De novo peptide sequencing from mass spectrometry data

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  • เผยแพร่เมื่อ 27 พ.ย. 2024

ความคิดเห็น • 23

  • @TJ-do4wt
    @TJ-do4wt ปีที่แล้ว +1

    You're a legend! This is currently helping me with my mass spec lab in my biochemistry degree 💪🏽📊

  • @jingjingxu8845
    @jingjingxu8845 ปีที่แล้ว

    Super great! Thank you very much. It is very helpful to me, a beginner of MS user

  • @mamarain8225
    @mamarain8225 3 ปีที่แล้ว

    This saved my skin, thank you so much! Succinct and easy to understand.

  • @niloofarfam4294
    @niloofarfam4294 8 ปีที่แล้ว

    This video was really a life-saver. Thank you!!!

  • @xuejie5507
    @xuejie5507 5 ปีที่แล้ว

    This Video is extremely helpful, thank you so so much!

  • @둥글-s2y
    @둥글-s2y 4 ปีที่แล้ว

    Thank you for your kind explanation :) This is very helpful

  • @isabelacopetti404
    @isabelacopetti404 3 ปีที่แล้ว

    This was very helpful! Thank you!

  • @TheMistakentruth
    @TheMistakentruth 8 ปีที่แล้ว

    Just the information i needed! Thank you sir :)

  • @acell1618
    @acell1618 ปีที่แล้ว

    Thanks a lot for these videos. However, a doubt remains.
    The peptic fragments are just being blasted with inert gas to break them down into b and y ions.
    Where from are the extra 1 or rather 2 H+ at the N terminal of 'y-ions' coming from, giving them overall +1 charge?

    • @MatthewPadula
      @MatthewPadula  ปีที่แล้ว

      The peptide ions are accelerated into the collision cell and collide with the inert gas molecules, which causes the fragmentation. There are no extra H+. The peptide starts out 2H+ and the fragments are 1H+.

  • @lucab012
    @lucab012 ปีที่แล้ว

    This was very helpful but I still have one question. I don't get why the relative intensities of complementary b and y fragments are different, like b2 and y10 in your example. I mean, when the parent ion fragments on a specific bond you get the same amount of the two complementary fragments, so I really don't get this. could you help me please?

  • @arjentenhave8961
    @arjentenhave8961 8 ปีที่แล้ว +1

    Excellent!

  • @AnniePrettyFace
    @AnniePrettyFace ปีที่แล้ว

    Hey sir! Thanks for the help- question I had is how would you draw a simple mechanism for the y and b fragmentation? How do both the nitrogen np oxygen become positively charged? Thanks for the vid!

    • @MatthewPadula
      @MatthewPadula  ปีที่แล้ว

      link.springer.com/article/10.1007/s13361-016-1341-0 - see scheme 6

    • @erikhenze2339
      @erikhenze2339 ปีที่แล้ว

      @@MatthewPadula How does that scheme account for the first b ion? according to that you would never get a N-terminal single amino acid, would always have at least two side-chains incorporated

    • @MatthewPadula
      @MatthewPadula  ปีที่แล้ว

      @@erikhenze2339 b1 is the singly charged parent ion mass minus the largest y-ion. With CID you probably will see b1 but not a lot more of the b-series. This depends on the amount of peptide. I don't understand about the side-chains comment.

  • @axalnas15
    @axalnas15 8 ปีที่แล้ว +1

    this is really informative video, thank you so much, can we have the ppt version i want to study it as well

  • @FunTime-hd4zz
    @FunTime-hd4zz ปีที่แล้ว

    I have a questions I did all this, b ions I got sequence of RYAAYKYA
    and for y ions I have the sequence of IKAYKYAA
    I am not sure what's my final sequence going to be

    • @MatthewPadula
      @MatthewPadula  ปีที่แล้ว

      You did all of what? Is it a tryptic peptide? If so, it should end in K or R. You should probably email me with more detailed info.

    • @FunTime-hd4zz
      @FunTime-hd4zz ปีที่แล้ว

      @@MatthewPadula Hi, Please i urgently need help, where do i find your email?

    • @FunTime-hd4zz
      @FunTime-hd4zz ปีที่แล้ว

      Its fine found it, I am going to send you an email right now thanks a lot!!!

    • @MatthewPadula
      @MatthewPadula  ปีที่แล้ว

      @@FunTime-hd4zz searching my name and "UTS" in Google is a good start.

    • @FunTime-hd4zz
      @FunTime-hd4zz ปีที่แล้ว

      Really appreciate it, I have sent the email! 🙂