Cell cycle analysis by flow cytometry
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- เผยแพร่เมื่อ 20 ก.ย. 2024
- This video provides an overall introduction to the use of flow cytometry for cell cycle analysis. Toward the end, I present a question intended to see what the viewers would expect to obtain when cells are treated with a specific inhibitor of cell cycle progression.
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Hello, dear Dr. Differently this video helpful THANK YOU
Thank you Doctor Rosas for your immense contribution to explaining flowcytometric analysis 👍
Firstly thank you so much for that lecture Dr. Rosas. I'm a Biology student from Turkey and I need Flow Cytometry Applications for a presentation for my Molecular Biology class and that was the best explanation on the Cell Cycle I could ever find. It really helped. Secondly I think the answer for the question is; G1-8.33%, S-25%, G2/M-41.66% and the Apoptosis is 25%. I hope that's correct. Thank you again.
Thank you Dr. Rosas, you make this matter very understandable. It is wonderful that you share your knowledge with us.
Thank you for very comprehensive explanation. Studying from Hiroshima here. Apoptotic 25%.. G2M 41.7% S phase 25%, G1 8.3%
This is the video I needed to see! Thank you Dr Rosas!
25%M, 16.67%G2, 25%S, No G1 and 33.33% apoptotic as per my calculation. Thank you for the wonderful lecture.
Send me an email to grosasacosta@me.com if you want me to let you know whether your answers were right on target. Thanks for your feedback, it is greatly appreciated!
Thank you very much! It was the only source that really helped me to understand how to read the data
thank you for your perfect explanation
I am from India. The video was extremely helpful to understand the basics since i come from a chemistry background.
Sir could you please post a video for the answer to the last question?
I think the answer to the question will be 25% in Pre-G1 (Apoptotic), 25% in S phase, and 50% in G2/M phases. Because, during the treatment time, the are two equivalent time-periods for the cell death. If the total cell cycle period lasts 24 hours, cells that have at least passed 18th hour and had only 6 hours left to finish the cell cycle will undergo apoptosis (which corresponds to quarter of all cells). Within 12 hours, all G1 phase cells will be at S or G2-M phases, which substitutes previous S phase cells and their remain as a quarter. Another quarter goes to G2-M phase coming from the G1 phase. Lastly, the remaining 25% will also be in G2-M phase (particularly in M phase) due to arrest which came from the 12-18th hours in the beginning of the experiment but did not die.
Complete and perfect explanation thank u sir.
Thank you dr Roase
The video is very helpful ❤
Wow, it's incredibly helpful 👍👏🙏 Thank you so much sir.
You are most welcome
you just saved my life
Ok, it is May 2, 2022... and so far, no one has provided a correct answer. If you are taking this course for credit during the spring of 2022, post your answer by tomorrow (May 3, 2022) and, if it is correct, I'll recognize you credit toward the final grade
6
Great teacher
Bilkent - Cell Biology II - salutes to Onur Hoca :)
Nice explanation sir
I think that the answer is: 25% apoptotic, 8.3% G1/G0, 25% S, and 41.7% G2/M
very good!
1/12 @ G1 3/12 @ apoptosis 5/12 @g2/m 3/12 @s phase
I think the answer for las problem would be that 33% of cells would be on apoptosis, 42% on G2, 25% on S, and none on G1.
Close but that's not the right answer... the fraction in apoptosis would be lower and there would be some cells in G1
5:55 🎯
Maybe: 10% in G1 phase, 25% in S phase, 40% in G2/M phase, 25% Apoptotic
Pretty close but not perfect…
is possible make this cell cycle in algaes from corals symbiodinium??
Nice
Answer for the last question: 25% S phase, 25% apoptosis, 42% G2/M phase and 8% G1 phase.
This is the closest answer so far. I guess you probably decided to use only integers- but there is no rule that requires that. Decimals are needed to have full accuracy…send me an email and indicate “BIOL3314 - Cell Cycle” in the subject line. In the email provide the answer using decimals (when/if needed)
Might I ask why 8% in G1 phase?
how would you know if the cells have gone into G0 rather than apoptosis?
Cells in G0 will have a "normal" DNA content (2n). Cells in apoptosis will have a "less than normal" DNA content, as during apoptosis the DNA is fragmented (activation of cellular DNases) and a substantial part of it is lost within apoptotic vesicles.
@ Thank you
0% G1 phase; 25% S phase; 50% G2/M phase; 25% Apoptotic
Close but that's not the right answer... there would still be some cells in G1, and the fraction of cells in G2/M would be slightly lower