Empirical Formula from Combustion - Carbon, Hydrogen AND oxygen

[@456chadt]

These videos are making gen Chem so much easier

[@bbbristian]

You are god sent . Who tf disliked your video?

[@lszpunar]

Thank you, we are both bosses! After going to office hours, your just reinforced the reaction ratio!

[@shreyashivkumar8484]

Thank you !! You explained this so well! :)

[@aliaaisyahabdulaziz8813]

tq so much!!!!! it helps me and saved my life

[@Muhammad_Juned]

Now it is proved that chemistry can save the life

[@nadineahmed1249]

This video is so so so helpful and has a great explanation!!

[@BksBkss]

How many significant figures do I need to round off.

[@opufy]

amazing video, learning general chem at cegep now

[@MrMonodude]

God bless your soul

[@sohibelhakim3154]

What piece of information do we need in addition to this to be able to workout the empirical formula?

[@jamesgonzalez9782]

The molar mass of the compound

[@beckseamons]

@@jamesgonzalez9782 No, I think molar mass of the compound is only needed to find the molecular formula

[@onionknight1130]

you save my life , thank you

[@ismailmajid9657]

How is the number of moles of carbon the same as the number of moles of carbon dioxide

[@ramsha-ky5fc]

1 mol Carbon dioxide contains one mole of MOLECULES, which contains one mole carbon ATOMS, and 2 moles of oxygen ATOMS

[@baldeojohnvernonb.7113]

Thank you! You've been helping me a lot

[@aradhyasinha6616]

Is it allowed in your country to use calculator in exams

[@nurulfarahaimi4160]

Thanks for the help.

[@johnbefth6520]

This is a Great video!

[@Muhammad_Juned]

Great explanation.
Thank you👍

[@CyberTronics]

Why cant you just add up moles of oxygen to get total moles of oxygen present???
Really confuses me this!!!!!!!
0.032 x 2 = 0.644
0.644 + 0.405 = 1.049 moles of oxygen present.
.... I have done this right?

[@jerish2125]

Hamza Abid look your wrong

[@roderickmobley7955]

Typically with these problems, you don't know how much oxygen gas is used. The gas is in excess, so the amount of oxygen that is in the original compound and the amount of oxygen gas you are adding is unknown. But since you know the mass of the original compound and can find the mass of both carbon and hydrogen, you can easily subtract those masses from the mass of the original compound to find the mass of oxygen.

[@lucaskasssab4543]

ur a real one

[@ifyousayso7630]

Thank You 😊

[@MustafaErkaya]

That was an awesome question.I totally understood everything ! Thanks NATE !

[@maryamsheikh6919]

THANKS!

[@eliasmuseto6248]

Thanks 👏🏽👏🏽👏🏽👏🏽

[@kingcuber7796]

thank you so much saved my ass for chem test lol

[@hamnashafqat5529]

Thankyou soo much man😍

[@sofjana1326]

youuuuuuu savedddd my lifeeeeee tu boft dita 1mijjjj😘

[@raashidjournalist2324]

Thanks

[@toyinatofarati5512]

Thanks Boss

[@yasodha-ei4eb]

We Indian need to calculate our self

[@nehachauhan5800]

Thanks sir

[@Nazcherry]

You save my life tnx💋

[@vanessamwenya1269]

Thanks man🤦🏽‍♀️😁 this was really helpful

[@salamaali4842]

Thanks!! I thought my method is wrong but turns out my teacher gave me some random masses which results in an impossible em. equation🤦‍♀️

[@abdullahbinaslam902]

OTIANOOOOOOOOOOOOOOOOOOOOO

[@sunnyday7935]

you made a mistake when finding oxygen, when something completely combusts, oxygen gas is required, and oxygen gas comes in the form of o2. so all you would have to do is divide the grams of oxygen by 32 instead of 16

[@roderickmobley7955]

Your comment is wrong. You are finding moles of oxygen atoms, not moles of oxygen gas. Since you are looking for moles of oxygen atoms, you would only divide by 16 g.

[@davidomondi4079]

Reply after one Yr 😂😂