Hello. I want to thank you for all the hard work you've put in for us. I am currently in the final stages in my GSA coursework for my UCL Civil Engineering course, and this video helped me get AMAZING results. For anyone hesitant about the quality of this video, I can assure you that this video is a LIFE SAVER. Thank you Engineer4Free, and i will no doubt be buying all your merch and repping it in classes haha :P once again, thank you. May the FORCE be with you!
I can't believe the video lectures I'm paying Penn State 1700 dollars to take for a 6 week structural analysis class pale in comparison to the videos you produce. You're seriously a blessing!!!
Hey Kamal, thanks for pointing out the typo as others have too. That was my bad, and there is a note in the description, but for anyone looking through the comments too it's helpful to flag it.
What if I have a situation where the structure is similar to yours, but the P load is not on the end of the beam? I'm unsure which equations to use when the P load is not on the end. The structure is still fixed at one end with a roller on the other (that we remove) and there is still a distributed load downwards across the length of the beam. The only difference is that the fixed end is on the opposite side that is on in regard to your structure and there is a point 20 m from the left side where the P load is applied, then 10 m to the right end of the beam where the fixed end is.
So that’s an overhanging beam. Here’s a video with an overhanging beam example: www.engineer4free.com/4/shear-force-and-bending-moment-diagram-practice-problem-7 the example is statically determinate but worth watching to get the idea. You just treat the beam section between the supports as if it’s simply supported, but instead of having zero moment on the end with the overhang, it’s going to have an internal moment equal to that point load out on the end times the distance to it. Actually, I’d recommend checking out the superposition section of engineer4free.com/structural-analysis because the force method is actually just what we call when we use the method of superposition for statically indeterminate structures. Hope that helps
You can use method of suoerpoaition + table for multiple point loads. See the third row here for the formula that you'd need to apply twice: engineer4free.com/extras/beam-slope-and-deflection-table
Awesome, glad I could help! You should check out engineer4free.com/structural-analysis if you haven't already for all the statically indeterminate methods that I covered 👌👌
their is but you can find it after finding the reaction at the redundant support. so first apply force method once you have your reaction use it to find the moment about A
@@flowmaticgaming4892 but how would you find it without first finding your support reactions😅 like yeah you can find it but after using that moment to find the support reaction of the redundant support your moment would just change again. So I’m my opinion it’s easier to just find the reaction first then use it to find the moment.
Oh wow, whoops. You've got the wrong sign for the "20(1)" term, but yes there is a typo at the end of the video. Ma should equal 5 kNm, not 5.6 kNm. I have added a note in the description mentioning this. Thanks for pointing it out!
Hello. First of all I would like to thank you for all the hard work you did in these videos to help us students become better on this topic. I have one question. I have a homework, and I should do it with the Force method.It is 3x staticly indeterminate. Could you please take a moment and guide me how is the easiest way of doing it. I will post link to my assignment. Greetings and sorry for bad english. Link: imgur.com/jcGstD3
Hey Kemo, sorry I don't have any videos on frames. I recommend just looking up some other examples on solving frames with force method and following the process, it's similar to beams.
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Hello. I want to thank you for all the hard work you've put in for us. I am currently in the final stages in my GSA coursework for my UCL Civil Engineering course, and this video helped me get AMAZING results. For anyone hesitant about the quality of this video, I can assure you that this video is a LIFE SAVER. Thank you Engineer4Free, and i will no doubt be buying all your merch and repping it in classes haha :P once again, thank you. May the FORCE be with you!
Thanks Aadam for the nice comment!!! Glad I can help, and hope your find the videos on the other methods useful too!! ✌️✌️
I can't believe the video lectures I'm paying Penn State 1700 dollars to take for a 6 week structural analysis class pale in comparison to the videos you produce. You're seriously a blessing!!!
Yeah it's all a bit messed up. I'm just tryna figure out how to get all those 1700s instead 😂😂. Thanks for the comment!! 🙌
I'm here for my last hour review and i understand it completely thanksss
Good luck with your exam!
Thank you very much. Just to let you know that MA should be 5.0 kN-m not 5.6 ...
Hey Kamal, thanks for pointing out the typo as others have too. That was my bad, and there is a note in the description, but for anyone looking through the comments too it's helpful to flag it.
Please sir i will need help with the moment area method but the table method is okay
hi, where did you get the list of equations from, cant find them on yourwebsite
Hey Chris, the link is here: www.engineer4free.com/extras/beam-slope-and-deflection-table
What if I have a situation where the structure is similar to yours, but the P load is not on the end of the beam? I'm unsure which equations to use when the P load is not on the end. The structure is still fixed at one end with a roller on the other (that we remove) and there is still a distributed load downwards across the length of the beam. The only difference is that the fixed end is on the opposite side that is on in regard to your structure and there is a point 20 m from the left side where the P load is applied, then 10 m to the right end of the beam where the fixed end is.
So that’s an overhanging beam. Here’s a video with an overhanging beam example: www.engineer4free.com/4/shear-force-and-bending-moment-diagram-practice-problem-7 the example is statically determinate but worth watching to get the idea. You just treat the beam section between the supports as if it’s simply supported, but instead of having zero moment on the end with the overhang, it’s going to have an internal moment equal to that point load out on the end times the distance to it. Actually, I’d recommend checking out the superposition section of engineer4free.com/structural-analysis because the force method is actually just what we call when we use the method of superposition for statically indeterminate structures. Hope that helps
Prof can you show us a way to draw the BMD for this type of loading on a cantilever?
Very good explanation of Force Method. Keep up the great work!
Thanks!!! =) Got some more examples in the playlist th-cam.com/play/PLOAuB8dR35oeyKU0ojIxD8Muf6Mwc8ugW.html =)
what if i have similar beam but with 2 point loads how do i find the equations from the table?
thank you
You can use method of suoerpoaition + table for multiple point loads. See the third row here for the formula that you'd need to apply twice: engineer4free.com/extras/beam-slope-and-deflection-table
do you have more example for ind beam
Yeah lots, all my indeterminate beam videos are at engineer4free.com/structural-analysis
Thank you I was having a really hard time for a while but you explained it clearly thanks again hope to see intresting new videos
Awesome, glad I could help! You should check out engineer4free.com/structural-analysis if you haven't already for all the statically indeterminate methods that I covered 👌👌
Great video, really clear explanation!
I think there’s a small algebra error and B_y should he 42.5kN
You made these problems so simple thanks!
Glad to hear it!!! =) =)
isnt there a moment and reaction force at point A?
their is but you can find it after finding the reaction at the redundant support. so first apply force method once you have your reaction use it to find the moment about A
@@Kindramo well yeah you can do that too..I just think having a complete diagram looks more better but that's just me lol
@@flowmaticgaming4892 but how would you find it without first finding your support reactions😅 like yeah you can find it but after using that moment to find the support reaction of the redundant support your moment would just change again. So I’m my opinion it’s easier to just find the reaction first then use it to find the moment.
Hi everybody. Does anyone have the Matlab code of 'Force Method'?
thank you, you are the best in force method
Thanks Amal =)
Can you do this method for a frame please
Hi at the moment I don't have any videos on structurally indeterminate frames, sorry.
You are better than my professor
Ma = 5 kN/m
How so?
Ma + 20(1) - 50(2) + 57.2(2) = 0, Ma = 5????
Oh wow, whoops. You've got the wrong sign for the "20(1)" term, but yes there is a typo at the end of the video. Ma should equal 5 kNm, not 5.6 kNm. I have added a note in the description mentioning this. Thanks for pointing it out!
thanks for the clarification....,I appreciate
This is great at least more on this structural analysis two
Thanks. Helped a lot.
Thanks for watching! I'll upload a 2 degree indeterminate force method problem in a few days too!
Ay= 17.5kN
And
MA= 7.5
Its not 5.6 and 12.5 check it
Excellent
Thanks!! =)
Hello. First of all I would like to thank you for all the hard work you did in these videos to help us students become better on this topic. I have one question. I have a homework, and I should do it with the Force method.It is 3x staticly indeterminate. Could you please take a moment and guide me how is the easiest way of doing it. I will post link to my assignment. Greetings and sorry for bad english.
Link: imgur.com/jcGstD3
Hey Kemo, sorry I don't have any videos on frames. I recommend just looking up some other examples on solving frames with force method and following the process, it's similar to beams.
Ay should be 2.5 kN, i guess
Thankssssss
You’re welcomeeeeee
Talk slowly