This dude seriously cracked the formula for free money lmao. All he's gotta do is make these videos and college students for years will watch them on a regular annual basis. Man's prolly got a Bugatti w all that TH-cam money
@@88NA it just should have said 'helps' because it was a singular noun...which calls for a singular verb If it were many people helping you, the correct verb would be 'help'.
Love all your videos, your explanations are much more better and simple to understand then my tutors in class. Helped me so much in my studies, thank you ❤🙏
In theory you're correct, but in reality NPN transistors drop around 0.7v at base emitter so the AND gate output never gona be at 5volts with both transistors on, and if bottom only is on there will be some voltage drop on the output because the base emitter current is flowing through the output resistor to ground. This may be as much as 0.6 or 0.7 volts and false trigger another stuff on the circuit if is sensitive enough. I like to do my transistors AND gate by making NAND and inverting the output by another transistor on the top resistor output. Gòod video anyway.
Not a silly question, simple way of putting it - it causes a voltage drop when the switches are closed (since current can flow through them, hence they are not resistant), does not cause a voltage drop when the switches are open (since the switches technically create infinite resistance) and no current is flowing. Voltage drop or otherwise changes the state of the output, hence the importance of the resistor as a regulating mechanism.
Thank you but I have a question. In the AND state, when A is off and B is on, Isn’t there a current from Base of the B transistor to Emitter? Then we have 5v in out.
How I understand it - Current is flowing from the emitter to the collector (top -> bottom). An open switch (points A and B act as a switch) creates an open circuit = infinite resistance, hence no current passes through. This means when B is low (the switch is open -> infinite resistance), there is a voltage drop across B. If there is a voltage drop across B, and you measure the voltage between the output (which comes after B) and ground, you get 0 voltage. The reason you had voltage in the output when there was a voltage drop previously, is because there was no voltage drop at the resistor only at the switch (since the open switch is like the point at which there is overshadowing resistance), the output was placed before the open switch and thus had voltage (potential). The location of the output matters. Hope it helps.
What is the purpose of the resistor at the beginning? Also, in the case that both switches are on, what keeps a why does only a negligible current branch off to the outlet? Were it the same as water, you might expect 50/50 to go to to each branch?
@@nibble1110 Simply put, a resistor resists the flow of current, this means it takes energy from electrons, and when this happens, voltage drops (it uses voltage). Thus, any point AFTER the resistor has a SMALLER potential to do work, so less voltage = voltage dropped. Caveat: IF there is an open switch after the resistor, the open switch does not allow current to pass through it, the open circuit leads to infinite resistance at that point, and the resistor is not 'resisting' any current.
The AND gate configuration shown in this video is not that practical. It is better to use a NAND gate configuration then connect its output to the input of a NOT gate , then its final output will be the output of an AND gate. It's like a NNAND(not a not and gate) which is basically an and gate
Because in real life, there is in fact a voltage drop across a transistor when it's on. This will cause the output voltage to be affected by the transistors that occur before it in the circuit. Having the output voltage be read from above the gates (then it would be NOR or NAND), you don't have to worry about the effect of the transistors on the voltage reading
Correct. This way the circuit is reliable since you can chain multiple gates together. The problem with the shown AND gate in the video is that it will continue to drop voltage foreach gate chained together until the system won't work anymore
Final Exams and Video Playlists: www.video-tutor.net/
Full-Length Math & Science Videos: www.patreon.com/mathsciencetutor/collections
This was ridiculously simple to digest.. you never cease to amaze me 👏🏻
This dude seriously cracked the formula for free money lmao. All he's gotta do is make these videos and college students for years will watch them on a regular annual basis. Man's prolly got a Bugatti w all that TH-cam money
Still at 95k Views. It's a great video but people sadly don't really use TH-cam for studying
@@mariocuric6690 I am doing it!
@@mariocuric6690lol all I have time for with daughter
@@mariocuric6690nah he will get slow views annually because there will always be new students learning this stuff
@@mariocuric6690but college students all the time are like "got my degree from yt
this guy really help me a lot in my education.
God bless you.
Now you just need a grammar tutor.
@@morgancalvi6675 Correct my grammar please
@@88NA it just should have said 'helps' because it was a singular noun...which calls for a singular verb If it were many people helping you, the correct verb would be 'help'.
@@morgancalvi6675 thanks
@@88NA I hope you didn't think I was being a snob...majored in English.
Perfect timing WTFFFF❤❤
Same to me . This week my new semester starts and this is what they thought today...
this is perfect! I'm learning electronics, and prototyping. This is prefect for my learning experience!
I owe you any success I may achieve, you're a legend 👍
Thank you. I'm trying to learn TTL from a book, and the initial gate behavior was throwing me off.
"Current-sinking logic" indeed lol!
Perfect timing. Just started to learn this topic in college. Thank you! 😌
Thanks!
How this guy can be my math, chem and physics teacher at the same time??
He knows all three subjects. You HAVE to know Math in order to solve the equations...at at least the Calculus level.
like as how can we study math, chem and physics at the same time
Love all your videos, your explanations are much more better and simple to understand then my tutors in class. Helped me so much in my studies, thank you ❤🙏
Wow, love the way you teach ❤
It's just amazing
I am having my jee mains tomorrow and this kind of question are so helpful for that
Thanks. After watching your video I am able to make my own logical gates.
Best channel for jee advanced
In theory you're correct, but in reality NPN transistors drop around 0.7v at base emitter so the AND gate output never gona be at 5volts with both transistors on, and if bottom only is on there will be some voltage drop on the output because the base emitter current is flowing through the output resistor to ground. This may be as much as 0.6 or 0.7 volts and false trigger another stuff on the circuit if is sensitive enough. I like to do my transistors AND gate by making NAND and inverting the output by another transistor on the top resistor output. Gòod video anyway.
Thanks for teaching me as a simple then my professor ❤
*Electroboom uploads video about transistors*
OCT: "My time has come"
Brilliant way to explain these ideas 💡 Thank you!
Super wytłumaczone bramki logiczne
is there anything you dont know mann!!!!........you are a top G
This is so amazing thank you for your explanation!
2:35 what purpose does the resistor serve here? Probably a silly question
Wondering the same
I think the transistors deliver a volt and then the current flows through the resistor resulting in the output to have 0 volt but I am not sure
It serves as the load
For Impedance matching
Not a silly question, simple way of putting it - it causes a voltage drop when the switches are closed (since current can flow through them, hence they are not resistant), does not cause a voltage drop when the switches are open (since the switches technically create infinite resistance) and no current is flowing. Voltage drop or otherwise changes the state of the output, hence the importance of the resistor as a regulating mechanism.
this is soooooooo valuable to me thnks a lott❤❤️🥰
All your videos are the best
Very clear explained thank you
Pretty LOGICAL, Sir!
I am super curious to know what your marks were like in high school?? I love your videos and I’m just curious?
Thank you but I have a question. In the AND state, when A is off and B is on, Isn’t there a current from Base of the B transistor to Emitter? Then we have 5v in out.
Unbelievable🥳🎉 thanku sir
8:24 isnt the no current flow in the resistor causing it to have no voltage drop and having then voltage as a result?
How I understand it - Current is flowing from the emitter to the collector (top -> bottom). An open switch (points A and B act as a switch) creates an open circuit = infinite resistance, hence no current passes through.
This means when B is low (the switch is open -> infinite resistance), there is a voltage drop across B. If there is a voltage drop across B, and you measure the voltage between the output (which comes after B) and ground, you get 0 voltage.
The reason you had voltage in the output when there was a voltage drop previously, is because there was no voltage drop at the resistor only at the switch (since the open switch is like the point at which there is overshadowing resistance), the output was placed before the open switch and thus had voltage (potential).
The location of the output matters.
Hope it helps.
Great explanation man!
Jay the Florida pool pump motor repair guy. When Service Calls Longwood approved ! that was good info 2 know 👨🔧JG
Amazing explination, thank you very much
Great explanation. Thanks.
amazing beast you rocked it man
great video very well explained thank you
Excellent video thank you
What is the purpose of the resistor at the beginning? Also, in the case that both switches are on, what keeps a why does only a negligible current branch off to the outlet? Were it the same as water, you might expect 50/50 to go to to each branch?
Hey did you understand? I don't know ty
i dont quite understand how the resistor works. Can someone explain it to me i dont understand how it works nor how it causes "voltage drops"
Did you understand? I don't know what is happening
@@nibble1110 Simply put, a resistor resists the flow of current, this means it takes energy from electrons, and when this happens, voltage drops (it uses voltage). Thus, any point AFTER the resistor has a SMALLER potential to do work, so less voltage = voltage dropped.
Caveat: IF there is an open switch after the resistor, the open switch does not allow current to pass through it, the open circuit leads to infinite resistance at that point, and the resistor is not 'resisting' any current.
God bless you Man.
Can you do a video on how to create linear and quadratic equations using Excel?
Are the tranzystors NPN and PNP woking the same?
Bravo, Bravo!
Insane timing have my exam in a few days LOL
why does he change the resistor location when changing from or to nor does its location matter?
So helpfull❤
Great job!
Can you make a video on automatic differentiation
does he place resistor in AND gate wrong place?
Thank you so much.
Nice information.
5:36 dawg 😂😂😂
hey man can you make a video explaining mos, nmos, pmos & cmos logic ??
Please to the NOT and XOR next
How about logic gates using MOSFETs?
Thank you sir
thank you for this!
Thank you
Thankyuuu so muchhh🥰
May allah bless you hocam
I like light emitting diode
NAND, and OR gates are not same???
Bubbled OR (OR gate with inverted inputs) is same as NAND. But NAND and OR are not equivalent.
THANKS!
w pfp
❤❤
helpful
the NAND gate in this video is actually the AND gate in this other one
th-cam.com/video/JQBRzsPhw2w/w-d-xo.html
so which one is it? I'm confused.
goat
super
Oh
Whats a not gate then?
cool
Is there anything this guy doesn't teach?
First comment ❤️
Poor explanation to to a learner
Two tos
thank you so much
The AND gate configuration shown in this video is not that practical. It is better to use a NAND gate configuration then connect its output to the input of a NOT gate , then its final output will be the output of an AND gate.
It's like a NNAND(not a not and gate) which is basically an and gate
Thats what I heard too, but why is it not practical? Could you explain?
Because in real life, there is in fact a voltage drop across a transistor when it's on. This will cause the output voltage to be affected by the transistors that occur before it in the circuit. Having the output voltage be read from above the gates (then it would be NOR or NAND), you don't have to worry about the effect of the transistors on the voltage reading
Correct. This way the circuit is reliable since you can chain multiple gates together. The problem with the shown AND gate in the video is that it will continue to drop voltage foreach gate chained together until the system won't work anymore
thank you