Horizontally launched projectile | Two-dimensional motion | Physics | Khan Academy
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- เผยแพร่เมื่อ 28 ก.ค. 2016
- In this video David explains how to solve for the horizontal displacement when the projectile starts with a horizontal initial velocity. He also explains common mistakes people make when doing horizontally launched projectile problems.
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Hopefully the cliff diver doesn't ignore air resistance lol
If they do ignore it, then that's pretty impressive.
To those are intrested in an in-depth analysis of the physics and the gometry of teh projectile motion, with simulation and visualization I recommend:
th-cam.com/video/HPehCUv6bEY/w-d-xo.html&ab_channel=Math%2CPhysics%2CEngineering
I'm watching this the day before my physics exam lol
how did u got?
lmao fuckin same HAHHAHAHHAAH
Im watching this just minutes before final exam
I'm watching on the day of exam, I have 2 hrs left for the exam
right there with you lol
i swear i understood everything thing more than the class
I am such a visual learner and I do online school so it's hard for me to teach myself some things especially in physics. This really helped me, i appreciate it.
3 years later and all we have is online school
@@oneagainsthumanity7893 this person is probably in college now😪
@@josephpate7646 Damn i never thought about that 🤭😔
U clearly understand students soo damn well mate. My mind is oficially blown by your teaching.. thnk yu mate
why arnt my physics teachers this good?
Looks like your English teachers aren't the best either.
Lol....same
Your profile picture makes you look like you're 5. There's literally no way you're in physics.
Svensk Gamer that could be his son -.-
@@MsOluyemi or his brother
“They REAAAAALLLY want to plug in 5m/s as the velocity in y; but don’t do it, it’s a trap.”
I like this dude already
"People are just *dying* to stick that 5m/s in there..." 😂
Thanks! My physics teacher bores me to sleep and I end up learning some of it on my own time. Wonderful explanation!
This teacher is better than my teacher, finally someone explain this with human language, and also this teacher is fun, dont try this at home lol
Words cannot express how much you have helped me. My gratitude for you is endless.
Thank you so much!! I have a physics test tomorrow on horizontal projectile motion and you explained this really well
I am in AP physics this year and the teacher blew through the first few “recap” lessons, I didn’t take any prior physics class so I’m in a loop lol. Very well explained!
Hey thank you for this video & explanation! Really helped me in reviewing for my physics quiz!
Lmao I love this! I’m in the library without headphones, and this so amusing with no sound and the captions on because of the humor. Thanks for the help!
Thank you so much for this! 😭 my school doesn't do lectures but instead just give us notes. This topic, they didn't really elaborate about this one and tomorrow is our exam, FINAL EXAM. 😭. Now I understand everything about this now 😭
Great video. This just helped so much! I was having such a hard time with this. Thank you!
This guy litterally saved my grade. I am a freshman in highschool. Im not very smart but the school still decide to put me in physics. I am so lost all the time. It also doesnt help that my teacher is kind of bad at teaching. I think she might have dementia. REgardless thank you so much for this awesome video you really helped with understanding horizantally launched projectiles.
you save my night! thanks a lot!
I found this extremely helpful. I really appreciate what you guys do. Thank you
Really helped me, got my a in the exam! :)
thank you so much, this really helped me finally understand this
The most open person ever. YOU ARE THE BEST, DAVID
Thanks for the refresh!
BASED DAVID!!! Thank you
How do you do this if you’re given the range but not the y value
Thank you this was very helpful!!
This has to be the best video ever.
Thanks this was very helpful
Got a test tomorrow and I have no idea what I'm doing, I'ma watch this and hope it helps
What a beautiful video. Explained so well. Great teacher.
Thanks. It helped me a lot
great video ,i understood everything ☺
Thank you. This video helped me a lot
Thank you.
This really helps me.
Thank you so much.
aweosome man. very good explanation
Such a good Explanation 👍👏 It helped tnx 😊
Thank you very much for this.
BEST EXPLANATION EVER!!!
I finally get it . Thank you
Thank youu
How would we determine the angle at which the person hits ground at various distances?
this is great thanks!
Basically use eqns of motion and apply proper sign convention. For other cases too, when projected at an gle theta above and below horizontal
Thank you so much it helped a lot
Yes. I could have been a genius with this sort of tuition. Cheers 🍻
I love this. Thank you.
Can you do colliding??
U are really a good tutor
I searched "why greater heights provide further distance when jumping into water" because of the movie "Deep Water Horizon" showing Mark Walberg climbing higher up the drilling platform before jumping to clear the fire in the water. Now I know why he did what he did. And your teaching skills are amazing
Thank you!
So amazing thank you
What we solving for how far, are we solving vertically or horizontally?
you should be my physics professor!
thank you very well explained
learning this 1 hour before our examinations
How do you find the height of the cliff given the velocity and the the distance it landed?
thank you I love you.
I love the way you teach
I love this guy. Good humor and explains in the easiest way. But I was looking for something else. I knew how to solve this problem. I was searching for muzzle velocity. But got caught still. hahah
More efficient than my phy classes
perfect explanation
thank u !! my physics textbook nor teacher does this good of a job lol
Like Bucky Roberts, but in Khan Academy! Great video!
lol, exactly, but this one is funner
thanks for it😁
God bless khan academy
What if we are asked about the horizontal and verticle components of the velocity when the object hits the water?
what if we needed to find the total distance?
Thankyou so much
I’ve learned more from this than 4 months with my teacher
THANK YOUUUUU!!!!
Thank you my good sir
Very nice
I'm watching this DURING my physics exam
Thanks
Physics I see you
Thank for the video sir
good stuff.
the sound effects are great, i like Sal, cuz hes prob like super smart af, but this narrator is great too, 1:45
Any idea what program they use
can i ask why you multiplied both sides by 2 on the equation of getting the time?
thk man appreciate
My teacher accent is kinda hard to understand so helps out a lot. Thank you.
This stuff makes a TON more sense when you have a calculator to help with finding square roots
i genuinely wanna meet this guy
Thank you so much! Im not going to fail my physics test tom
taking the class next year wish me luck!
Justin Kim good luck
try hard
This is good
bless you sir
A bullet is fired 30deg to the horizontal with a speed of 200m/s. The acceleration of the bullet is 15 m/s^2 vertically downward
What is the change in velocity after 2 seconds?
Hey! Initial velocity= 200 m/s, final velocity after 2s= 186.81m/s, the change in velocity after 2s is -13.19 m/s.
Velocity only changes during vertical motion. So, we are neglecting the horizontal motion since the velocity here is always constant.
During vertical motion,
Acceleration =Δv/t.
Initially, during the vertical motion, the initial velocity is usually zero.
15ms-² = Vf - 0./2s.
Vf = 15ms-² × 2s.
Vf = 30ms-¹.
ΔV = 30 - 0 = 30ms-¹.
do we only give a e -9.8 going upwards if it is in free fall?
This literally is more helpful than the videos my teacher makes
awsome
This might sound strange but what software are you using?
life saviour
Regarding the value of downward acceleration due to gravity, why did it happen that it is negative? When in fact the object/body is accelerating not decelerating? Can someone explain?
The sign on acceleration has nothing to do with whether the object is speeding up or slowing down. A negative sign on any kinematics quantity just means that it is opposite the direction you arbitrarily define as positive. It is customary to define up as positive, but you don't necessarily need to do this.
My saving grace
a video not made by khan? praise the sun
is there a vertical version of this?
can anyone explain how to do the math portion once he gets to the radical
hi, so when you take vertical displacement (dy) as + 30 instead of -30, you will find that the value inside the root (that long line, i am assuming that's not what they call in your country) becomes negative. now, the square root of negative numbers come under the family of complex numbers and most calculators aren't build to do that (cos complex numbers are imaginary and unlikely anyone is gonna use irl) hope it helps
Omg Holy Shit, this came in clutch for my physics exam.
What if you are not given the cliff height at all and you are supposed to find it?