Mesh Analysis (Solved Problem 1)

Network Theory: Solved Question on Mesh Analysis
Topics discussed:
1) Developing the mesh equations (KVL equation of meshes) for the given electrical network.
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#NetworkTheoryByNeso #NetworkTheory #MeshAnalysis

[@munugotiganesh573]

-(i3R6)-(i3-i2)R4-(i3-i1)R2=0

[@shozabnaqvi2673]

You published this video 5 whole years ago and it is still helping students till this day! Thank you so much for your informative video, I will get 100% on my upcoming test, because of you. Thank you. May God bless your soul.

[@sayan486]

-I3R6-(I3-I2)R4-(I3-I1)R2=0

[@gopalshukla4471]

Neso academy: thanks for lectures

[@reddymanikanta6263]

+R4+R2 ...u keep - R4,-R2 why

[@siddieswarthota1350]

@@reddymanikanta6263 because we taken direction in such a way that current flowing clock wise direction

[@Abhishek-uu5by]

-R6I3+(I2-I3)R4+(I1-I3)R2=0 this is the right ans...

[@kaus05]

@@Abhishek-uu5by isnt your equation same as -(I3-I2)

[@FonkiMonkiDan]

Its been 20+ hours. ive watched countless lecture podcasts and explanations. It could not click until this video, thank you sir.

[@Vivek23_2]

Where are you in 2021 and which country

[@arshkumar5928]

Same here bro this is amazing,

[@subhojyotimondal901]

Thanks a lot Neso Academy for all the free lecture series. And also thank you sir ❤.

[@karthikreddy9824]

thanks a lot for giving the free cost (full content classes ) .Thank you again sir

[@AryanSingh-sn3dx]

Just came across this channel, it has some of the best and useful videos I have seen

[@priyanshigupta1117]

Sir thanks for these videos . In ur videos the basics are explained very well . Thanks again sir

[@longyili8163]

Most helpful video so far. Thanks!

[@kiara6805]

The best lectures i have ever seen

[@souravpati2980]

thnx for video sir,,,, i hope you will add videos of network theory in daily basis....really helpful...waiting for next videos..thnk q very much sir...

[@rarlasebae3412]

Thank you so much sir, your videos about transistor helped me too much.
I want to know if you will explain the AC power and super position for the AC, or did you explained them and I couldn't see them?

[@jaydobariya7602]

Thanks u sir for giving a best content for study 😊

[@edgbaston149]

Thanks a lot Sir. Your videos are really helpful

[@chaitalirane]

Worth watching this video thanks!!!

[@anushuaghosh1790]

-r6i3-r4(i3-i2)-r2(i3-i1)=0

[@ajay....5913]

Topper 🙏🙏

[@kiranoleti3653]

@@ajay....5913 Nvuu endi ra

[@jyothikiran6911]

Andaru toppers a bro ..... Nen tappa

[@kiranoleti3653]

@@jyothikiran6911 what bro I can't understand

[@am_editz9145]

Hi ❤️😘

[@keerthanapodili9075]

This video was so much help ful in understanding the problem sir thank you sir
Mesh 3 EQ I got is
-I3R6-(I3-I2)R4-(I3-I1)R2=0

[@tapaskumardey650]

I too got the same equation.

[@gpcfmt3663]

Thankyou sir ,this video is very useful for me 😊😊

[@aryansinha1818]

Love you sir I was stuck for 3 hours completely irritated, now its all clear. May you risee and shinnee

[@sadmansami2052]

I am from Bangladesh. It is a helpful video. I am grateful to you

[@user-ne5vk5fo4t]

Thank you sir for giving a best content for study

[@DastagiriDibbesha]

-(i3-i1)R2-i3R6-(-i3-i2)R4

[@happyharsha2422]

Sir,can we apply clock wise direction and anti clock wise direction of current in 2 side by side mesh's in a network.if so how to check the polarity of the resistors.....

[@ramkesh4144]

Nice mesh analysis proper method 👍

[@pullepujaswanth5035]

Sir can you solve the voltage source in the first mesh with the current source plz..?

[@muraadmasood2968]

mesh 3: -R2(i3-i1)-R4(i3-i2)-R6i3

[@menglimarrero4296]

Mesh 1 and 2 i noticed that in the direction of loop, all of the resistors are changed to potential drop, if that so, then mesh number 3 must be in potential drop. Pls explain any body

[@user-vx9sx4rw7w]

Thanks sir for these video ,and very good explanation

[@pranaysagar5349]

Thank you sir . Waiting for nodal analysis

[@rimadutta5144]

thanks alot sir, this vedio is really very helpful to understand mesh analysis... thanks again.

[@sandipsolanki7918]

Video*

[@TeluguWebTV1]

Video

[@vidhikumari1425]

Nice explanation... Plz uploaded superposition

[@reficeismail6520]

-R6I3-R4(I3-I2)-R2(I3-I1)

[@prabhakardas4261]

Sir directly can we write the equation in metric form?

[@LexLutrkeima]

just out of curiosity, shouldn't I3 current recombine with I2 and terminate together past the R5 at ground level? if I3 doesnt have a voltage source of its own how is it that I3 is able to circulate on it own?

[@vishalkarmakar418]

Bro its a whole network voltage will flow in evry branch

[@kummathiudaykiranreddy1107]

Sir is it opposite polarity for sharing resistance

[@symbionictitan4074]

Thank you sir

[@upparaanandbabu8495]

Sir we can also write this sir -v1+I1R1+(I1-I2)R2 please tell me sir

[@sreekanth2339]

Thank you BRO

[@tanishnelli8947]

Thank you sir🙏

[@sreekanth2339]

Thank you SIR

[@anthonykioko5306]

✔✔good lecture sir

[@xavierstudios8562]

your a good man

[@ashwinrajpanicker3413]

Thanks sir.

[@recreativeandinformativech8341]

Best lecture

[@cck1496]

Thanks.... What is the Physical application of such analysis in real world?

[@SaikatPodder]

Sir will I complete network theory with in 2 months?

[@dharniesh3651]

YES SIR THE COMMENTS ABOVE ARE TRUE. I ALSO GOT BENIFITTED

[@menglimarrero4296]

Neso academy
sir where is the link of answer mesh number 3?

[@aquariumandbirds2382]

Can I interchange the mesh number ?:

[@charandeepkusupati2399]

-I3R6+R2(I3-I1)+R4(I3-I2

[@viveksharma2733]

How do you know that I 1is greater than l2

[@Indian_addy]

Amazing

[@jatinchauhan6902]

Mesh-3: I3R6 + (I3-I2)R4 + (I1-I3)R2 =0

[@farimahaminzare8884]

Can anyone explain Why I1 is larger than I2?

[@bhagyabuch6037]

I3R6+(I3-I2)R4+(I3-I1)R2 = 0... eq.(3)
Can I write this?
And also for the first 2 meshes:
-V1+I1R1+ (I1-I3)R4+ I2R5 = 0... eq.(1)
-V2+(I2-I1)R3 + (I2-I3)R4 + I2R5 = 0...eq.(2)
I just assume the reversed for the voltage drop and voltage rise and it is okay. Isn't it?

[@sikandarkhan419]

mesh #3:
-i3*R6-(i3-i2)R4-(i3-i1)R2 = 0

[@emmanuelmwaba8483]

-IR6-(I3-I2)-(I3-I1)R2=0 This was my answer sir

[@killergamer7125]

R2(i3-i1) - R6i3 - R4(i3-i2)

[@atharmoin1]

thx

[@mohamedashfark8351]

-r2(i3_i1) - r6i3-r4(i3-i2) =0

[@subhojyotimondal901]

-(I3-I1) R2-I3 R6-(I3-I2) R4=0

[@jitendrasingh-ey4gr]

while calculating no of equations why we are not considering simple node ??? sir kindly explain

[@jitendrasingh-ey4gr]

Neso Academy Thank you sir

[@venkatesh3148]

Current will not divide same current will flow

[@rudranilparui2455]

-(i3-i1)R2-i3R6-(i3-i2)R4=0

[@Hems28]

Which White Board Application are you using?

[@rajeshkumarorg]

How to contact u sir

[@SameerKhan-bt4vj]

-(i3-i2)R2-i3R6-(i3-i2)=0

[@user-vx9sx4rw7w]

-R6I3-R4(I3-I2)-R2(I3-I1)=0

[@Shashankhere_]

-(I3-I1)R2-I3R6-(I3-I2)R4=0

[@ankushsingh792]

Mesh 3: -R2(I3-I1)-R6I3-(I3-I2)R4=0

[@Anujsharma-jo7ql]

-I3*R6 - (I3-I2)*R4 - (I3-I1)R2 = 0

[@rajorshimandal7433]

-(I3-I1)R2 -(I3-I2)R4 -IR6 = 0

[@Siddu.Sivva28]

-I3R6+(I3-I2)R4+(I3-I1)R2=0

[@opbhai3091]

-i3R6-(i3-i2) R4-(i3-i1) R2

[@pawankushwaha8571]

Please mesh 3 btao

[@user-nv4np1eg8g]

-I3R6-R4(I3-I2)-R2(I3-I1)

[@phanikrishna0000]

-i3R6-(i3-i2)R4-(i3-i1)R2=0

[@tariquekhan7717]

-I3. R6(I3-I2) - R2(I3-I1) =0

[@Bksi_swm14]

(R2+R4+R6)I3-I1R2-I2R4=0

[@soorajdsharma]

-i3R6-(i3-i2)R4-(i3-i1)r2=0

[@ashokchatla9475]

-R2(I3-I1)-R4(I3-I2)-I3R6=0

[@Technical_ktk1]

That's great

[@thegoatoffootballmessi]

It is simple

[@lathasrichavala155]

-i3(r6)+r4(i3-i2)+r2(i3-i1)

[@prabhjotsinghdhaliwal9772]

ryt

[@shamshad126prottoy6]

@@prabhjotsinghdhaliwal9772 how brother?how the + came

[@hardikparashar2799]

R2I1-R2I3-R6I3-R4I3+R4I2=0

[@ln9998]

i3R6-(i3-i2)R4-(i3-i1)R2=0

[@anuragdas7252]

I3R6 - (I3-I2)R4 - (I3-I1)R2 = 0

[@shajibsarder4875]

R6I3+R4(I3-I2)+R2(I3-I1)=0

[@muhammadfaizanahmed4356]

For Mesh3 : -R2*I1 -R4*I2 +(R2+R4+R6)*I3 = 0

[@Duckman793]

-I3R6-R4(I3-I2)-R2(I3-I1)=0

[@mdsajjadattari6254]

Can't understand point iv

[@s.m.senses7199]

🙏❣

[@demonking5934]

-(I3-I1).R2-I3.R6-(I3-I2).R4 = 0

[@apurbamandal6535]

-I3R6+(I2-I3)R4+(I1-I3)R2=0

[@jamwithme4725]

It should - R4 and -R2 because you will assign another polarity just like what we did on the second mesh current.

[@sportsuper9489]

mesh 3 =i3r6+(i3_i2)r4+(i3_i1)r2=0

[@aniketshede383]

E1(I3-I1)-I3.R6+R4(I3-I2)=0

[@nileshkshirsagar7827]

I3*R6+(I3-I2)*R4+(I3-I1)*R2 = 0

[@shekharverma2675]

-R2 (I3-I1) -R6 I3-R4(I3 -I2) =0

[@percybyssheshelley9403]

i3R6+R4(i3-i2)+R2(i3-i1)=0

[@SuperKishore108]

-R2(I3-I2)-I3R6-R4(I3-I2)=0

[@phanindrareddy4885]

Neso Academy
I3_i1

[@sahil9907]

Why can't I see the comments

[@sambitsahoo1123]

homework ka solutions bhi diya karo kabhi