How To Solve Any Projectile Motion Problem (The Toolbox Method)
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- เผยแพร่เมื่อ 29 ก.ค. 2024
- Introducing the "Toolbox" method of solving projectile motion problems! Here we use kinematic equations and modify with initial conditions to generate a "toolbox" of equations with which to solve a classic three-part projectile motion problem.
Millish's music available on iTunes: itunes.apple.com/us/album/mil...
I had tears rolling down my cheeks! Never in my life have I seen a physics problem laid so beautifully and elegantly in my life before!
SURELY YOU'RE JOKING, MR. SAINI!
Jesse Mason I'm serious.
I am flattered then. I spent a lot of time on this one. :)
Watch physics wallah
First of all, wtf. Second of all, is your Physics teacher THAT bad
Start every projectile motion problem with the Displacement Equation (DE) and the Velocity Equation (VE) for both horizontal and vertical directions. Next modify the equations to reflect your known values - creating a toolbox! Then solve for your unknown quantity. Good luck!
You are way better than my teacher who just provides cheeky demonstrations and makes us learn it all ourselves.
I just found a simple way.
Distance = Horizontal velocity
x
(Time to decelerate vertically + Time to freefall from height)
my teacher lol
I'm stuck with this kind of guy. don't know why physics teachers are so garbage
feel like you're talking about my teacher lol
Dude I think we have the same teacher
I wish I could give you the money I give my useless professor.
+FrostByte how does he get 5.68s? what is y0?
Sholla Hanafiah y0 is displacement bro taken in projection cocepy
is it 100m?
That makes two of us.
Yup. I was right along with him, then he skipped solving the quadratic, and I'm out.
*Don't use a yellow marker*
Good suggestion.
Thanks! :D
Asante sana
YEAH AGREE
Dat yellow tho
@Anthony Willson: If you can tolerate me sounding drunk, click the Gear button below the video and set me to 0.5 speed.
i did this. and it totally made my day! Thanks.
Awesome reply :D
Jerry Li yo, are you studying for the PQ as well? Good luck!
Jerry Li Thanks. =)
It reminds me of my typing teacher in grade 10. Mr. Dudley was a great guy but he smelled funny and I didn't suffer from anosmia.
Nice vids, thanks!
@Shreshth A: "Make everything as simple as possible but not simpler." -Albert Einstein
To find Yo without having time though, don't you need another equation, V^2 = Vo^2 + 2a(X-Xo)? I think that would be Voy^2 + 2a(Yo) = 0 simplified with your variables
MissPielops
Yes, you're absolutely right in my opinion considering the formula you have given is only when the acceleration is constant, which in this case is -g.
3d834 To save time and space. (Sounds epic.)
Jesse Mason at the Range parts when your solving for the components of time isn't it -5.68 and 3.59 instead of the other way around?
Jesse Mason Thank you so much! Your video wasn't boring like other and it really helped!!!! ^_^ Coming in from Trinidad and Tobago btw :)
This was so helpful! You explain things so well, make it fun, and make the whole video aesthetically pleasing. Thank you so much!
13 min video taught me more than a three hour lecture...
Glad that you found the toolbox method useful, Dean! Feel free to share this video with your teacher. =)
bro u alive?
Combing textbooks and the internet for an equation specific to your situation is usually a frustratingly fruitless endeavor. Instead, start every projectile motion problem with the Displacement Equation (DE) and the Velocity Equation (VE) for both horizontal and vertical directions. Next modify the equations to reflect your known values - creating a toolbox! Only then will you have the right equations you need to solve your problem.
This has helped me so much!!! Hello from Malawi😁
Jesse, you couldn't have made this problem any simpler! I've been struggling with Physics and had this exact same problem on my exam. Thanks alot! Would love to see more videos from you. Cheers.
Remember that time I fell in love with a video and the clarity it brought?
+Chelsea George I do, I do! Cheers from Detroit, Chelsea!
Never in my life has someone taught me projectile so well. Thank You, sir. May you live long and bless us with more of these sort of videos.
Students needs Teachers like you.. good job. keep doing..
Thanks, Rao!
this was EXTREMELY helpful, and was presented way more clearly than my physics prof! thank you so much!
My pleasure, Kevin!
This is a great video Jesse! I'm taking my first physics class ever at a community college and your toolbox method really solidified what I've been learning in school. Thanks!
You are my new BFF!!!! You may be saving my bacon for my midterm on Monday! Great vid! Thanks for being here!
Cassandra Siegfried omg same
Glad to help and hope you crushed that midterm!
Thank you, Mayson!! That means a lot to me since it required an extra - oh, I don't know - dozen takes (attempts) to get it right!
Brilliant! I retired from teaching in 2018 at a high school in Cape Town. I was born in 1955. My dad was a physics teacher. I also taught physics for a while, but your teaching is a stunning revelation to me! Thank you very much, Prof Mason.
You made physics understandable for the first time in my 5 years of university life! God bless you Jesse!
You're welcome, Sravya! Hope you did well on your test.
Jesse Mason can you improve the quality of you video please i cant understand it
@@tonibautista4439 there's nothing wrong with the vid, maybe slow it down a little on your end or pause every once in a while. the problem is with u not the vid itself
I'm really confused as to how he got his t values. I plugged the equation he used into wolfram alpha and got an answer of 3.733
This helps me so much with studying for the MCAT! I forgot everything until I reviewed this video. Gets to the point!
This video honestly cannot be more helpful than it is... Thanks so much you made projectile motion problems a lot easier for me. Keep doing what you do best!
I'm flattered, Kewal! Best of luck with your studies.
Thank you sir. While I have undoubtedly ruined any chance of successfully completing my physics exam by putting my issues off until today, this video will certainly help in my quest for a passing grade!
Thank you so much! This extremely helpful, neat, well planned and laid out.
I'm struck by your praise. ;)
Reviewing for a physics certification test...THANK YOU!!! You helped make sense out of all the formulas in the toolbox! Instead of trying to memorize these formulas, you helped me understand where they come from! Yay logic!!!
It's 1 o'clock in the morning, I've downed 3 red bull because I have an assignment to hand in 12 hours that I haven't started. This vid has just helped me solve 4 out of the 7 task. Thank you sir for making my life easier
You rock! Thanks for taking the time to make this vid!
For peak height, there's an equation I find easier to use in this case: 2ad = V^2 - Vo^2. And it become even easier because V = 0m/s when finding peak height. a = -9.8m/s, d = the peak height. Hope this helps :)
I agree. The toolbox is cool but I feel like it overcomplicates some things, especially if you are timed on a test
I was breaking my head over this but after watching this video all everything is all crystal clear now ! Keep up the good work!
Hi, dude
Such a great video to refresh old days. I'm an engineer, and If I had watched videos like this when I was in my first semester, I would have been one of the top students in the class.
I say hi from Colombia, the best paradise in the world.
I just watching this now and in 15 minutes I have a test on this. I LOVE LIFE!!
i am listening to this a day before my physics exams
Wanted to let you know that this video is one of the most helpful videos I have ever watched! Thank you so much.
I was forced to watch this video for a physics class. I was prepared for the worst. As it turns out, your video is extremely informative and even fun to watch!! Thank you very much for this helpful teaching tool :D
Thanks so much! Made my day knowing that I can understand this concept a lot better now (please tell me that you're a teacher- you're definitely a lot better than mine!). Just a quick question, the formula you used was s=1/2at^2 + vt + s. Isn't the formula just ∆y(or s) = ut + ½at^2??
I was also stumped on this for a while. He adds the S to the left side of the equation because it is a problem where the projectile is launched from a ledge. Therefore we need to add the height of the ledge to the vertical displacement.
YOU HAVE SAVED ME THANK YOU SO MUCH
I helped you. You saved yourself. Nice work, Nani!
Thank you so much. $ for college tuition is worthless when you have a teacher that doesn't explain things well. This was my second time taking physics and I have an exam tomorrow and did not understand projectile motion. The way you explained the process was clear and concise, and the effort and production that you put into making your videos neat, informative, and short at the same time is awesome. Really cannot thank you enough!
Thank you for the kind words, Jacob. Hope you crushed today's test!
An extremely useful video, especially a day before your actual University tests. Thanks for removing my doubt about projectile motion..
7:22 at the moment of imapact how is the vertical displacement = 0?
Because at impact, the projectile is already landed at land which is at the x-axis, wherein the y is 0. Correct me if I misunderstood the question.
@Dave Henning Yes, the displacement is -100m, but because of where we set the origin of our x,y plane, it's position would be indicated as 0m. Remember that it started at 100m.
WOOOOHOOOO I actually get it! Some people like you are gifted in their ability to teach!! Thank you this method is so perfect
+Nighat Ansari Awww... thanks, Nighat!
Yeah.
Have my edexcel as level physics unit 1 tomorrow. This video helped me with projectile and i got what icouldnt get for months. Thanks!
this is the most useful video I have watched for AP Physics! Thank you so much for being very thorough!
awesome man ...who the hell are you .....love to study from you
I am Batman, no wait, I am Jesse Mason.
that yellow tho
i kno, bro. i kno.
Jesse Mason you still the man tho
Everyone is upset about the yellow when it represented the easiest thing which was gravity lol. I get it though it was bright.
What a nice and structured explanation! I wish I had this kind of video's 25 years ago. It would have made my studies a lot easier even though I passed all my exams. I just wanted to calculate something and after 25 years I had forgotten most of this but now it's all coming back.
This is the first time I have actually been able to understand this. Thank you so so much!
At 0:57, when you turn on captions, that tune is actually Tchaikovsky not Pachelbel.
"Take 'zat, Pachelbel." - Pete T. (Get it? Because Pachelbel's... cannon! Eh?! I'll just let myself out...)
The magnitude of g is negative, Ian!
Amazing explanation that helped me understand my college physics lecture. Thank you for sharing! I wish my college professor were as good as explaining the 2D motion problems as you explained them. Thanks for your help! Hoping to pass Physics this college semester and your video helps clarify some concepts that I had been struggling with.
i tried to do this on my own but when calculating the time, the numbewr inside the radical was negative, (104.4-2000) ?? what have i done wrongg? please someone help me out with this
I was listening to this in the background, so all I could think of was:
Visa bosa why? Visa bosa bex!
LOL
🤣
mad facts visa bosa x visa bosa y
great video but I couldn't see the yellow marker
thanks - if you turn your monitor upside down the hue saturates and the yellow becomes much more visible
Extremely Helpful! I understood the concepts taught in class but putting into use became 'mind blanking'. Thanks for making this usable for me. Cheers.
I love your explanation using the toolbox never did I think I'll ever understand projectile motion.
that yellow marker fucked me up
+jrpg0630 I know, right?
+Jesse Mason Thanks though. Really helpful!
+jrpg0630 Glad to hear it!
you lost me after the first 1min and my physics half yearly is tomoz rip me
Hahaha how did you do?
Miss Spectator 13%
feelsbadman rip IB physics exams coming up in about a week :/
@Donald Trump yeah no wonder orange.
thank you trying to teach my grandson how to solve projectile problems for his A level physics, English AQA. Your Video was excellent brought everything back after 30yrs since I taught this topic. Agree the yellow marker was rubbish but your explanation was life saving. Thank you.
Learned more from this 13min video the I did listening to my 2 hour lecture. You're the best!
Thanks, jmc - good luck with your studies!
I can't see the yellow writings clearly :/
When writing text the camera over exposes the yellow sharpie making it really hard to read. Please use another color. Other than that this is awesome.
Will do. Thanks, Jerry!
I appreciate the help, mate. I literally used this video whilst doing an online test. Thanks!
+Babooshka00 You're welcome Babooshka!
Spent an entire day going through videos on projectile motions. Wish I had watch this one first! Well explained!
Thanks so much, Mr. Lennon! Have a great Thanksgiving!
@@JesseMason Thanks and same to you, professor.
I was on the edge of pulling all my hair off because I couldn't understand projectiles. Thank you so much for this! (from the Philippines
My pleasure, Eli!
Philippino
great goddamn video
Thanks, ODB!
hi bro. does it OK to use same tool box for other projectile motion problems even if the problem is different? thanks
The systematic and beautiful way of solving a problem.
I had trouble with the quadratic because my TI84 Plus Silver requires parenthesis before the square. So (30sin(20))^2.
so...
(30*sin(20) - sqrt(30sin(20))^2 - 4(.5)(-9.8)(100)) / (2(.5)(-9.8))
Hope that helps somebody else.
Thanks for your help I was using positive for gravity which gave me math error
Looks like you helped in other ways too
@@dontbeserious5153 same!
7 years later does he still reply to comments?
My vanity knows no bounds.
@@JesseMason Good video. Just one thing: magnitude is never negative.
@@jlbenson I used to have an annotation that pops up with this correction. I have no idea where it went. Thanks for letting me know, John - will look into this!
Thank you for the great explanation! It really helped me a ton. I was lost trying to figure this out by myself. My professor told me to read the book and that didn't help much either but you video was a game changer for me. Thank you again!
This really helped me before the night of my Physics Exam and removed some of my confusions
. Thank you ! ^^
why my book states that -1/2gt but yours is like positive 1/2gt
***** thank you! :)
i still don't understand why the acceleration become positive because acceleration in earth in always negative g, or is it?
Depends on the direction of motion I think. If you are moving away from the centre of the earth (up) gravity is not helping you. Whereas, if you are moving towards the centre of the earth (down) gravity aids you. Also depends on how you set the directions, which you should do for every physics problem.
Slow down you were talking really fast, but good job.
Just slow down the video
how is he getting the time from the quadratic formula i plug in the values and I keep getting a negaive number in the radical
This's probably the easiest and funniest way of teaching I've ever experienced!. thank you, sir.
I feel like I’m about to have a nervous breakdown god why did I have to take physics
Yellow writing! gah!
Great vid though!
I would think you'd like yellow, Pineapple. ;)
@Gamming Lab If I had a dollar for everytime someone commented on that yellow marker...
Honestly the best educational vid by far! It made you pay attention w/ some comic relief, therefore you learn!
You are saving me from drowning in physics with this big help and for that, thank you so much! I am into the 3rd week of my physic class, my first one since 07 and I started to question myself about my choice of career. However, I don't give up and look for as much help as I can. Besides Khan, your is the next best so far.
Next best? I'm the NEXT best?! KHAAAAAAAAAAAAAN!!!!!!!!
That just made physics 99.99% easier
Gosh SLOW DOWN!!! are you in a HURRY or something? I have to like repeat it again! but it's worth it. :)
Gear button up top - take it as slow as you'd like!
Love the way you put the equations together in the quadratic equation...
This is amazing! I'm having a hard time understanding Physics problems like this and this really helped me a lot! thank you!
yeah imma just drop outta college now I guess
if this isnt me right now lol
stopitidontlikeit yeah you might not want to pursue something in steam if this doesn’t motivate you. However, there’s a huge amount of majors out there! Just find the right one for you! Or maybe a technical job is your deal?
sir you are genious but sir what to do when the projectile is not on a given height
+sourav ghosh
You can just set the initial height to zero, and proceed from there.
+Sourav Ghosh Pretty much the same thing. List all the horizontal and vertical competent information listed downward, SUVAT. Some information is already known, horizontal acceleration is zero whilst vertical is -g (given that 'up' is taken as positive). Also, at the maximum height final velocity is zero (or initial if considering the right hand side). Then select the correct equation with the variables you know and one unknown. Give me a example question if you want.
So how would I calculate the angle of impact on a parabolic trajectory? If I were given a ballistics chart based on known drag coefficient spec?
Does this tool box help me answer other kind of projectile motion questions? (for example: a soccer ball is kicked at angle across a plain field, find the range and the peak) (I know it says any kind of projectile motion in the title but i just wanted to ask.)
Watching on mobile... Damn cant see.. And you use yellow marker... Ouch my eyes hurt.. :(
Sorry, Ian!
What value of initial y would I input to get t? From the 3rd equation?
dude, you're a life saver! if my professor was merely half as good as you, our class would be filled with physics geniuses.
+Gabi Paczolay Ha! A high compliment highly enjoyed.
How do you find the launch angle if launched from the ground where the projectile reached a range R equal to the max height H? No other values are given.
What do you do if it asks for the minimum or maximum angles for the projectile to clear an obstacle of given height a given distance away?
Wow! You're really talented. You find the way to make things easy and funny with the right concepts. Thank you so much. You should continue making more videos like this, your "how to solve..." are fantastic!
I swear to God I've never thought that i will understand this unit but u made my day
Your comment made my day, Sandrine. Cheers from Detroit!
Im not fully getting the exact times. I understand the process but numbers dont match out can anyone provide me with some numbers for the quadratic formula portion just to compare.
Im confused on the time equation/ what do you substitute for the Yo in the quadratic formula?
This was incredibly helpful, and I appreciate that your video is so well made,i cant stand to be taught something wile that person try's their best to wright/draw it out with a mouse!
I have my first Uni test on Wednesday and I know that my life would have been way easier if I had you as my physics teacher! Thanks for sharing your knowledge and great sense of humour.
From New Zealand!
Aidan Mcmanus I was just looking at a globe saying "I want to visit New Zealand someday"! So glad my video(s) helped you with your test, Aidan. Good luck with the rest of your studies. All the best from Detroit!
THE BEST 13 MINUTES SPENT ON PROJECTILE IN MY WHOLE LIFE