I will become a mechanical engineer student 1 year after, and I absolutely sure that I still watch your helpful videos! My grades are increasing thanks to your videos and I think that everybody needs a teacher like you, MR. Biezen! Thank you so much for your every videos that help me for my lessons! I hope that I have a chance to meet you one day!
My physics professor skipped a lot of steps that made me feel lost after every lecture. Good thing you have videos covering electric fields. I'm forever grateful. Thank you so much professor!
Thank you! I'm taking Physics 2 in the summer so the semester is only 6 weeks long. My professor is really good but it's too fast paced to grasp the concepts. Your videos are life saving!!!
Sir, you explain so nicely so that everyone understands. Your method of teaching is one of the best. You are far more better than my teacher here at the school. I have got more information from your videos than from my daily class in physics. Greetings from Germany
Thank you sir! seems complicated when our prof discussed this topic to us but you explained everything smoothly. I learned a lot! God bless:) -all the way from Philippines
A good father does a LOT more than teach physics to his children. A good father teaches good morals, good habits, discipline, kindness, compassion, a good work ethic, honesty, patience, tolerance, and teaches his children to become good citizens in society with wisdom and discernment.
I really appreciate what you're doing and I've already finished Mechanics course and watched all mechanics videos. However, i'm still wondering when would you upload the rest of the series 5,6,7...etc. Thanks & Regards
Can somebody explain how did he get the square root of 2? Why didnt he use the charges' distances? Is the value of x and y always provided, why if they are not? I was thinking of Pythagorean theorem. Thanks in advance.
I'm here 'cause my physics teacher shared this video on our gc. Physics is undeniably hard to study, but this topic seems to be much more difficult to understand 'cause what's in my module and in this video has a bit of a difference. Isn't the x component supposed to be multiplied by sin theta and the y component by cos theta? I hope someone will clarify. Thanks in advance 💛
It all depends on which angle you are looking at. Yes, in many cases the x is associated with cos and the y is associated with sin but again that depends on which angle you are considering. Always use cos = adjacent side / hypotenuse and sin = opposide side / hypotenuse
Noted sir. I was just confused since, based on what I've been reading in my module, it seems that in every example, the x component is being multiplied to sin theta. But it's clear now, somehow. So I guess it would be better to subscribe to your channel to learn more about physics💯Thank you, Mr. Biezen, for your quick response 😊💛
+shakamaos80 We only use a negative sign do depict an angle when using the unit circle reference. Here we simply indicate the magnitude of the angle (which cannot be negative, like the magnitude of a vector cannot be negative even when it points to a negative direction).
Abiel Hernandez There are many ways to express an angle between vectors, rays, and/or coordinate systems. If you use polar coordinates, then yes, the angle would be -20 degrees. Or the angle is 20 degrees below the x-axis. Or the angle between the x-axis and the force is 20 degrees directed below the x-axis. Or the angle is 20 degrees south of east. etc.
can you do five charge? which is two negative on the left side and two positive on the right side with magnitude of 2, and one positive on the middle with magnitude of 1. and then look for the net force.
Chen There really is no difference when you add additional charges. All you have to do is find the x and y components for each charge and then them up.
Thank you for the great explanation. I have one question regarding the angle: can it be a negative -20? I mean should it be because we are supposed to take inverse tan(E y^ / E x^) and E y^, in this case, is -32000 (it has a negative sign so the angle should be negative).
It depends on how you want to express the angle. (Negative angles are a purely mathematical concept and are used to express phase angles) But in the real physical space negative angles do not exist - can a triangle have a negative angle?
@@MichelvanBiezen Thank you again. In my university, we take a negative angle and subtract it from 360; a -20 angle is equal to 360 - 20 which is 340. As you said, it depends on how you want to express it. 340 also makes sense in this problem.
When you are finding the magnitude of E total, you didn't include the negative sign of E total in the y- direction, Why is that? I believe you made a mistake. Here's what I got when I included the negative sign with E total in the y-direction, Et = 85000 N/C and here's what I got without the negative sign, Et = 98000 N/C. I believe the correct answer is 85000 N/C. The reason why is 2^2 = 4 and -2^2 = NEGATIVE 4.... So, is the correct answer 85000 N/C?
The magnitude of a vector is ALWAYS positive. So you must include the magnitude of the vector components. However, when you are ready to ADD the components, then you must include the direction of the components as well. (As shown in the video).
can you help me this question...strontium-90 is Radioactive isotope having a half-life of 28years.strontium-90 has a density of 2.54gcm^-3. (I)the decay constant in s^-1 ,of strontium . the mass of strontium-90 in the sample,
Did you take a look at this playlist? It has a number of such examples: PHYSICS 64 NUCLEAR PHYSICS th-cam.com/play/PLX2gX-ftPVXX74EmmpD9mx3Gyy88S_rPO.html
when you are finding the direction of the electric field, why did not you include the negative sign of the y component of the electic filed in the arctan equation
Rita, Good question. It is just a preference. I prefer to just calculate the magnitude of the angle, and then looking at the sketch, we can determine the relative direction (usually in reference to the positive x-axis). I also prefer that the student utilizes the visualization of what is going on.
a very helpful videos just got some bonus points today due to your videos thanks....but a bit confused in the very video, isnt it possible to find E1,E2,E3 in the both y and x direction ?
+Ali Barma For every vector you can find the x and y components. Matter of fact, in order to add vectors you must add the x components and the y components separately.
Two like charges attract each other. Therefore there exists a force on the right charge pushing it to the left and there exists a force on the left charge pushing it to the right. Since a force is a vector quantity, you can represent these 2 forces with 2 vectors that point to each other.
I liked the video so much. But I have a question. please answer my question. If Q1 was a negative charge (suppose -12 micro culomb), then E1 would be inward. then how I could find the magnitude of E1 in x component and E1 in y component??? please try to give the answer.
Hasan, If Q1 was negative instead of positive, the magnitude of the electric field at (1m, 1m) would be the same due to Q1 and the direction would be towards Q1 (instead of away from Q1). Just draw the E1 vector to Q1 instead of away from Q1. Take a look at Q2 which is negative and its effect on the electric field.
There is no such thing as a negative angle, only angles greater than zero. Thus when we find the angle using the arc tan, we use the definition of the tan (theta) = opposite side / adjacent side. Here again there is no such thing as a side of a triangle less than zero. In mathematics we use the positive x-axis as a reference and define an angle 30 degrees below the x-axis as being -30 or 330. In physics dealing with real life scenarios we look for the magnitude of the angle between 0 and 90 degrees.
That depends on how you want to look at it. Typically you want to express the size (or magnitude) of the angle, which cannot be negative. (Like when you indicated the size of the angles of a triangle, you don't call one of the angles negative because the side is sloped downward). In mathematics when you want to express the angle relative to a coordinate system, you can call such an angle negative (by definition relative to the positive x-axis). Here the angle is just 20 degrees.
I'm back at your videos again, Mr. Biezen. I'm now in PHY2. I passed my PHY1 class with A because of your videos. Thank you for your help.
Excellent! All the best with PHYS 2.
Same bro I failed first then I studied with Mr.Biezen videos and I passed my class, now I am studying with Mr.Biezen again for PHYS 2
th-cam.com/video/XOeqvDi803o/w-d-xo.html
th-cam.com/video/0UzzAgPn2bo/w-d-xo.html
me like wise . i passed physics 1 with your videos. i am here to pass physics two
This is the best lecture my left ear has heard in years!
Thank you. We'll have to make one for your right ear. 🙂
I will become a mechanical engineer student 1 year after, and I absolutely sure that I still watch your helpful videos!
My grades are increasing thanks to your videos and I think that everybody needs a teacher like you, MR. Biezen!
Thank you so much for your every videos that help me for my lessons! I hope that I have a chance to meet you one day!
th-cam.com/video/0UzzAgPn2bo/w-d-xo.html
@Vela S th-cam.com/video/0UzzAgPn2bo/w-d-xo.html
@Vela S I graduated 1 year ago, and believe me or not I watched all the videos related my engineering programme till my last year.
@@neutronstar9983 Damn
My physics professor skipped a lot of steps that made me feel lost after every lecture. Good thing you have videos covering electric fields. I'm forever grateful. Thank you so much professor!
I wish I had teachers like you at my university. Thank you so much!
You study this in university ?
I can't believe these lectures are free! Thank you so much for what you do :)
Thank you! I'm taking Physics 2 in the summer so the semester is only 6 weeks long. My professor is really good but it's too fast paced to grasp the concepts. Your videos are life saving!!!
These lectures are amazing, they have helped me pass my physics 1 class and now they`re helping me with physics 2 as well!
Thank you. Glad you found our videos. 🙂
I LOVE YOUR VIDEOS. I WAS SO FRUSTRATED BEFORE AND NOW IT MAKES TOTAL SENSE. Thank you!
Great! Thanks for sharing.
Just because you explain that so clearly I followed you 🔥🔥🔥your student have a lot of chance 🔥
Glad you found our videos. Keep working hard, you will succeed. 🙂
you are far better than my professor.
Same !
amen to that
Amen
Sir, you explain so nicely so that everyone understands. Your method of teaching is one of the best. You are far more better than my teacher here at the school. I have got more information from your videos than from my daily class in physics.
Greetings from Germany
Thank you for the feedback. Welcome to the channel!
Me at 6:13: why does he always use a calculator.
The lecturer: i don't even need a calculator.
*illuminati confirmed*
First Electromagnetism exam passed !!! Thanks a lot for your clear lectures !!!.... 2 more exams coming up ! Happy Eastern !!
You have the best physics videos I have ever come across. Thank you!
Glad you like them!
Thank you this really helped! good to find videos for above intro level physics
This channel deserves more subsribers
Thank you so much Michel. I watched all the 12 videos and they are very helpful. Again, thanks and please continue posting more of your work.
My prof is a freaking train, he made even the simplest questions so confusing :( This is very helpful! Wish I stumbled on this earlier.
at first i underestimated this guy, but he really knows his stuff! thanks for the help prof Biezen
Van Biezen the Physics savior.
th-cam.com/video/0UzzAgPn2bo/w-d-xo.html
I am now in my second quarter of physics and your videos are great!
Felicia,
Keep up the hard work and thanks for the comment.
Thank you sir! seems complicated when our prof discussed this topic to us but you explained everything smoothly. I learned a lot! God bless:)
-all the way from Philippines
Welcome to the channel!
Thank you so much for this! It was very helpful. Much better explanation than my professor.
How i wish you're my father I could be learning this daily , thank you very much
A good father does a LOT more than teach physics to his children. A good father teaches good morals, good habits, discipline, kindness, compassion, a good work ethic, honesty, patience, tolerance, and teaches his children to become good citizens in society with wisdom and discernment.
Thank u very much, sir!! I like how u always put the units in your calculation =D
I have a question and need quick answer sir!
How did you assign those charges their sign +ve,-ve. because of their values?
That should be "given" in the problem. Without that being given you cannot solve the problem.
Was posted 4 years ago, Still relevant for exams LMAO
did you expect the physics to change?
physics never changes
Dumbest comment on the internet!
@@razeen4152 not as dumb as you
@@bull3asaur168 That's... not true. If you were joking then nvm.
Doc Biezen, thank you so much for the videos. They are an excellent supplement for electromagnetic theory (ENEE380)..
Thank you so much!! Helped me ace my test! Love your teaching and solving methods.
I really appreciate what you're doing and I've already finished Mechanics course and watched all mechanics videos. However, i'm still wondering when would you upload the rest of the series 5,6,7...etc.
Thanks & Regards
All the physics videos have been placed in a new set of playlists from PHYSICS 1 through PHYSICS 65
Take a look at those.
This is amazing, it cleared things up so much for me. Thank you for taking the time to do this, I love your videos!
Glad they are helping. Thanks for the comment.
Thank you very much for this excellent explanation. This is very helpful.
Glad it was helpful!
Thank you very much for these videos Mr. Michel van Biezen!
Oh my!! You're so clear. THANK YOU
Thanks a lot. It was very helpful !!!!
Grettings from Argentina.
Sir can you please apply in my University
Nigeria Maritime University
They are looking for lecturers on various courses in Engineering sir....
Your Lecture was more understandable than my German school Teachers. Danke schön :)
You are welcome and welcome to the channel.
yes I'm looking for the net electric field and its direction of the unnamed charge
We are not allowed to calculators in my country. We just write the problem on a paper and do the math, no matter how hard is the simplification is.
And what's ur country?
sri lanka
You're my HERO ! Thank you thank you so much.
Michelle Biezen was always the best at teaching.
yo mikey, homie you be killing this shit holmes!
Michel van Biezen You're a BOSS!!
Your videos are really helpful. Greetings from South Africa.
Welcome to the channel. Glad the videos are helping.
Your videos are amazing! You give great and clear explanations! thank you!
Stefany,
Thanks for the positive feedback.
doing a great work sir, keep it up!
Thank you. We hope to continue for as long as we can.
Thanks for the videos sir it has actually helped me
Can somebody explain how did he get the square root of 2? Why didnt he use the charges' distances? Is the value of x and y always provided, why if they are not? I was thinking of Pythagorean theorem. Thanks in advance.
The diagonal distance of a square with sides = 1, is indeed the square root of 2. Use Pythagorean theorem.
my left ear loved this
Yes, our old videos were filmed in mono sound.
if only you taught my class! So amazing at explaining..thank you so much:)
I'm here 'cause my physics teacher shared this video on our gc. Physics is undeniably hard to study, but this topic seems to be much more difficult to understand 'cause what's in my module and in this video has a bit of a difference. Isn't the x component supposed to be multiplied by sin theta and the y component by cos theta? I hope someone will clarify. Thanks in advance 💛
It all depends on which angle you are looking at. Yes, in many cases the x is associated with cos and the y is associated with sin but again that depends on which angle you are considering. Always use cos = adjacent side / hypotenuse and sin = opposide side / hypotenuse
Noted sir. I was just confused since, based on what I've been reading in my module, it seems that in every example, the x component is being multiplied to sin theta. But it's clear now, somehow. So I guess it would be better to subscribe to your channel to learn more about physics💯Thank you, Mr. Biezen, for your quick response 😊💛
thank you so much
omg i am sooooooo thankful
i cannot thank you enough
You are welcome. Glad you found our videos. 🙂
Thanks for your nice and clear explanation.
It Is really good Have enjoyed that
thanks for your video! I finally understand this chapter...
Thank you a lot professor michel I return more times only how can explain cery clearly
Life Saver once again
We are glad to be of help.
greatest teaching.. thank you Sir
Thank you. Glad it is helpful. 🙂
thanks a lot, i was stuck on this problem❤️ love from India
Glad it helped!
Thank you. Great example covers everything.
Thanks man, that was awesome, I learned a lot.
Glad it helped!
Sir it isn't 349.4 degree as Ey is -ive and Ex is +ive which means it lies in fourth quadrant.
I physics, we tend to keep the angles between 0 and 90 degrees with reference to the x and y axis.
This is a Great Example!!
Thank you so much sir! You save me every time!
Seriously a life saver!!!
Thank You!
I think that the angle should be negative since is under the x axis. tan-1 of (-34000/92000) which is -20 degrees .
+shakamaos80 We only use a negative sign do depict an angle when using the unit circle reference. Here we simply indicate the magnitude of the angle (which cannot be negative, like the magnitude of a vector cannot be negative even when it points to a negative direction).
sir ur explanation is amazing .. thank you .. greetings from Sudan
Thanks for your feedback and welcome to the channel.
Sir while calculating the direction or angle at last u did right 20 degrees y didn't u consider the -ve sign of y component .plz tell me sir
Because we are calculating the magnitude of the angle. (No phase shift here).
i wish you were my teacher , but just a quick question , wouldnt the direction be at -20 degress or 340 since the y is negative
Abiel Hernandez
There are many ways to express an angle between vectors, rays, and/or coordinate systems.
If you use polar coordinates, then yes, the angle would be -20 degrees.
Or the angle is 20 degrees below the x-axis.
Or the angle between the x-axis and the force is 20 degrees directed below the x-axis.
Or the angle is 20 degrees south of east.
etc.
Super helpful!!!!!! thank you so much.
i want to ask you a question which ıs related to dipole moment😔
can you do five charge? which is two negative on the left side and two positive on the right side with magnitude of 2, and one positive on the middle with magnitude of 1. and then look for the net force.
Chen
There really is no difference when you add additional charges.
All you have to do is find the x and y components for each charge and then them up.
Thank you for the great explanation. I have one question regarding the angle: can it be a negative -20? I mean should it be because we are supposed to take inverse tan(E y^ / E x^) and E y^, in this case, is -32000 (it has a negative sign so the angle should be negative).
It depends on how you want to express the angle. (Negative angles are a purely mathematical concept and are used to express phase angles) But in the real physical space negative angles do not exist - can a triangle have a negative angle?
@@MichelvanBiezen Thank you again. In my university, we take a negative angle and subtract it from 360; a -20 angle is equal to 360 - 20 which is 340. As you said, it depends on how you want to express it. 340 also makes sense in this problem.
When you are finding the magnitude of E total, you didn't include the negative sign of E total in the y- direction, Why is that? I believe you made a mistake. Here's what I got when I included the negative sign with E total in the y-direction, Et = 85000 N/C and here's what I got without the negative sign, Et = 98000 N/C. I believe the correct answer is 85000 N/C. The reason why is 2^2 = 4 and -2^2 = NEGATIVE 4.... So, is the correct answer 85000 N/C?
The magnitude of a vector is ALWAYS positive. So you must include the magnitude of the vector components. However, when you are ready to ADD the components, then you must include the direction of the components as well. (As shown in the video).
Here in this problem angle is 45 degree if its a rectangle and and the angle is not 45 degree then how we get the x and y components .
Then you can use trigonometry. tan (theta) = opposite side / adjacent side
Around minute 8 why is the angle between E1 and E3 and not between E1y and E1?
You can use either angle, it doesn't matter. Traditionally we pick the angle between the vector and the horizontal axis.
Excellent video
Thank you very much!
I realize this is a stupid question but why is the distance square root of two?
The length of the diagonal of a square = sqaure root (2) x side
Thank yo so much for the video. Helped out in a question. 8 August 2021
Glad it helped!
can you help me this question...strontium-90 is Radioactive isotope having a half-life of 28years.strontium-90 has a density of 2.54gcm^-3.
(I)the decay constant in s^-1 ,of strontium .
the mass of strontium-90 in the sample,
Did you take a look at this playlist? It has a number of such examples: PHYSICS 64 NUCLEAR PHYSICS th-cam.com/play/PLX2gX-ftPVXX74EmmpD9mx3Gyy88S_rPO.html
This was great!
Glad it was helpful 🙂
I have a question, what if I got negative sign to the direction going to the right? will I still change it to positive?
Note that the sign only gives you the direction. The magnitude of a vector or the magnitude of the component of a vector can only be positive.
please can you help me with the 4charges problem I'm not getting the point why you are finding Ex and Ey. up to the end.
Are you looking for the net electric field? If so at what location? Or are you looking for the force on one charge due to the presence of the others?
when you are finding the direction of the electric field, why did not you include the negative sign of the y component of the electic filed in the arctan equation
Rita,
Good question. It is just a preference. I prefer to just calculate the magnitude of the angle, and then looking at the sketch, we can determine the relative direction (usually in reference to the positive x-axis).
I also prefer that the student utilizes the visualization of what is going on.
Michel van Biezen okay that makes sense. Thank you so much for responding!
Thank you kind sir for this helpful video.
a very helpful videos just got some bonus points today due to your videos thanks....but a bit confused in the very video, isnt it possible to find E1,E2,E3 in the both y and x direction ?
+Ali Barma For every vector you can find the x and y components. Matter of fact, in order to add vectors you must add the x components and the y components separately.
Thank you sir
can you please explain why you said that the vector of the two like charges attract each other
Two like charges attract each other. Therefore there exists a force on the right charge pushing it to the left and there exists a force on the left charge pushing it to the right. Since a force is a vector quantity, you can represent these 2 forces with 2 vectors that point to each other.
I liked the video so much.
But I have a question. please answer my question.
If Q1 was a negative charge (suppose -12 micro culomb), then E1 would be inward. then how I could find the magnitude of E1 in x component and E1 in y component???
please try to give the answer.
Hasan,
If Q1 was negative instead of positive, the magnitude of the electric field at (1m, 1m) would be the same due to Q1 and the direction would be towards Q1 (instead of away from Q1). Just draw the E1 vector to Q1 instead of away from Q1. Take a look at Q2 which is negative and its effect on the electric field.
so the angle would be (90+45)=135 degree. [considering from positive X axis]
thank you , I have Q .. why don't u add negative with 34000 when you find the angle ! , we use Fy/FX
and fy iss negative I hope you answer me
There is no such thing as a negative angle, only angles greater than zero. Thus when we find the angle using the arc tan, we use the definition of the tan (theta) = opposite side / adjacent side. Here again there is no such thing as a side of a triangle less than zero. In mathematics we use the positive x-axis as a reference and define an angle 30 degrees below the x-axis as being -30 or 330. In physics dealing with real life scenarios we look for the magnitude of the angle between 0 and 90 degrees.
thank u , you helped me a lot ^_^
You save mye life!!
thanks for the lesson
Thank you, Sir!!!
i have a question why did we multiply Ex1 and Ey1 by sin and cos and did not multiply E2 and E3 ?
E2 and E3 are lined up vertically and horizontally with the point of interest so we don't have to find the components.
please am a bit confused at the distance of the electric field(x=1.0, y=1.0) it seems the one there is y=10
The decimal points are hard to see, but they are there.
i Appreciate your videos sir, where are the missing videos though (5-12)?
BET8ON8ME
They are in the playlist: PHYSICS 36 THE ELECTRIC FIELD
cheers mate
Hi
Thank you YOU ARE THE BEST
thank you for your knowledge!!!
thank you so much sir but the electric field 5\12 doesn't exist.could you please add more electric field videos?
All the videos are there, I renumbered them so it is clear. There are 16 in the playlist. Which specific examples were you looking for?
The angle should be negative 20 since the y component is negative Right ??
That depends on how you want to look at it. Typically you want to express the size (or magnitude) of the angle, which cannot be negative. (Like when you indicated the size of the angles of a triangle, you don't call one of the angles negative because the side is sloped downward). In mathematics when you want to express the angle relative to a coordinate system, you can call such an angle negative (by definition relative to the positive x-axis). Here the angle is just 20 degrees.