How to Use the Method of Consistent Deformations to Solve a 2nd Degree Indeterminate Beam
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- เผยแพร่เมื่อ 13 ก.ย. 2024
- In this video, we tackle a more difficult, second degree indeterminate beam using the method of consistent deformations. This question involves taking two redundant supports, developing two additional equations and solving them simultaneously in order to solve for our reactions!
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Post down below and let us know if this helped you, and if you want to see more!!
Link to another example (1st degree): th-cam.com/video/-dhVofRCoPM/w-d-xo.html
We actually slice this same question in class today
Thank you
we want to see the deflection formulas, and you can shorten the video just by editing the slow writing/drawing part.
Thank you so much. This helped me a lot
simple and easy to understand ! Thanks !
If you please name a book you are using for these types of question
can you at least show the deflection tables or just show the formula you used so we can substitute it on our own thank you!
You didn't even show the deflection table. And you didn't teach how to solve the delta Bo and Co, Fbb and Fcb and Fbc and Fcc
Solving those deflections is literally just plugging into formulas from your textbook, theres nothing to teach. The purpose of our channel is not to show you how to plug numbers into simple formulas. Also you should have a deflection table of your own in your textbook, or your professor will supply one and you should practice with that one as itll be the one given to you in the midterm/final, not ours.
But you didn't explain on what value should I use for "a" and "x" base on the formula you used on the last video you did.
Very true, we didn't explain in this video because: 1. We did it in a previous video and we don't like repeating steps that make the video unnecessarily long (its already 10 minutes), and 2. This problem isn't about solving for deflections using formulas, it's about using the force method to solve indeterminate beams. In a lot of our problems we skip some calculation steps and focus on how to solve the problem, while encouraging you to try to solve for the deflection and compare with what we got. If we didn't do this, our videos would be 30 minutes long. I know there are other TH-cam channels that focus on formulas and such that may help you further supplement our videos!
yep dis video doesn't help it lacks steps
Whenever there is beam and vertical loading cause udl is vertical loading and support are at same level, then there is no horizontal reaction and and we aslo take 2 equilibrium eq in this case ❤️
There is a horizontal reaction still, there has to be or the member is unstable. It's just zero. In example questions the loading is almost always perpendicular. If you have some inclined loading or tension/compression in the member it isn't zero.
Bro it's not 5-3 it's should be 4-2
No, just because the horizontal reaction is zero doesn't mean you don't count it (it could be non zero), but without it the member is statically unstable.