^^ Correction^^ For the 1st question, D'long is 30×60 = 1800 minutes. Therefore the final distance between Posn A and Posn B will be Cos 20° × 1800' = 1691.4 Nm Thankyou & Happy Learning :)
Wow Sir, Your videos cleared all my doubts and I always prefer your videos during my exams because you explain all the concepts with such ease . I feel more confident showing up for my examinations after seeing your videos. This helps me write my exams in a better way and score more.
In my opinion, as long as it is not clearly defined the (given) distance can be as well DLong as Departure. Both are distances and since it is given in NM I asumed it was DLong. Correct me if I am wrong.
@@seashellshore9997 ok sir .. thanks a lot it really helped me to clear my doubts..Sir can you plzz make videos on ship stability chapter ( bouyoncy and fresh water allowance and density, pressure and thrust)
Good Day! Initial Position or Long A is 10 deg East. D'long is 6 deg 32 mins towards the West of Long A. Therefore, final position arrived will be 3 deg 28 mins East.
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^^ Correction^^
For the 1st question, D'long is 30×60 = 1800 minutes. Therefore the final distance between Posn A and Posn B will be
Cos 20° × 1800' = 1691.4 Nm
Thankyou & Happy Learning :)
Wow Sir, Your videos cleared all my doubts and I always prefer your videos during my exams because you explain all the concepts with such ease . I feel more confident showing up for my examinations after seeing your videos. This helps me write my exams in a better way and score more.
Great channel ! Much love from Turkiye !!!
thank you so much, sir. we need more videos on other topics, like days work, great circle sailing, azimuth, etc.
Thanks vishnu brother ✌
In getting long b, how do you know if it's (+) or (-)
Hello how did u find the long B? You just write it.
Sir my conversion from degrees to minutes 30°=1800
I see u wrote 180 how possible?
True, that was a mistake he made, but he corrected it later.
how did u get 3°28'
Imu exams m v aise hi questions aate h kya
In my opinion, as long as it is not clearly defined the (given) distance can be as well DLong as Departure. Both are distances and since it is given in NM I asumed it was DLong. Correct me if I am wrong.
Sir I have a question, how can we determine if we need to plus or minus the Long A and Dlong to get the Final Position? im confused
There's actually a rule for that bro
So good, very easy nice tutorial, more power sir
Sir is the whole topic (parallel sailing) completed in this video???
Yes, most of it is covered in this video. Try solving more & more questions so that you get familiar with the concepts.
@@seashellshore9997 ok sir .. thanks a lot it really helped me to clear my doubts..Sir can you plzz make videos on ship stability chapter ( bouyoncy and fresh water allowance and density, pressure and thrust)
Sir your videos are Amazing!!!....
Correction on question 2, the 391.6 divided by 60 is 6.52 right?
-6 then times to .60
❤❤❤thanks
Sir how do you determine the course?
to elaborate
(in prob. 1 you said the Course was 90° T since its east)
how and why is it 90 and why is it east
I do have the same question. Lol
Since lat is same, and point A to B is going easterly
Gaurang Rathi G 👍
Sir if in the second type of Question if D'long comes negative , then what shall we do ??
Recommend to check your calculations again.
I think, must use mercator map. Not the Globe to explanation.
Will take that in consideration🤝
good day sir why is the longitude in the east ?
Good Day! Initial Position or Long A is 10 deg East. D'long is 6 deg 32 mins towards the West of Long A. Therefore, final position arrived will be 3 deg 28 mins East.
30degree dLong is 1800minutes
That is correct!
@@seashellshore9997 so the answer is 1691.4 instead of 169.1?
@@marcryantorrevilla5108 Yes, the correct answer for Departure is 1691.4 Nm.
what for I have seen this?
Sorry to say but u explain very badly
If you try it yourself it probably will be better :-) You yust sometimes need to read an listen double or triple cause a mistake is made easyly.