Solution to questions that appear in CSIR NET, GATE and many other major national exams. Learn tips and tricks to solve questions in a shorter time span.
at 29:14 Metal will gain slight electropositive character due to deficient of electrons... everything is explained nicely with good tactics. Thank you and keep resuming this wonderful work.
Sir u r very hardworking and at the same tym calm and patient that evn aftr technicl issue u keep on teachng so calmly that ovrpowers these typ of things in this video.thanku for ur efforts..
Sirr ..place that mirror which is behind the board ...in front of camera while filmjng so that you can see from the place where you are teachingg...and plz make an video or tell me a book about boron hydrid..
Can you please explain how to calculate the structure of (Rh6 C (CO)15)-2. SEP comes out to be 9. So the structure should be decahedron. But the correct answer is trigonal prism. Can you please explain sir?
sir it not work for Rh6C(CO)15with 2 negative. question in dec. 2106. Acc to u S.E =9 dodecahedron. but ans is trigonal prism ....... dodecahedron is not in option of csir net dec 2k16
Formula to be used is (TVE-(12*n)-(2*n))/2. Where the first 'n' represent the number of transition metal and the second 'n' represent the number of main group element. When solved we get 10 SEP and hence its structure is tricapped trigonal prism
sir! In miessler and tarr,I have found that they have given octahedron for 6 skeletal atoms and pentagonal bipyramidal for 7 skeletal atom.so which table we have to follow?
Sir plz upload a video about how to find out no. Of bridging carbonyl ligand in a organometallic compound and also finding out the no. Of M-M bond and bridging carbonyl simultaneously.
Please help me with this doubt: Why didn't you take C as a vertice in [Fe4 (C) (CO)12]^-2 calculations but you took C as a vertice in [Co2 B8 C2 H10 (Cp)2].
In your last example where both transition and non transition atom is present you calculate SE predict the geometry of complex if we want know its is closo nido aur arachano..then ???
In case of( fe4c(co)12)4_ u r not contributing carbon while substracting it as 12 *n while in case of co2B8c2h10(cp)2 u substracting ....pls explain..is we HV to subtract when both r present only???
sir,in house craft books one similar type of tables has been given in page no -717 but on the basis of total electron count where when if TEC =90 then the geometry should be trigonal prism and also one example is solved in this books,i.e. for [Os6(co)18P]-(WITH ONE NEGATIVE CHARGE) BUT when i go through your tables and findind the SEP i got 9 for this same comolex which means it has dodecahedron geometry,how this two geometry co-relate ,i have checked ,these two geometries are totally different.which is correct please told me.
Sir, if both polyene attached with metal are aromatic and even no. Of carbon then where nucleophile will attack (no. Of carbon is different in both polyene....
sir, in complex os6(co)18 the S.E=6 so a/c to u the geometory should be trigonal bi pyramidal but the answer is capped trigonal bipyramidal.are the both same
Sir what is the geometry of [ReH9]2_ ? According to you geometry is Dodecahedron. But csir and is tricapped trigonal prism... Dec 2016 set B , question no 80. Sir plz kindly check it
The geometry provided here for SeP is arranged in wrong order if I'm not wrong. Shouldn't it be octahedron for 6, pentagonal bipyramid for 7? Please clarify.
Sir according to you if skeletal electron pair is 9 then Dodecahedron geometry. But csir ans for the compound RhC(CO)15 with 2 negative charge is trigonal prism which contain 9 electron pair. Sir PL kindly reply ....
a big thanku for such kind of precise videos as well preparation strategies when the exam is knocking at the door..will u please give some lecture on raman spectroscopy?
Sir, we have studied for 5 SEP geometry should be trigonal bipyramidal but here you are telling that for SEP =6, geometry will be TBP. I am very much confused
sir according to mingos rule the geometry of OS6(CO)18 should be trigonal bypyramidal as it has T.V.E are 84 and SE is 6 ....but the geometry is Bicapped tetrahedron ...sir how ? pls explain sir
Sir can you explain how to find the M-M bond order in [Re2Cl4(PMe2Ph)4]+... I have tried finding it n getting as 5.5 following the formula as given by you but in misseler n tarr, it's 3.5.. how
![Wade Rule and Wade-Mingo's rule[Simplest Explanation] | Finding Geometry of Metal Cluster](http://i.ytimg.com/vi/qypcvnf9k3I/mqdefault.jpg)
Your hardwork and efforts in making this video is really appreciable🙌🙌🙌🙌....thank you so much for this video sir
at 29:14 Metal will gain slight electropositive character due to deficient of electrons...
everything is explained nicely with good tactics. Thank you and keep resuming this wonderful work.
Sir, today I had to take seminar on wade-mingos rule. This video really helped me a lot. Thank you sir.
Your work is great you dont know you helping so manny students who hv no proper resources to crack the exam.. continue..it..plz..great job
I agree
Sir u r very hardworking and at the same tym calm and patient that evn aftr technicl issue u keep on teachng so calmly that ovrpowers these typ of things in this video.thanku for ur efforts..
Your efforts are outstanding keep it up 👏👏 ur videos r really helpful for us thanks for making such a wonderful videos
Best way of teaching... It helps us alot. Thanx for the great help...
Thankyouuu so much sir... even ASF didn't tell me the geometries of skeletal electrons. I was so confused before watching this... thanks a ton sir.
Sirr ..place that mirror which is behind the board ...in front of camera while filmjng so that you can see from the place where you are teachingg...and plz make an video or tell me a book about boron hydrid..
Can you please explain how to calculate the structure of (Rh6 C (CO)15)-2. SEP comes out to be 9. So the structure should be decahedron. But the correct answer is trigonal prism. Can you please explain sir?
sir it not work for Rh6C(CO)15with 2 negative. question in dec. 2106. Acc to u S.E =9 dodecahedron. but ans is trigonal prism ....... dodecahedron is not in option of csir net dec 2k16
Sir did you find the correct solution for this? Plz reply sir
Formula to be used is
(TVE-(12*n)-(2*n))/2. Where the first 'n' represent the number of transition metal and the second 'n' represent the number of main group element. When solved we get 10 SEP and hence its structure is tricapped trigonal prism
deebika baskar hi mam. ...here by applying that formula we got 8 SEP.how u got 10 SEP ? can u plz explain ?
sir! In miessler and tarr,I have found that they have given octahedron for 6 skeletal atoms and pentagonal bipyramidal for 7 skeletal atom.so which table we have to follow?
Sir plz upload a video about how to find out no. Of bridging carbonyl ligand in a organometallic compound and also finding out the no. Of M-M bond and bridging carbonyl simultaneously.
The struture of Os4(CO)16 is square planar not pentogonal bipyramidal
Sir geometry rule is totally wrong plz correct that one .
Could you please tell me what's wrong. Which geometries, and what should they be?
Yes sir number only changes in geometry
Manisha Subedi 6 was octahedron
Sir very useful video I have never found it before in such a good way.
Sir , I think the Geometries tbp is for SE=7 , and in that way all the other Geometries are shifted from their SE values ,,, as written on the Board
Sorry Sir , Geometry pbp is for SE=7
thanks for preparing simple explanations. your all videos are easy to understand
nice video making .specially thankfull sir .it is very helpfull for preparation for interance exam ...
Your videos are superb! Thank you so much..Please make a video on Mossbauer spectroscopy taking all previous years questions of CSIR NET exam
thanking you sir for valuable information... video is not filming again again but you tried for us is very important... thanks a lot again sir
Please help me with this doubt: Why didn't you take C as a vertice in [Fe4 (C) (CO)12]^-2 calculations but you took C as a vertice in [Co2 B8 C2 H10 (Cp)2].
Nice video sir non of single video on mingo rules u did it only thnk u sir
After the attack of nucleophile in Mingos & Greevs Rule, what will be the compound final structure? What will be the final hapticity of ligand?
In your last example where both transition and non transition atom is present you calculate SE predict the geometry of complex if we want know its is closo nido aur arachano..then ???
Thanku so much sir fr these wonderful videos..they means a lot fr my csir preparation.please upload as many videos as possible.
In case of( fe4c(co)12)4_ u r not contributing carbon while substracting it as 12 *n while in case of co2B8c2h10(cp)2 u substracting ....pls explain..is we HV to subtract when both r present only???
sir,in house craft books one similar type of tables has been given in page no -717 but on the basis of total electron count where when if TEC =90 then the geometry should be trigonal prism and also one example is solved in this books,i.e. for [Os6(co)18P]-(WITH ONE NEGATIVE CHARGE) BUT when i go through your tables and findind the SEP i got 9 for this same comolex which means it has dodecahedron geometry,how this two geometry co-relate ,i have checked ,these two geometries are totally different.which is correct please told me.
Thx i finally got a interesting chemistry explaner ....method is too effective
really I was waiting for this type lectures especially for csir ...
helpful
Sir, can you explain why you didnt subtract 2n from [Fe4(C)(Co)12]2- eventhough carbon is present.
Why did you not consider the C atom for se calculation in Fe4C(CO)12 2-
Sir, if both polyene attached with metal are aromatic and even no. Of carbon then where nucleophile will attack (no. Of carbon is different in both polyene....
when two T.metals are there then how to find metal metal bond such as in Co2Fe2(CO)11(mu4-PPh2)
Sir, in Mungo's rule if two polyenes have odd number of carbons then nucleophile attacks or not.
please tell me that whether geometry depends on SE pairs or NO. OF VERTEX ( and whether no. of vertex = SE pairs or Not)
Very useful and resourceful video.Thank you for the effort
you are simply awesome. Can you please share tricks to bag single digit rank.
sir how to find structure of (Bi5)2+ , there is no matching with 4n+2 or 4n+4 ...
sir when both rings having odd no.of carbon means how to find out the attack of nucleophile like ferrocene
Sir i have one doubt sir... Co2 B8C2 H10cp 2is considered under nontransition thenwhy we dont consider c in Fe4 C CO 12 2- ....
thank u very much sir plz keep going on to upload these videos
you really helps a lot for cracking such competitive exams .
thank you so much sir..you are doing a very good job .. it's really helpful sir..may God bless you
sir, in complex os6(co)18 the S.E=6 so a/c to u the geometory should be trigonal bi pyramidal but the answer is capped trigonal bipyramidal.are the both same
Thank you sir... Very nice collection both closo, neido type.. As well as geometry..
Sir thanks A lot i started preparation after 3 year n you clear my doubts
Could you please explain why H2Os6(CO)18 has capped square based pyramid ( housecroft)
Sir what is the geometry of [ReH9]2_ ?
According to you geometry is Dodecahedron.
But csir and is tricapped trigonal prism...
Dec 2016 set B , question no 80.
Sir plz kindly check it
for the second example the structure you have drawn square pyramidal not trigonal bipyramidal.
The geometry provided here for SeP is arranged in wrong order if I'm not wrong. Shouldn't it be octahedron for 6, pentagonal bipyramid for 7? Please clarify.
okay, thanks
Sir how can we calculate bond order in metal halide clusters, eg in (Nb6Cl12) 2+?
Sir when SE is less then 6 then how to find geometry
Sir how to calculate M-M bonds for those system which doesn't follow 18 e's rule.
how can we find terminal and bridged carbonly atttached group in a molecule
I think steric no should be 5 for trigonal bipyramidal geometry...??
Sir according to you if skeletal electron pair is 9 then Dodecahedron geometry.
But csir ans for the compound RhC(CO)15 with 2 negative charge is trigonal prism which contain 9 electron pair.
Sir PL kindly reply ....
Rh can't be only one... Your question is wrong
Please explain the geometry of [RhC(CO)15]-2. It does not work according to what you taught.
Y (ReH9)2- has not octahedral geometry while it's skeletal electron papir are 7
sir how can we calculate no. of bridging co in a complex like fe3( co )9
Sir what if both the polyenes are even numbered & aromatic??
a big thanku for such kind of precise videos as well preparation strategies when the exam is knocking at the door..will u please give some lecture on raman spectroscopy?
In 4 th example why you didn't count non metal C menat you didn't minus the 2 according to 2n for non transition metal It is very confusing
In davies mingo..if both aliphatic polyenes are attached to central.maletal.atom.then what about the preferential attacks in these cases???
ok.sir.
Sir, we have studied for 5 SEP geometry should be trigonal bipyramidal but here you are telling that for SEP =6, geometry will be TBP. I am very much confused
I am very much confused in geometry. Many teachers are explaining in different ways. I don't know what is the right way to calculate geometry
plz upload a video on various hydroxylations across a double bond (uncommon ones)......thanks for the earlier videos.....means a lot
Is n-4 is tetracapped or n-3 is tetracapped? U mentioned n-4 as tetracapped in this video.
Which book follow for Davis mingoes & greaves rules?
Sir in os5co16 SEP is 6 means TBP geometry.... But u have drawn octahederal pyramidal
sir, may i know the name of the book from which you have taken the table of geometry?
sir how do we come to know that where we have1 to apply mingos rule and where not
What is the geometry of [Rh6C(CO)15]2-
Sir, each skeleton electron pair will be 1 less for corresponding.....like dodecahedron will be 8, (here given 9)...so on
Same problem I am also facing, I can't decide now which is true, I am totally confused
Awesome Sir...all examples are really helpful..
Sir what should be studied from the topic chemistry of noble gases??
Sir how to find The number of bridging ligands and M--M bond present in [Ru(n5c5)2(CO2)2(Ph2PCH2PPh2)]..??
Ok sir.
lecture was to good
one suggestion for u put mirror in front of ur phone to look recording is on or not
bcoz ur effort shld not be wasted.
thank you
sir according to mingos rule the geometry of OS6(CO)18 should be trigonal bypyramidal as it has T.V.E are 84 and SE is 6 ....but the geometry is Bicapped tetrahedron ...sir how ? pls explain sir
ok Thank you sir..
Ok sir..
Sir what is the geometry of [RhC(CO)15]2-
Sir how can we find the polyhedron geometry of lanthnide or actinide for eg-(UO2(NO3))- it askd in csir net jrf
Gate chemistry ok thnq sir
Ritu khatri icosahedron geometry...
Ritu khatri here coordinaton no is 12, thus it takes icosahedron geometry
Avishek Guin ok
Coordination number is 12
OH- ve show 1 electron contribute . So why OPh contribute 3 .
Thnq sir...this is giving clear idea to me, plz upload more videos on csir topics
Sir for 6 trigonal bipyramidal or octahedron,n for 7 octahedron or pentagonal bipyramidal ???
Sir please please correct it coz m confused
kashmina akhtar 5= trigonal bipyramidal 6= octahedral and so on.....
What will be the case for [ Rh9P(CO)21] 2- ?
Sir this rule I'd not obey to csir question June 2018 ...
Please suggest the answer...
N really ur videos r very helpful for our preparation..
Sir can you explain how to find the M-M bond order in [Re2Cl4(PMe2Ph)4]+... I have tried finding it n getting as 5.5 following the formula as given by you but in misseler n tarr, it's 3.5.. how
You got answer now??
Sir Is this rule is apply only closo borane.Plesse clear it.
How to find out structure of OS5C(CO)13? Nido, hypo or arachno?
No...actually no. Of skeletal electron pair is 10 that leads to 2n rule which means monocapped series but how to find out the structure?
thank you sir for helping us in such a way........
Thank you soo much sir..... Very greatful for ur work 🙏
Thank you sir.. I requested this video . U responded soon.. thanks a lot for ur support and guidance
Very unique and helpful...
sir NET 2016 DEC QUESTION NO 80.i had got the answer but i am unable to know how to predict its structure.sir please help me.
and sir if we want to solve queations from wherewe can pracise
Sir 6s.e is octahedron
sir what shd i do from solid state on point of view for csir only
sir agar pi acceptor h to electronegative. kaisi hoga
Thank you for your patience.....
very nice way to solve the questions
sir I was attempt 15 ques in part c n only 8 correct n 7 wrong in june17 plz tell me how to attempt questions