OR Gate using Transistors on a Breadboard

This circuit shows the working of a logical OR Gate.
When both the switches are open, there is no current flowing through the transistors and hence the output is LOW. In this state, the LED is OFF.
When either or both the switches are closed, the current flows through the respective transistors to the LED. This causes the output to go HIGH.

[@earlysyed]

U SAVED ME MAN! NO Other video or article could make me understand this. This video was the best.

[@johndessire399]

Thank you, this was very insightful.

[@easwarsendhil]

Perfectly working thumbs up for the video

[@electronics_champ]

Glad you liked the video! Please consider subscribing!

[@mrpovpov298]

Nice work👍

[@muhammadarfan7247]

Perfect ❤
Jzak Allah Khaira ❤️

[@binodkumarmallik4234]

Great work sir, this is so awesome❤. But why this channel is so underrated 😢

[@electronics_champ]

Thank you so much for your kind words! I appreciate your support. Sometimes great content takes a little time to get the recognition it deserves, but with viewers like you, we hope to grow and reach more people in the future. 🌟😊

[@avinavpri]

Can we use 220 ohm resistor

[@Code_code79]

Can we connect anode of led to collector and cathode to emmiter of transistor -2??

[@electronics_champ]

The OR Logic does not work in this case.

[@razeen_128]

Hii.. Can u say how to check output using multimeter without using led..

[@electronics_champ]

Will let you know in a day or two.

[@razeen_128]

@@electronics_champ thanks

[@electronics_champ]

Without an LED, if you connect a multimeter between emitter (T-2) and ground, you will see a voltage of 8.03V when either of the switches are on. This is fractionally higher (8.18V) when both the switches are on.

[@razeen_128]

@@electronics_champ thankuh...

[@adamadness2283]

Is it a npn

[@electronics_champ]

Yes, they are BC547 NPN Transistors