Nodal Analysis Example-Dependent Voltage Source
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- เผยแพร่เมื่อ 11 ม.ค. 2012
- Shows how to do nodal analysis when the circuit contains a dependent voltage source. More instructional engineering videos can be found at www.engineeringvideos.org.
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Thanks a lot. I was staring at a problem for about 3 hours trying different methods to solve it and that simple super-node did the trick for me :)
5:52 you have forgot at V3 the 1/1
Everything was explained well and easily understood.
Nice work..
I'm already graduated and have 3 years experience but I like to watch it again for nostalgia
in minuit 6:00 finding KCL arround supernode , in the equation you missed to write the current through the i ohm resistor in node 3 ,,,,am i right?
@stephenxluo Yes, I meant KCL. Thanks for catching this.
around 5:52 why is it that you didn't account for the V3/1ohm? in the second quantity of the purple equation
I ENJOYED your presentation...easy to understand. Thanks
Darryl i really don't know how you came up with the second equation, but i think the super node is the sum of the two equations on both sides, can you please tell me if im right or not. and if im right, would you make it like that because it's going to become alot easier to understand. thanks alot for your videos
according to my calculations,v1=162/7, v2=36/7 and v3=-18/7.can u please tell me where I might have gone wrong
When you simplify Eqn 2, did why did you leave out V3(1/1)?
how can i find the directions of the currents? it's really bothering me....plz help....thanks in advance
Did you make a mistake in the equations when simplifying the pink equation? (at 5:36) you write out the value for v3... shouldn't it be v3(1+1/3) rather than just v3(1/3)....?
5:42 It is supposed to be V3*(1/3+1) because you do sum of conductances connected to node 3 multiplied by voltage at node 3.
Pattern for supernode equation: Sum of conductances connected to one "sub-node" of super node multiplied by its voltage PLUS Sum of conductances connected to the other "sub-node" of super node multiplied by its respective voltage MINUS sum of conductances shared between the whole entire supernode and node 3 multiplied by node 3 voltage.
Pattern for regular node eqn at node 2: sum of conductances connected to node 2 multiplied by voltage at node 2 MINUS sum of conductances shared with node 2 and node 1 multiplied by voltage at node 1 MINUS sum of conductances shared with node 2 and node 3 multiplied by voltage at node 3
+iwillavengeyou agreed. he forgot to bring the V3 term from the [(V3-V2)/1ohm] part of the equation
how did you get the 3A side to be zero,my arithmetic sucks
Yes it should be v3(1+1/3), you can see it clearly when he writes the original equation at 5:15
how can equation draw from node 2 ?
please i real need your help
How do you input this in calculator?
The solution is correct but there is a much easier way to solve using nodal analysis if you set the reference on the left node. You end up with only 2 unknows since the right note's voltage will be defined by the dependent voltage source with respect to the new reference
how come i dont' see capacitors or fets or inductors and thinks like that
Nvm, you only forgot to re-write it, you did it correctly in the calculation using wolfram
how did Vx became V2 ??
Vx is actually defined as V2 in the problem. A dependent voltage source must depend on something already defined in the problem, (just Vx is meaningless) so keep that in mind when you're solving
VividlyVicious But Vx is the voltage drop across the 4ohm resistor so shouldn't Vx=V2/4 be the correct equation?
VividlyVicious Oh I get it now
supernode simplification is not correct should be v3(1/4)
Brian Woolschlager right
why is it v3/4? isn't it v2/4?can you explain?
The correct one should be v3(1/3+1)
How come, V2 is equal to Vx?
4 ohms resistor has voltage Vx and the node voltage of that node is V2 and since in a node voltage is same V2=Vx
Vx is part of the dependent variable.
The hardest part of this problem is deriving the right purple equation.
Yes, 1 + 1/3 = 4/3, not 1/3.
v1 is 18v.. V2 is 7.2v
another day, another bomshell
my calculation is diffrent..haih..pakek..
my ans is v1=81/11 v2=18/11 v3=-9/11
I got 12v, 6v and 4.5v seems like much more reasonable numbers if you ask me. But then I'm no electronics genius
u r right
prob is ,our college doesn't allow wolframalpha
try symbolab.com
Or plug it in in your Calculator. See if your calculator has an equation solver.
U taught well but u are really slow !
jesus christ. put me to sleep.
Im gonna have to dislike this video, at aleast acknowledge when and where in the comments or the description that you fucked up and the answer is incorrect.
So bad