Dear Greg, I do not know if you're still here but I want to let you know your video and your explanation is the reason I understand how to do the subnet with this great formula. Thank you so much.
All - I incorrectly call the address at 15:05 a class C address. It is a class B. I still did the problem correctly, but my brain was too distracted with what my hand was doing to get my mouth on the same page. Thanks for catching this Jeff!
N = 7, it means 2^7 = 128 total number of networks we have. H = 1, it means 2^1 = 2 total number of IP addresses per each network. (2^1) - 2 = 0, it means this sub-netting will not allow us to have usable hosts per network. 256 - (2^1) =254 (254.0.0.0 is the custom subnet mask). hope it helps
@@hasibullahkhairi8981 No. That's not how it works sir. And 2 to the first power is 2, not one. 2 the zero is one. I see you made an edit and corrected your power of 2 issue. Good. Now to further address your question, you have to consider the total host bits remaining, not just in the octet. If you watch the video again, I point this out. For example, 170.1.1.0 / 23, still can have up to 510 hosts per network, because there is 1 host bit in the third octet, and 8 in the forth. That's 9 bits left total. Lastly, Cisco has now allowed for /31 bit masks for point to point connections where effectively the subtnet ID and the broadcast address are usable. Sorry for the delayed response!
@@gregschmidt2256 This does not seem a valid question, because the given IP address belongs to Class-B and it has a subnet mask of 255.255.0.0, by default. It should be written like 130.110.30.0/16.
@@NetworkingNewbies , please keep in mind the class of an address has nothing to do with a subnet mask. I can assign a /22 to a class C or a /28 to a class A if I wish. The default values for class full addresses remain.
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Dear Greg, I do not know if you're still here but I want to let you know your video and your explanation is the reason I understand how to do the subnet with this great formula. Thank you so much.
Dude... You have no idea how much this has helped me.
god bless this mans soul, may you reach the highest of heavens my boy. you deserve it.
The best explanation I ever seen. Thank you sire.
All - I incorrectly call the address at 15:05 a class C address. It is a class B. I still did the problem correctly, but my brain was too distracted with what my hand was doing to get my mouth on the same page. Thanks for catching this Jeff!
you had me worried for a while
Great breakdown. Voted!
I enjoyed the video. Thanks
Good one
Excellent lecture
Thank you sir!
Algebra
And easy Algebra at that! Subnetting isn't hard at all!
i have one question about subnetting
how can answer thie question
130.110.30.2 / 7
best regard
whats is your question lol you just gave us IP address and a mask?
N = 7, it means 2^7 = 128 total number of networks we have.
H = 1, it means 2^1 = 2 total number of IP addresses per each network.
(2^1) - 2 = 0, it means this sub-netting will not allow us to have usable hosts per network.
256 - (2^1) =254 (254.0.0.0 is the custom subnet mask).
hope it helps
@@hasibullahkhairi8981 No. That's not how it works sir.
And 2 to the first power is 2, not one. 2 the zero is one.
I see you made an edit and corrected your power of 2 issue. Good. Now to further address your question, you have to consider the total host bits remaining, not just in the octet. If you watch the video again, I point this out. For example, 170.1.1.0 / 23, still can have up to 510 hosts per network, because there is 1 host bit in the third octet, and 8 in the forth. That's 9 bits left total. Lastly, Cisco has now allowed for /31 bit masks for point to point connections where effectively the subtnet ID and the broadcast address are usable. Sorry for the delayed response!
@@gregschmidt2256 This does not seem a valid question, because the given IP address belongs to Class-B and it has a subnet mask of 255.255.0.0, by default. It should be written like 130.110.30.0/16.
@@NetworkingNewbies , please keep in mind the class of an address has nothing to do with a subnet mask. I can assign a /22 to a class C or a /28 to a class A if I wish. The default values for class full addresses remain.