACITOR REACTOR
#ElectricalTechnologyAndIndustrialPractice, #Capacitor, #DetunedFilter
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VERY GOOD SIR
Very good explanation and useful !
Excellent description & easy for learning & very helpful too !
Fantastic.
Clear Explanation.. Easy for new learners...thanks ..
Useful ❤❤
it is superb video .could you explain me the difference between fixed KVAR and virable KVAR please?
Nice
Nice explanation
very useful, thanks.
Thank for best video pl explain in more simple way ,ie Std formula requirements capa Inductors initial pf to consider .
Going over the head. But I am trying to gather it.
How we selecting Line reactor for a DC drive and for a Capacitor bank. Please discuss on it.
Is there any IS no. For selection of 4% to 7% of impedance of capacitors?
Thanks for the video, I still could not understand how will you check the power factor of a system.
The required Power factor.. Ok can be assumed but please explain how will you calculate PF of complete system. I mean.
If you have a residential building of 10 floors with a plant room, which accommodate the pumps and heavy AC system .
Now for individuals motor the PF will be written on the name plate but when you consolidate into its panel (sub panels), then main panels and substation.... How will you calculate the complete PF of system.. Ultimately the Power factor control panel will be connected to the main panel. Hope you understand my explanation.
It also mean while calculating the connected load we aggregate the total individual wattage so we have total watts, now to derive a ampere we assume the PF to be some value but we cannot derive the PF from the same as it was assumption.
Kindly clarify please
Can you please further explain what is this 7% of reactor and why do we consider this.
Pl advice in each bank 6 nos are safe (or) 12 are safe
Sir transformer no load power factor low time capacitor bank used or not.Again the load increase power factor normal how select the capacitor bank size.
Hi sir,
Thanks for your informative video, I want to know how we calculate %age reactor (e.g 7% or 14%) can u please guide me
Wow...very nice explanation . Please can you mention the reference book for this calculation (Reactor sizing 7-10%)
This design assumes star connected cap and not delta, must be specified
When and why to use star and Delta design , parameters to consider.
good explanation sir. Why capacitor banks are heated too.
capacitor also has resistance...
HI, can you please explain why we are using the sqt of 3 in the current equation, I am making a pf corrector for a vfd and I feel a little bit confused with it.
if we are considering this as a single phase branch so KVAr=I*V without using sqt of 3
v in this case to be considerd V line to neutral then later VXL sqr of 3 is used, I am missing something here, would you be so kind to explain that in more details.
Thank you in advance.
actually the voltage and current are line to line voltage and line current only. if you calculate power with line to line voltage and line current you have to multiply by 1.732. i have videos on star delta system. please watch that. i hope your doubts wil be cleared
@@electricaltechnologyandind5335 Thank you very much for your rapid response, you are very kind, I will watch these videos and hope to get rid of this problem of sqr of 3....
Thank again.
also in calculation of xeq why we has not divided the voltage by sqrt 3.
Sir,
Do u have some excel sheet for the same calculations, it would be kind of u if u could help with the same.
What's is Value of 0.93 sir?
This formula can reduce harmonic?
How this
XL=00.93 XC = 56.08?
Please explain.
How to select series reactor %z. What are the basis of selection.
the 7.7kv is the voltage produced by capacitor? please explain. 6.6kv=VL+VC should be like that.
You are absolutely right. This is because inductive voltage drop phasor and capacitive voltage drop phasor are 180 deg out of phase.
However, one point that this gentleman has missed is the star delta conversion which is the soul to thi design. After you have found out the Xc you need to transfer it to equivalent delta connection. This way delta Xc will be 3*Xc . Please note that almost all capacitor bank in LT system is delta connected. So you have dovthis change.
In voltage drop across the inductor why (sqrt3) multiply?
This is the most relevant query which almost everyone has overlooked. You have all along done calculation on per phase basis. Why suddenly you multiply
Y the voltage drop with root3. In fact voltage drop is always a phase parameter. But interestingly if you do your calculation strictly on per phase basis you will arrive at the same thing. Here is how the calculation goes
Per phase voltage drop = 65.61 * 4.37 = 286.71 volts
Per phase Cap voltage = (6600*1.1/1.732)+286.59=4.48kv
Per phase Cap KVAR = 4.48^2*1000/62.45=321.38kvar
So three phase kvar =3*321.38=964kvar
So even when the line voltage increases to 1 .732*4.48=7.76kv this will work satisfactorily.
But generally the cap banks are connected in delta in LV network and in that case the calculation will done considering star delta transformation.
The end result will be as follows:
Capacitance value in delta connected cap unit: 17micro farad
Xc = 187.2 ohm
Ic = 37.88 A
Voltage grade of each cap unit= 7.76 kv
Kvar rating of each cap unit = 321.38 kvar
HOPE EVERYBODY HAS UNDERSTOOD THIS
Why we can select 14% rector instead of 7% reactor. Plz explain how we can select 7% reactor ?
Here no consideration of tunning frequency. And tunning factor is not considered.
What will be happened in case of resonance.
Regards
From where 0.93 this value came?
Please check reply to Sovik mondal query. You can clear your confusions
Sir what if the requirements is 6% reactor but the proposal is 7% reactor. Is that acceptable?
Yes. That depends on harmonics compensation. 4-7% is acceptable.
In capacitor current calculation why sin© is not used.. Pls explain.. Formula is root 3 visin©
You calculate with sin theeta and let me know the difference in comment section... You will understand yourself
May be © near to 90 as capacitance is of large value as I think..am I right.??
Yes.. that is the reason... There won't be any significant difference.....
How Xeq = Xc-XL? It should be Xeq = Xc + XL
These are not scalor quantity but vector quantity.