Combustion Analysis of Gaseous Hydrocarbons

[@zacharialushika85]

Very good, we need teachers like you!!!!

[@musangofrancis7677]

You have no idea how my chemistry teacher confused me on this one, our teachers prefer teaching us to memorize expressions rather than understand where they come from, thanks alot

[@siyamrafiq8162]

Thanks been stuck on these type of questions for hours.

[@leilani34]

Wow! Thanks, you made it simple more than my teacher

[@amryu3258]

Yeah, some teacher just don't have the talent

[@luciadroplet6338]

Thank you so much sir this was so helpful compared to my teachers 😭

[@fareedasamer3311]

You’re a great chemistry teacher, much love

[@ChemistryGuru]

Hi Fareeda thank you for the compliment! :)

[@ceejaysvlog3558]

Dude's really good... keep up the good work

[@bunnybunny4930]

THANK YOU SO MUCH FOR THIS!

[@ChemistryGuru]

Glad it was useful!

[@melisapryce7370]

You are indeed a God sent. Thank you so much

[@bazeketaali5701]

great teacher

[@bazeketaali5701]

♥️

[@nimeshpalungwa1716]

Thank you for giving the best idea for solving this equation...

[@teddy543]

Thanks for the video! Is it possible to have a complete combustion reaction in which oxygen is actually the limiting reactant?

[@ChemistryGuru]

if oxygen is limiting then we will not have complete combustion. So for combustion of hydrocarbons or organic compounds we always assume oxygen is in excess since it is available from atmospheric air.

[@amryu3258]

Nice and simple.... Thx for helping

[@ashamgunya75]

Thank you sir 👍👍👍

[@patriciaakwero993]

Thanks a lot.I finally got that concept

[@ChemistryGuru]

Thanks Patricia! Glad the video was useful :)

[@siddhanthduggal6728]

thanks you so much!!! had been struggling since a long time

[@ChemistryGuru]

you are welcome Siddhant! Glad you found it useful :)

[@vulcan8288]

Will this come in jee

[@RomarioBryan-y1i]

i was using this method but i got x=9/2 for the first two fraction and this kind of complicate things. what should i do

[@jmvw9669]

bro you explained it way better than my teacher... arigato

[@ChemistryGuru]

thanks for the compliment! :)

[@葉赫那拉榮禹]

It’s very useful video. Thx for sharing!

[@ChemistryGuru]

You are welcome! Glad you find it useful! 😊😊

[@infinitefutbol8054]

Really helpful thank you

[@hauwaujidda4498]

Amazing

[@hauwaujidda4498]

Pls how is it c2h4

[@ShortsBaba233]

❤️❤️❤️ nice video man!

[@starlight1991]

Sir, I have a question to ask. How can I find the grams of carbon and water if the given are grams sample of hydrocarbon, pressure, temperature, and volume? Thank you sir

[@vijaygupta6067]

Why take ratio of co/co2 to check combustion in LPG stove?

[@hauzeeb3175]

Thank sir it was helpful

[@raphaelfarrugiawismayer3521]

hey, sorry for the inconvinience but how is y=4 in the last problem if 3x4 is 12 -2 is 10

[@ChemistryGuru]

for the last step
2 + y/4 = 3
we bring 2 to the right hand side
y/4 = 3 - 2 = 1
then multiply both sides of equation by 4
y = 1 x 4 = 4

[@drmazensaad]

Thank you very much

[@bambi3886]

sir i have a question to ask. if the question ask the volume of water formed b4 the reaction, how should I answer ?

[@ChemistryGuru]

The volumes we are interested in are for gaseous species, since we are using Avogadro's Law to compare mole ratio and volume ratio of gases. If the question mentions standard conditions or at room temperature, then the only gases we focus on will be reactants CxHy (hydrocarbon) and O2, and product CO2. Water will be in liquid state so its volume is not important

[@chathuk6122]

@@ChemistryGuru But sir, would it be possible to just find the volume of water produced by converting from ml of C2H4 to ml of H2O using the molar and volume ratios? Or is that not possible without something like the molarity of the gas? Thank you so much for making this video as well.

[@ChemistryGuru]

@@chathuk6122 we cannot compare volume of liquids since Avogadro's Law is only for comparing volume of gases. To determine volume of water we need to find
(1) moles of C2H4,
(2) compare mole ratio to find moles of water formed,
(3) calculate mass of water,
(4) calculate volume of water using density where density of water is 1 gram per cm cube

[@chathuk6122]

@@ChemistryGuru Ohh, that makes sense. I didn't know that the volumes weren't interchangeable with their state in this Law. Thanks for explaining sir.

[@Aarvindsundar]

Hi chemistry guru , i have a question . how will you solve the question if the question doesnt specify the volume of excess oxygen ?

[@ChemistryGuru]

Hi Aarvind for questions that do not specify the total volume of oxygen but the change in volume is given, we can use the following expression:
Change in vol = vol of CO2 + vol of H2O - vol of CxHy - vol of oxygen reacted
This is simply the change in vol is equal to volume of products formed less volume of reactants used up.
If H2O is liquid at room temperature then vol of H2O will be zero.
Hope this clarifies! 😄

[@bavirisettygopalakrishna4041]

Thank you

[@tysonboygaming4756]

I'm from india

[@hauwaujidda4498]

I think is c2h3

[@enelesszulu7822]

Please stop calling yourself a chemistry guru😑

[@dilanjamanorathna1739]

Thank you so much